Al and I talked about the final together. we each took about 1 hour 20 min to complete it. Here are my comments, including stuff Al and I talked about: 1. third question: I guess our graph is connected, yes? I admit I don't know how to solve this one, though. 9th question: what's the answer? I can think of a surjection from [0,1] to [0,1]^2 (alternate digits: .2414256... maps to (.2126...,.445...) so it seems plausible to me that a surjection from R to R^2 exists (since there's a bijective map from [0,1] to R). Am I mistaken, or are the students supposed to have a similar line of reasoning? final question: Are we trying to make this one this easy? it seems obviously false to me. or did we want to say, n!=2^{f(n)} 2. we haven't done many examples like this... actually, I think the only example we did this term showed up in the quiz review. is a=32 the minimal $a$ we want? 3d. people throw dice, not flip them (sorry to be picky) 4b. technically, it's not the LHS and RHS of the identity that are the number of ways... we need to multiply by $r$ on both sides first, and we should change either the equation in 4a or the problem statement in 4b to reflect that. 6. there's a fair amount of computation involved here. it'll make things easier on the students (and us as graders) if we tell them 8!=40320. 7. it'll be easier to grade this question for partial credit if we name the events, e.g., H is the event of having high blood pressure, and P is the event of testing positive 9. Al and I don't understand what this problem is asking. If a try is a "sequence of pulled balls," how does a try "consist of one or two consecutive balls"? (We haven't been able to solve the three parts of the problem, either.) 10. the method of repeated diagnoses will only work if we assume some level of independence of diagnoses. 12b. Al notes that 12b yields a tighter bound than part a. it's strange but okay. **oops** we used the var/(var+x^2) formula but forgot to square x. 12c. if we're going to use standard dev on a problem, we should include the formula standard dev=\sqrt{variance}.