From kylee@MIT.EDU  Tue Feb 24 15:12:30 1998
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To: 6042-sec5@theory.lcs.mit.edu, 6042-sec6@theory.lcs.mit.edu
Subject: Mailing list created
Date: Tue, 24 Feb 1998 20:12:30 EST
From: Edmond Kayi Lee          <kylee@MIT.EDU>

Hi all,
 
        This is a mail sent to the mailing list for 6.042 students
in section 5 and section 6. If you receive this mail, that means 
you are in the mailing list.
 
        The list names for section 5 and section 6 are 
6042-sec5@theory.lcs.mit.edu and 6042-sec6@theory.lcs.mit.edu
respectively.
 
        Please feel free to send mail to the list for questions,
comments concerning the recitation. Also, I will make section 
announcements via this mailing list.
 
Thanks,
Edmond

From kylee@MIT.EDU  Wed Feb 25 12:23:21 1998
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To: 6042-sec5@theory.lcs.mit.edu, 6042-sec6@theory.lcs.mit.edu
Subject: Problem Set 4 question 1
Date: Wed, 25 Feb 1998 17:23:21 EST
From: Edmond Kayi Lee          <kylee@MIT.EDU>

Hi,

	In problem set 4 question 1, it is asking the Robot problem
similar to the one given in the lecture. However, pay attention that
the robot is moving a distance of 1 unit for each time. Therefore, the
solution is not as trivial as it looks. 

	For example, if it goes in the 45 degree direction at the 
first step, then it will end up in the coordinate (sqrt(2)/2, sqrt(2)/2), 
instead of (1,1) as in the lecture. To prove "yes", give the path that the
robot can reach the point. To prove "no", design and prove an invariant
such that the state (1,1) does not satisfy the invariant.

Good luck,
Edmond

From kylee@MIT.EDU  Sat Feb 28 18:43:12 1998
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To: Dmitry Brant <dbrant@MIT.EDU>
Cc: 6042-sec5@theory.lcs.mit.edu, 6042-sec6@theory.lcs.mit.edu
Subject: Re: 6.042 ps4 question 
In-Reply-To: Your message of "Sat, 28 Feb 1998 16:05:24 EST."
             <199802282105.QAA24010@w20-575-45.MIT.EDU> 
Date: Sat, 28 Feb 1998 23:43:12 EST
From: Edmond Kayi Lee          <kylee@MIT.EDU>

>I have a question about question 4e on the pset. When they say "every stable mar
>riage set leaves two bachelors of each sex" do they mean 2 bachelors are women +
> 2 bachelors are male? If so, then does the hint suggest the situation when the 
>marriage
>set is empty? is that valid?
> 

Yes, what you said is right. Here it is talking about every stable marriage 
set has to leave 2 men unmarried, and also 2 women. In the case involving 
2 men and 2 women, this reduces to the case where the only stable marriage
is "no marriage" at all, which is a stable marriage by definition. Thus,
you have to think of a situation (an acceptance list) where there cannot
be any non-trivial stable marriage. 

Hope this helps.

-Edmond

From kylee@mit.edu  Wed Mar 11 12:46:25 1998
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To: 6042-sec5@theory.lcs.mit.edu, 6042-sec6@theory.lcs.mit.edu
Subject: Quiz next week
Date: Wed, 11 Mar 1998 17:46:25 EST
From: Edmond Kayi Lee          <kylee@mit.edu>

Hi,

	Just a reminder that the mid-term quiz is next Wednesday. The questions
in the quiz will cover materials up to lecture yesterday. I'll give a brief
summary of topics here:

	- Propositional Logic
	- Basic proof technique: direct proof, proof by contradiction,
				 proof by cases
	- (strong) Induction (on mathematical equations, graphs or any 
			      other mathematical objects)
	- Well Ordering Principle
	- Graph Theory: definition, coloring, isomorphism
			(you should also be familiar with definition of 
			 terms such as tree, path, connected component,
			 cycle/circuit, adjacency matrix, DAG, etc)
	- State Machines: Design and Proof of Invariants, Derived 
			  Variables and Termination.
	- Sum and series: perturbation method, differentiation method,
			  integration method for closed forms or bounds.
			  Also the "guess" method by solving for the 
			  coefficients of speculated closed form and 
			  verification by induction.
	- Asymptotic Notation: Definition of big-O, Theta, big-Omega notation.
			       Comparison between functions.
	- Divide and Conquer Recurrence: Deriving Recurrence, 
			     Plug-and-Chuck(Iteration), Master Theorem

Also, you should be able to read definitions of new stuff and do proofs 
according to the definition.

If you find yourself comfortable with all these topics, you are in good 
shape. If not, be sure to go over it again and ask me about any confusion.

Also, the section this Friday will be a bit short. I am expecting to have
some time left (hopefully 20-30 minutes) to answer your questions. So if
you have any questions about any topics covered so far, be prepared to ask.

Last reminder, the topic Divide and Conquer Recurrence is not covered in 
any problem sets due before the quiz. You may want to do some practice 
exercise on that. Please look at the practice quiz we are going to give 
out soon.


Sorry for the long message. Wish you all do well next week.



Edmond

From kylee@mit.edu  Fri Mar 13 17:09:32 1998
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To: 6042-sec5@theory.lcs.mit.edu, 6042-sec6@theory.lcs.mit.edu
Subject: About Recurrence
Date: Fri, 13 Mar 1998 22:09:32 EST
From: Edmond Kayi Lee          <kylee@mit.edu>

Some of you have asked me about where to get the materials for recurrences,
and I would say the first place you should check if the recitation note 6
on the web. It states the Master Theorem, a corollary, some examples and 
the Change of variable we went over today. There is also a proof of the 
Theorem for those who are interested. So I guess it contains the basic 
information that you need to know about the topic.

The lecture note last year (lecture 10) is also a good reference for the 
topic. It talks about how to find and solve a recurrence using plug and 
chuck, and also verifying it using induction. The Towers of Hanoi example
is not mentioned in the lecture, but it is an interesting example for you
to learn how to find a recurrence. Note that section 4, the Akra-Bazzi 
Method is not covered this year. 

Last but not least, to get yourself familiar with the recurrence problems,
you have to practice more. The practice problem set has some questions on 
recurrence. If you think you need more, I would recommend you to check 
out old 6.042 webpages before Fall 97. The Divide-and-Conquer recurrence 
questions in those terms will not include Akra-Bazzi and fit the topic 
for this year.

Work hard and good luck on the exam.


Edmond

From kylee@mit.edu  Mon Mar 16 18:11:35 1998
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To: 6042-sec5@theory.lcs.mit.edu, 6042-sec6@theory.lcs.mit.edu
Subject: Problem set 5 graded
Date: Mon, 16 Mar 1998 23:11:35 EST
From: Edmond Kayi Lee          <kylee@mit.edu>

Hi,

	Problem set 5 is graded. I will bring those and all the unclaimed 
problem sets to the lecture tomorrow so that you can pick up.

	For those who still wants to read more about Master Theorem, you 
can refer to the book Introduction to Algorithms by Borman, Rivest and 
Leiserson. There are 3 pages (p.61-64) explaining how to understand and
use the theorem. This is the book for the course 6.046, so your neighbour
may have it.

	Reminder: office hour tomorrow 4-10 in 24-115.


Edmond

From kylee@mit.edu  Fri Mar 20 12:06:17 1998
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To: 6042-sec5@theory.lcs.mit.edu, 6042-sec6@theory.lcs.mit.edu
Subject: Quiz 1
Date: Fri, 20 Mar 1998 17:06:17 EST
From: Edmond Kayi Lee          <kylee@mit.edu>

Alrite quiz 1 is graded and handed back, and I see a lot of students 
having trouble in problem 1. I know it's too late for the quiz, but
I would like to suggest a general way on how to find the falsity in
the proof. This should be something that is useful for you.

	
1. Agree that the proof is faulty, and find a counterexample (better 
   a simple one). 

2. Verify the faulty proof LINE BY LINE with your counterexample. And
   find the transition of lines where it turns false for your counter-
   example. Since it is a false proof, there must be such a transition.
   This is the place where the proof goes wrong.

3. Think about the transition and get a sense of why that is false. Then
   make a comment and explanation on that. 



That is all what you should do. It should work for most of the cases,
even though I can't guarantee it works for all false proofs.

I hope that helps. Have a nice break.



Edmond

From kylee@mit.edu  Thu Mar 26 09:06:08 1998
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To: 6042-sec5@theory.lcs.mit.edu, 6042-sec6@theory.lcs.mit.edu
Subject: PS6 Problem 1
Date: Thu, 26 Mar 1998 14:06:08 EST
From: Edmond Kayi Lee          <kylee@mit.edu>

Hi,

	When you are doing problem 1 in problem set 6, be sure your argument
goes rigorously. It is a standard pigeon-hole type question. So if you use
pigeon hole principle to prove, be sure to write down what is pigeon, what
is hole, and why the pigeon-hole principle can make you prove the desired
statement.

	Maybe some of you will write down something like: "The only way
to place 32 checkers is to place them alternatively (or place them in
squares with the same color). And if you try to put the 33rd checker, there
is no way for you to do that." This is a true assertion and right intuition, 
but this is NOT a rigorous proof, becuase you haven't proved why all others 
ways to put the checkers do not work. (If your proof really cover all the 
possible cases, that's fine. But I am sure you don't want to do this since 
there are so many possible ways of placing checkers to consider.) 

	In conclusion, I have reminded you not to write down the "intuitive"
argument above. You'd better find another way to prove the result rigorously.


Edmond

From kylee@MIT.EDU  Mon May  4 12:10:22 1998
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To: 6042-sec6@theory.lcs.mit.edu
Cc: 6042-sec5@theory.lcs.mit.edu
Subject: A bad mistake in recitation
Date: Mon, 04 May 1998 16:10:22 EDT
From: Edmond Kayi Lee          <kylee@MIT.EDU>

Hi all,
 
        In the recitation Friday (Sec 6) I mentioned two Random Variables 
X,Y are independent iff Ex(X*Y)=Ex(X)*Ex(Y). I checked that at home and 
I found that this is not true. 
 
        This is true only for one direction: if X, Y are independent, then
Ex(X*Y)=Ex(X)*Ex(Y).
 
        But the other direction is not true: even if X,Y depend on each other,
Ex(X*Y)=Ex(X)*Ex(Y) MAY still hold. For example, 
 
        Let (A,B) be (1,1),(1,-1),(-1,2),(-1,-2) each w/prob 1/4. 
        So P(A=1)=P(A=-1)=1/2
        P(B = 1) = P(B = -1) = P(B = 2) = P(B = -2) = 1/4 
 
        We have E(B)=0, E(A)=0, and E(AB)=0
 
        However, A and B are dependent since P(A=1|B=1)=1 but P(A=1)=1/2.
 
        So in conclusion:
 
        - independence of random variables is defined as 
          P(A=i and B=j) = P(A=i)P(B=j) for all i,j. 
          To show independence, you show the random variables have the
          above property.
 
        - If A and B are independent, then Ex(AB)=Ex(A)Ex(B), but the
          converse is not true.
 
        I am sorry about the mistake. I made that mistake, so I hope you
won't follow me.
 
Edmond

From kylee@mit.edu  Thu May 14 07:14:23 1998
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To: 6042-sec5@theory.lcs.mit.edu, 6042-sec6@theory.lcs.mit.edu
Subject: Office Hours
Date: Thu, 14 May 1998 11:14:23 EDT
From: Edmond Kayi Lee          <kylee@mit.edu>

Hi,

	I am planning to hold office hours this week and next week
in order to help you prepare for the final. My tentative time will
be 3-5 this Friday, next Monday and Thursday. If you have trouble with 
any problems or topics, they are the good times for you to make it
clear. 

	The place will be 3rd Student Center in Lobdell. (Sorry I 
don't have an office. Lobdell is a decent place for study in 
non-meal times though.) 

	If the time doesn't work out for you. You are welcome to 
schedule another time with me.

	Have fun studying.


Edmond

