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Summary-line: 26-Feb                jee@MIT.EDU  [15] #Testing...1..2..3...
Mail-from: From jee@MIT.EDU  Thu Feb 26 11:37:36 1998
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Date: Thu, 26 Feb 1998 16:37:36 -0500
From: Roshan Gupta <jee@MIT.EDU>
Organization: Massachusetts Institute of Technology
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*** EOOH ***
Sender: jee@MIT.EDU
Date: Thu, 26 Feb 1998 16:37:36 -0500
From: Roshan Gupta <jee@MIT.EDU>
Organization: Massachusetts Institute of Technology
X-Mailer: Mozilla 4.04 [en] (X11; I; SunOS 5.5.1 sun4m)
To: 6042-help@theory.lcs.mit.edu
Subject: Testing...1..2..3...

Here is a quick question:  how do you prove that a rational number times
and irrational number is irrational?  My first instinct is to use a
proof by contradiction, that is to prove that a ratoinal times an
irrational number is rational.  Unfortunately, I can't seem to figure
that one out either.  Thanks.



1,,
Summary-line: 26-Feb            to: jee@MIT.EDU  [30] #Re: Testing...1..2..3...
Mail-from: From meyer@theory.lcs.mit.edu  Thu Feb 26 11:55:08 1998
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Date: Thu, 26 Feb 98 16:55:08 EST
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From: "Albert R. Meyer" <meyer@theory.lcs.mit.edu>
To: jee@MIT.EDU
Cc: 6042-help@theory.lcs.mit.edu
In-Reply-To: <34F5E09E.3C980F6D@MIT.EDU> (message from Roshan Gupta on Thu, 26
	Feb 1998 16:37:36 -0500)
Subject: Re: Testing...1..2..3...
Reply-To: 6042-meyer@theory.lcs.mit.edu

*** EOOH ***
Date: Thu, 26 Feb 98 16:55:08 EST
From: "Albert R. Meyer" <meyer@theory.lcs.mit.edu>
To: jee@MIT.EDU
Cc: 6042-help@theory.lcs.mit.edu
In-Reply-To: <34F5E09E.3C980F6D@MIT.EDU> (message from Roshan Gupta on Thu, 26
	Feb 1998 16:37:36 -0500)
Subject: Re: Testing...1..2..3...
Reply-To: 6042-meyer@theory.lcs.mit.edu

   Sender: jee@MIT.EDU
   Date: Thu, 26 Feb 1998 16:37:36 -0500
   From: Roshan Gupta <jee@MIT.EDU>
   Organization: Massachusetts Institute of Technology
   X-Mailer: Mozilla 4.04 [en] (X11; I; SunOS 5.5.1 sun4m)

   Here is a quick question:  how do you prove that a rational number times
   and irrational number is irrational?  My first instinct is to use a
   proof by contradiction, that is to prove that a ratoinal times an
   irrational number is rational.  Unfortunately, I can't seem to figure
   that one out either.  Thanks.

Yes, suppose for contradiction that

(n/m)x = k/l

where n,m,k,l are nonnegative integers and x is a real number.  Now prove
that x is rational.

Regards, A.


1,,
Summary-line: 26-Feb    luca@theory.lcs.mit.edu  [39] #Re: Testing...1..2..3...
Mail-from: From luca@theory.lcs.mit.edu  Thu Feb 26 11:51:55 1998
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Date: Thu, 26 Feb 1998 16:51:55 -0500
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To: Roshan Gupta <jee@MIT.EDU>
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Subject: Re: Testing...1..2..3...
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*** EOOH ***
Sender: luca@theory.lcs.mit.edu
Date: Thu, 26 Feb 1998 16:51:55 -0500
From: Luca Trevisan <luca@theory.lcs.mit.edu>
X-Mailer: Mozilla 3.01Gold (X11; I; SunOS 4.1.4 sun4m)
To: Roshan Gupta <jee@MIT.EDU>
Cc: 6042-help@theory.lcs.mit.edu
Subject: Re: Testing...1..2..3...
References: <34F5E09E.3C980F6D@MIT.EDU>

Roshan Gupta wrote:
> 
> Here is a quick question:  how do you prove that a rational number times
> and irrational number is irrational?  My first instinct is to use a
> proof by contradiction, that is to prove that a ratoinal times an
> irrational number is rational.  Unfortunately, I can't seem to figure
> that one out either.  Thanks.



the proof by contradiction goes this way (you use
the fact that a rational number divided by a non-zero rational number
is rational):

assume by contradiction that r is a non-zero rational, x is irrational,
and r times x is rational. let r' = rx. then you have

 x = r'/r

which is well-defined since r is non-zero. 
now, r'/r is rational, so x is rational and you reach a contradiction.
QED

observe that you have to assume that r is non-zero, since
zero (that is rational) times an irrational number gives zero
(rational).

Best
--Luca


1,,
Summary-line: 26-Feb        to: flattop@MIT.EDU  [32] #Re: ps#4
Mail-from: From meyer@theory.lcs.mit.edu  Thu Feb 26 12:10:26 1998
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Date: Thu, 26 Feb 98 17:10:26 EST
Message-Id: <199802262210.AA15736@stork.lcs.mit.edu>
From: "Albert R. Meyer" <meyer@theory.lcs.mit.edu>
To: flattop@MIT.EDU
In-Reply-To: <34F48CD6.392D@MIT.EDU> (flattop@MIT.EDU)
Subject: Re: ps#4
Cc: 6042-help

*** EOOH ***
Date: Thu, 26 Feb 98 17:10:26 EST
From: "Albert R. Meyer" <meyer@theory.lcs.mit.edu>
To: flattop@MIT.EDU
In-Reply-To: <34F48CD6.392D@MIT.EDU> (flattop@MIT.EDU)
Subject: Re: ps#4
Cc: 6042-help

Your offer of office hours is a nice one.  You can announce it by emailing
to 6042-students@theory.lcs.mit.edu.  Also, put announcement on the web
page under "News and Reminders".

Regards, A.

   Sender: flattop@MIT.EDU
   Date: Wed, 25 Feb 1998 16:27:50 -0500
   From: "Jack V. Chung" <flattop@MIT.EDU>
   X-Mailer: Mozilla 3.01 (X11; U; SunOS 5.5.1 sun4m)

   Prof. Meyer,

   I'm thinking about having myself available in the Student Center Sunday
   night and Monday night to help people with ps#4.  I'll e-mail out the
   other helpers if they want to join me.  Is there a mailing list for all
   of the 6.042 students?  I'll probably tell them the time and place
   Friday.

   What do you think of this?
   When will the solutions be available?

   jack



1,,
Summary-line: 26-Feb              to: 6042-help  [49] #[jee@MIT.EDU: Re: Testing...1..2..3...]
Mail-from: From meyer@theory.lcs.mit.edu  Thu Feb 26 12:17:18 1998
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From: "Albert R. Meyer" <meyer@theory.lcs.mit.edu>
To: 6042-help
Subject: [jee@MIT.EDU: Re: Testing...1..2..3...]

*** EOOH ***
Date: Thu, 26 Feb 98 17:17:18 EST
From: "Albert R. Meyer" <meyer@theory.lcs.mit.edu>
To: 6042-help
Subject: [jee@MIT.EDU: Re: Testing...1..2..3...]

------- Start of forwarded message -------
To: 6042-meyer@theory.lcs.mit.edu
Subject: Re: Testing...1..2..3... 
In-Reply-To: Your message of "Thu, 26 Feb 1998 16:55:08 EST."
             <199802262155.AA15662@stork.lcs.mit.edu> 
Date: Thu, 26 Feb 1998 17:14:22 EST
From: Roshan Gupta <jee@MIT.EDU>


Thanks, I get it.  x = (k/l) * (n/m) = (k*l)/(l*n) which is rational.
X is defined as irrational, so that's the contradiction.

Thanks again for the (really) fast reply.  I have another quick question...how do you do problem 3 on the problem set?  Sorry, I thought I would try.



Roshan Gupta




- ----------------------------------------------------------------------------
   Sender: jee@MIT.EDU
   Date: Thu, 26 Feb 1998 16:37:36 -0500
   From: Roshan Gupta <jee@MIT.EDU>
   Organization: Massachusetts Institute of Technology
   X-Mailer: Mozilla 4.04 [en] (X11; I; SunOS 5.5.1 sun4m)
 
   Here is a quick question:  how do you prove that a rational number times
   and irrational number is irrational?  My first instinct is to use a
   proof by contradiction, that is to prove that a ratoinal times an
   irrational number is rational.  Unfortunately, I can't seem to figure
   that one out either.  Thanks.
 
Yes, suppose for contradiction that
 
(n/m)x = k/l
 
where n,m,k,l are nonnegative integers and x is a real number.  Now prove
that x is rational.
 
Regards, A.
------- End of forwarded message -------


1,,
Summary-line: 28-Feb           seajaspe@MIT.EDU  [17] #Problem 2
Mail-from: From seajaspe@MIT.EDU  Sat Feb 28 03:54:07 1998
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Date: Sat, 28 Feb 1998 08:54:07 -0500
From: Sean Sutherland <seajaspe@MIT.EDU>
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*** EOOH ***
Date: Sat, 28 Feb 1998 08:54:07 -0500
From: Sean Sutherland <seajaspe@MIT.EDU>
X-Mailer: Mozilla 4.04 [en] (Win95; I)
To: 6042-help@theory.lcs.mit.edu
Subject: Problem 2

I have a question as regards to the receptacle. If in line 3 of the
problem you state that "the receptacle can be used to store an unlimited
amount of water" why is there a condition namely 2 which saids "pour
from the receptacle to a bucket until the bucket is full or the
receptacle is empty". That can't happen based on argument above. How do
I deal with this?

Sean
seajaspe@mit.edu



1,,
Summary-line: 28-Feb       to: seajaspe@MIT.EDU  [31] #Re: Problem 2
Mail-from: From meyer@theory.lcs.mit.edu  Sat Feb 28 07:34:10 1998
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Date: Sat, 28 Feb 98 12:34:10 EST
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From: "Albert R. Meyer" <meyer@theory.lcs.mit.edu>
To: seajaspe@MIT.EDU
Cc: 6042-help@theory.lcs.mit.edu
In-Reply-To: <34F816FF.7BF969A0@mit.edu> (message from Sean Sutherland on Sat,
	28 Feb 1998 08:54:07 -0500)
Subject: Re: Problem 2
Reply-To: 6042-meyer@theory.lcs.mit.edu

*** EOOH ***
Date: Sat, 28 Feb 98 12:34:10 EST
From: "Albert R. Meyer" <meyer@theory.lcs.mit.edu>
To: seajaspe@MIT.EDU
Cc: 6042-help@theory.lcs.mit.edu
In-Reply-To: <34F816FF.7BF969A0@mit.edu> (message from Sean Sutherland on Sat,
	28 Feb 1998 08:54:07 -0500)
Subject: Re: Problem 2
Reply-To: 6042-meyer@theory.lcs.mit.edu

The receptable CAN hold a lot of water, but at any given moment between
pourings, it might only be filled with a little bit -- or even be empty as
it is at the start.

Regards, A.

   Date: Sat, 28 Feb 1998 08:54:07 -0500
   From: Sean Sutherland <seajaspe@MIT.EDU>
   X-Mailer: Mozilla 4.04 [en] (Win95; I)

   I have a question as regards to the receptacle. If in line 3 of the
   problem you state that "the receptacle can be used to store an unlimited
   amount of water" why is there a condition namely 2 which saids "pour
   from the receptacle to a bucket until the bucket is full or the
   receptacle is empty". That can't happen based on argument above. How do
   I deal with this?

   Sean
   seajaspe@mit.edu




1,,
Summary-line: 28-Feb        to: flattop@MIT.EDU  [74] #ps4 solns
Mail-from: From meyer@theory.lcs.mit.edu  Sat Feb 28 17:29:00 1998
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From: "Albert R. Meyer" <meyer@theory.lcs.mit.edu>
To: flattop@MIT.EDU
Cc: 6042-help
In-Reply-To: <34F8C3F3.27E0@MIT.EDU> (flattop@MIT.EDU)
Subject: ps4 solns
Reply-To: 6042-meyer@theory.lcs.mit.edu

*** EOOH ***
Date: Sat, 28 Feb 98 22:29:00 EST
From: "Albert R. Meyer" <meyer@theory.lcs.mit.edu>
To: flattop@MIT.EDU
Cc: 6042-help
In-Reply-To: <34F8C3F3.27E0@MIT.EDU> (flattop@MIT.EDU)
Subject: ps4 solns
Reply-To: 6042-meyer@theory.lcs.mit.edu

I looked at Stas' incomplete ps4 draft solution.  Except for obvious minor
typos, solns to 1--3(a) are fine.

Soln to 3(b) doesn't yet have a proof that M(S) is decreasing, but that's
pretty clear by cases:
 if the new move is bounded, then by def it does not change xmin or ymin,
 and it decreases the number of bounded pts -- since the move itself was
 bounded and can't be reused.  If it's not bounded, then it decreases at
 least one of xmin and ymin.  Of course xmin and ymin can never increase.

Soln to 3(c):
 the first player starts with (1,1).  Then the second player, whatever he
 picks, say (0,n) for some n, the first player will respond with (n,0).  By
 symmetry, the first player will always have a move whenever the second
 player had a move, except when the second player picks (0,0) and loses.

 If the first player plays any other first move, the second player can win
 by choosing (1,1) -- except if the first player chooses (1,0) or (0,1), in
 which case (1,1) is disallowed, but the second wins by playing (0,1) or
 (1,0).

soln 4(a):
one soln is to arrange preferences so each woman is the first-choice of
exactly one man, and she is his first choice.  It's easy to see that when
a man and a woman have each other as first choice, they will be a rogue
couple unless they are married.

another soln is to have all the men rank the women in the same order, and
all the woman rank the men in the same order.  Then first-choice man must
marry first choice woman, after which 2nd choice man must marrry 2nd
choice woman, etc.

4(bcd) follow by exactly the reasoning in the notes for the case of an equal
number of men and women.

4(e) M1 accepts only W1, M2 accepts only W2, W1 accepts only M2, W2
accepts only M1.  No mutually acceptable marriage is possible.

4(f) I'll leave this for Stas to explain.

4(g) We're looking for a brief statement, not a long proof.  The brief
statement is that, "Exactly the same reasoning which worked for the
morning-afternoon-evening protocol applies to show that the one-at-a-time
protocol yields a stable marriage set with bachelors of only of the excess
sex.  Moreover, exactly the reasoning in the notes which shows that the
morning-afternoon-evening protocol yields the unique man-optimal matching,
also applies to the one-at-a-time protocol, so it yields this same
matching."

BTW, there's another argument for uniqueness of the one-at-a-time matching
which doesn't appeal to man-optimality, but is based on the claim that the
order in which simultaneously possible crossings-out are performed doesn't
matter.  The argument uses the

Lemma: If at some point, woman W1 can tell man M1 to cross her off his
list, and at the same time woman W2 can tell man M2 to cross her off, then
if either of these is the crossout which occurs, it will still be possible
to do the other one next.

I doubt that anyone will come up with this argument, so I won't finish
spelling it out, but if you see anyone with reasoning along the line of
this lemma, don't assume they're off the track.

Regards, A.



1,,
Summary-line:  1-Mar              cstan@MIT.EDU  [15] #Problem Set 4
Mail-from: From cstan@MIT.EDU  Sun Mar  1 11:42:11 1998
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Message-Id: <34F9D633.76C5@mit.edu>
Date: Sun, 01 Mar 1998 16:42:11 -0500
From: ChoonsiangTan <cstan@MIT.EDU>
Reply-To: cstan@MIT.EDU
Organization: MIT
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*** EOOH ***
Date: Sun, 01 Mar 1998 16:42:11 -0500
From: ChoonsiangTan <cstan@MIT.EDU>
Reply-To: cstan@MIT.EDU
Organization: MIT
X-Mailer: Mozilla 3.01 (Win95; I)
To: 6042-help@theory.lcs.mit.edu
Subject: Problem Set 4

Hi,

What is question 3 (a) asking when it asks us to prove that the subset
has a least element?

Choonsiang


1,,
Summary-line:  1-Mar             stasio@MIT.EDU  [12] #Re: Problem Set 4
Mail-from: From stasio@mit.edu  Sun Mar  1 11:49:01 1998
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Date: Sun, 1 Mar 1998 16:49:01 -0500 (EST)
Message-Id: <199803012149.QAA12353@enigma.LCS.MIT.EDU>
From: Stanislaw Jarecki <stasio@MIT.EDU>
To: cstan@MIT.EDU
Cc: 6042-help@theory.lcs.mit.edu
In-Reply-To: <34F9D633.76C5@mit.edu> (message from ChoonsiangTan on Sun, 01
	Mar 1998 16:42:11 -0500)
Subject: Re: Problem Set 4

*** EOOH ***
Date: Sun, 1 Mar 1998 16:49:01 -0500 (EST)
From: Stanislaw Jarecki <stasio@MIT.EDU>
To: cstan@MIT.EDU
Cc: 6042-help@theory.lcs.mit.edu
In-Reply-To: <34F9D633.76C5@mit.edu> (message from ChoonsiangTan on Sun, 01
	Mar 1998 16:42:11 -0500)
Subject: Re: Problem Set 4


the question asks you if a subset has a least element *in this
ordering*.  Not every ordering of a set has this property.


1,,
Summary-line:  1-Mar            asomani@MIT.EDU  [17] #
Mail-from: From asomani@MIT.EDU  Sun Mar  1 18:45:59 1998
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To: 6042-help@theory.lcs.mit.edu
From: Ashutosh Somani <asomani@MIT.EDU>
Subject: 

*** EOOH ***
Date: Sun, 1 Mar 98 23:45:59 EST
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To: 6042-help@theory.lcs.mit.edu
From: Ashutosh Somani <asomani@MIT.EDU>
Subject: 

I had a question regarding problem 4 parts e and f. What does it mean by
"suppose that no person is unacceptable to more than one person of the
opposite sex."  How could a person be unacceptable anyone...in the protocol
you ONLY rank people who are acceptable right?

Thanks.
Ashutosh Somani
asomani@mit.edu



0, unseen,,
Summary-line:  1-Mar            flattop@MIT.EDU  [38] #Re: 
*** EOOH ***
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To: Ashutosh Somani <asomani@MIT.EDU>
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I had a question regarding problem 4 parts e and f. What does it mean by
"suppose that no person is unacceptable to more than one person of the
opposite sex."  How could a person be unacceptable anyone...in the
protocol
you ONLY rank people who are acceptable right?

Thanks.
Ashutosh Somani
asomani@mit.edu

---------------------------------------------

That's what it means,  To be unacceptable is not to be ranked.
So in other words, let say there are n people in the opposite sex, at
least n-1 of them must rank you.  

jack


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Summary-line:  2-Mar                mli@MIT.EDU  [29] #6.042 PS4, #2
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To: 6042-help@theory.lcs.mit.edu
Subject: 6.042 PS4, #2
Date: Mon, 02 Mar 1998 13:20:51 EST
From: Michael W Li <mli@MIT.EDU>


Hi,

for problem 2, what is the purpose of the drain?
in something like move #5 where it says: pour from A to B until either
A is empty of B is full, whichever happens first,
is this to say that if B becomes full, the excess water in 
A is thrown down the drain? or does it stay in A?

so if A is filled with water capacity a, and B is empty,
and A is poured into B, and we assume that a > b, when 
B becomes full, is there a-b left over in bucket A?
or does that go down the drain?

mike


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Summary-line:  2-Mar             stasio@mit.edu  [23] #ps4 solutions
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Date: Mon, 2 Mar 1998 13:22:40 -0500 (EST)
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From: Stanislaw Jarecki <stasio@mit.edu>
To: 6042-help@theory.lcs.mit.edu
Subject: ps4 solutions


Hey helpers,
i put the new ps4 solutions on our staffonly:

1.  They dont have 4g
2.  The 4f is done for the problem as I revised it
   (it is clear that the old statement was not true,
    but it is not clear whether we will cancel the problem
    or brodcast the fix.  but just in case: it's there)

stas


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Summary-line:  2-Mar             flints@MIT.EDU  [39] #PS#4 Q 4.e
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Date: Mon, 02 Mar 1998 15:42:24 -0500
From: Petra S Chong <flints@MIT.EDU>
Organization: Massachusetts Institute of Technology
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I do not understand this part of the question; I would like to clarify
what the exact situation described is.

1. Are we to show that every stable marriage set leaves two bachelors of
each sex, if there are arbitrary (non-equal) numbers of men and women? 

2. If we are, I don't know how to start; I've been looking at this all
weekend. The hint given says to find a situation involving exactly two
men and women; I took this to mean the situation where there were ONLY
two men and two women. In this case, I can find an arrangement where
there is NO marriage set; but I don't see how I can extend this to
arbitrary numbers of men and women. I can't find an invariant, and I
can't find a derived variable that seems to lead anywhere.


Thanks

petra


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Summary-line:  2-Mar         to: flints@MIT.EDU  [54] #Re: PS#4 Q 4.e
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From: "Albert R. Meyer" <meyer@theory.lcs.mit.edu>
To: flints@MIT.EDU
Cc: 6042-help@theory.lcs.mit.edu
In-Reply-To: <34FB19B0.571F@MIT.EDU> (message from Petra S Chong on Mon, 02
	Mar 1998 15:42:24 -0500)
Subject: Re: PS#4 Q 4.e
Reply-To: 6042-meyer@theory.lcs.mit.edu

It's OK to pick a "situation," that is, set of men and women and their
preferences, in which there are equal numbers of men and women.  You could
also pick a situation with unequal numbers.  You only have to pick one
situation.

If you do pick a situation w/2 men and 2 women as the hint suggests, the
stable marriage set will necessarily be empty, but that's allowed.

Regards, A.


   Sender: flints@MIT.EDU
   Date: Mon, 02 Mar 1998 15:42:24 -0500
   From: Petra S Chong <flints@MIT.EDU>
   Organization: Massachusetts Institute of Technology
   X-Mailer: Mozilla 3.01 (X11; U; SunOS 5.5.1 sun4m)
   Cc: flints@MIT.EDU

   I do not understand this part of the question; I would like to clarify
   what the exact situation described is.

   1. Are we to show that every stable marriage set leaves two bachelors of
   each sex, if there are arbitrary (non-equal) numbers of men and women? 

   2. If we are, I don't know how to start; I've been looking at this all
   weekend. The hint given says to find a situation involving exactly two
   men and women; I took this to mean the situation where there were ONLY
   two men and two women. In this case, I can find an arrangement where
   there is NO marriage set; but I don't see how I can extend this to
   arbitrary numbers of men and women. I can't find an invariant, and I
   can't find a derived variable that seems to lead anywhere.


   Thanks

   petra



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Summary-line:  2-Mar            flattop@MIT.EDU  [58] #Re: 6.042 PS4, #2
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I'm not sure if anyone answered your question:

Purpose of the drain is to empty either Bucket A or B.
In move 5:
	you have the option of keeping the excess water in A or 
	pour it in the drain.
you cannot assume a>b.
	If A is filled with capacity a, and B is empty.
	If you pour A into B:
		if a>b --> A will have excess water, B will be full
		if a<b --> A will be empty, B will be partially full
		if a=b, then A is empty, B is full
	You can do whatever you want with the excess water:
		keep it or pour in drain.

Hope this helps

jack



Michael W Li wrote:
> 
> Hi,
> 
> for problem 2, what is the purpose of the drain?
> in something like move #5 where it says: pour from A to B until either
> A is empty of B is full, whichever happens first,
> is this to say that if B becomes full, the excess water in
> A is thrown down the drain? or does it stay in A?
> 
> so if A is filled with water capacity a, and B is empty,
> and A is poured into B, and we assume that a > b, when
> B becomes full, is there a-b left over in bucket A?
> or does that go down the drain?
> 
> mike


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Summary-line:  2-Mar              to: 6042-help  [52] #[meyer@theory.lcs.mit.edu: Re: 6.042  pset4, prob3b: correction to example]
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From: "Albert R. Meyer" <meyer@theory.lcs.mit.edu>
To: 6042-help
Subject: [meyer@theory.lcs.mit.edu: Re: 6.042  pset4, prob3b: correction to example]

FYI:

------- Start of forwarded message -------
Date: Mon, 2 Mar 1998 16:20:34 -0500
From: "Albert R. Meyer" <meyer@theory.lcs.mit.edu>
To: low@MIT.EDU
In-reply-to: <2.2.32.19980302192938.006e183c@po7.mit.edu> (message from Low
	Tzer Hung on Mon, 02 Mar 1998 14:29:38 -0500)
Subject: Re: 6.042  pset4, prob3b: correction to example
reply-to: 6042-meyer

In addition to 5. & 6., prob 2(c) won't let you use 2. or 3. either.

Regards, A. 

   X-Sender: low@po7.mit.edu (Unverified)
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   Date: Mon, 02 Mar 1998 14:29:38 -0500
   From: Low Tzer Hung <low@MIT.EDU>

   Is there a mistake in question 2, since I can do 2b) without  using 5 and 6.
   This makes 2c) trivial.

   thanks

   Low Tzer Hung


   At 05:44 PM 3/1/98 EST, you wrote:
   >In the example given in PSet4, Prob 3b: the set of bounded moves
   >should be
   >     {(1,1),(1,2),(2,1), (0,3), (0,2),(0,1),(0,0),(1,0),(2,0),(3,0)}.
   >(The last 7 points above, with a 0 coordinate, were omitted in the
   >original handout.)  And the unbounded moves in the example are the points
   >with at least one zero-coordinate, except the 7 above.
   >
   >Regards, A.
   >
------- End of forwarded message -------


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Summary-line:  2-Mar         to: flints@MIT.EDU  [41] #Re: PS#4 Q 4.e
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From: "Albert R. Meyer" <meyer@theory.lcs.mit.edu>
To: flints@MIT.EDU
In-Reply-To: <199803022156.QAA27999@quickstation-50-1.MIT.EDU> (message from
	Petra Chong on Mon, 02 Mar 1998 16:56:46 EST)
Subject: Re: PS#4 Q 4.e
Cc: 6042-help
Reply-To: 6042-meyer@theory.lcs.mit.edu

It could be that one woman finds NO man acceptable, but all the other
woman accepted all the other men.  This still satisfies the condition that
each man is unacceptable to at most one woman.

Regards, A.

   Date: Mon, 02 Mar 1998 16:56:46 EST
   From: Petra Chong <flints@MIT.EDU>

   I have another question; this time about question 4 part f. I have
   taken note of the correction in the question. 

   I would like to clarify one specification:

   If N is the number of men and women:

   Is the situation such that each man likes ONLY N-1 women, and every
   women likes ONLY N - 1 men?

   thanks

   petra




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Summary-line:  2-Mar            mphil14@MIT.EDU  [31] #PS #4
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To: 6042-help@theory.lcs.mit.edu
Subject: PS #4
Date: Mon, 02 Mar 1998 21:11:06 EST
From: Mark Phillip <mphil14@MIT.EDU>

*** EOOH ***
To: 6042-help@theory.lcs.mit.edu
Subject: PS #4
Date: Mon, 02 Mar 1998 21:11:06 EST
From: Mark Phillip <mphil14@MIT.EDU>

Hi, I'm having problems with 2c and 4b.  For 4b, I totally understand the
protocol and the rest of question 4, but I don't exactly see how I can model
the states and the transitions.  For 2c I honestly don't even understand the
question.  Any help you could give me would be great.  THanks...-mark 



Mark Phillip
Phi Sigma Kappa
Boston MA, 02215


REEFPRODUCTIONS.mit.edu
web.mit.edu/mphil14/www


"near...far.....NEAR....FAR!!!"


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Summary-line:  2-Mar        to: mphil14@MIT.EDU  [50] #Re: PS #4
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From: "Albert R. Meyer" <meyer@theory.lcs.mit.edu>
To: mphil14@MIT.EDU
Cc: 6042-help@theory.lcs.mit.edu
In-Reply-To: <199803030211.VAA19228@no-knife.MIT.EDU> (message from Mark
	Phillip on Mon, 02 Mar 1998 21:11:06 EST)
Subject: Re: PS #4
Reply-To: 6042-meyer@theory.lcs.mit.edu

You should be able to answer 4b, if you understand how to model the protocol from
lecture as a state machine.  This was described in lecture and in the Handout 17
notes.  If you are still stuck after that, ask for more 6042-help.

For 2c, remember the 3cent 5cent postage problem?  You couldn't make up
ALL amounts of postage, only all amounts >= 8.  With stamps (or buckets)
9, 12 you can make up all amounts divisible by gcd(9,12)=3, provided the
amount is >= 18, but you can't make 3, 6, or 15.  The problem asks you to
show that this kind of thing is what always happens.

Regards, A. 

   Date: Mon, 02 Mar 1998 21:11:06 EST
   From: Mark Phillip <mphil14@MIT.EDU>

   Hi, I'm having problems with 2c and 4b.  For 4b, I totally understand the
   protocol and the rest of question 4, but I don't exactly see how I can model
   the states and the transitions.  For 2c I honestly don't even understand the
   question.  Any help you could give me would be great.  THanks...-mark 



   Mark Phillip
   Phi Sigma Kappa
   Boston MA, 02215


   REEFPRODUCTIONS.mit.edu
   web.mit.edu/mphil14/www


   "near...far.....NEAR....FAR!!!"



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Summary-line:  2-Mar             aileen@MIT.EDU  [38] #question 4
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Date: Mon, 02 Mar 1998 21:39:47 -0500
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From: Aileen Tang <aileen@MIT.EDU>
Subject: question 4
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Hi,

Question 4 defines the terminating condition as "the first afternoon when
every man who proposed to a woman that morning ends up engaged to her in
teh afternoon."

Is this any different from the terminating condition specified in lecture
when "no changes occur"?

Thanks,

Aileen @=)
_________________________________________________________________________

Aileen Tang '99                        MM      MM   IIIIIIII  TTTTTTTT  
Massachusetts Institute of Technology   MM    MM    ~~ II        TT 
320 Memorial Drive Rm 704               M M  M M    @@ II        TT 
Cambridge, MA 02139                     M  MM  M    C  II        TT
http://kwaibao.mit.edu/                MM  MM  MM    V IIIII     TT
_________________________________________________________________________


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Summary-line:  2-Mar                mli@MIT.EDU  [22] ##2b
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To: 6.042-help@theory.lcs.mit.edu
Subject: #2b
Date: Mon, 02 Mar 1998 21:59:40 EST
From: Michael W Li <mli@MIT.EDU>


can you explain Lemma 0.2 in Problem Set 4 solutions 97
problem #5?
I been staring for a while at it to get insight into problem #2
on the set but I don't understand where they get m and n.

thanks,
Mike Li


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Summary-line:  2-Mar         to: aileen@MIT.EDU  [48] #Re: question 4
*** EOOH ***
Mail-from: From meyer@theory.lcs.mit.edu  Mon Mar  2 18:09:05 1998
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From: "Albert R. Meyer" <meyer@theory.lcs.mit.edu>
To: aileen@MIT.EDU
Cc: 6042-help@theory.lcs.mit.edu
In-Reply-To: <3.0.1.32.19980302213947.0069a4a0@po7.mit.edu> (message from
	Aileen Tang on Mon, 02 Mar 1998 21:39:47 -0500)
Subject: Re: question 4
Reply-To: 6042-meyer@theory.lcs.mit.edu

They are indeed equivalent, but if you intend to use this fact, you should
prove it.

Regards, A.

   X-Sender: aileen@po7.mit.edu
   X-Mailer: Windows Eudora Pro Version 3.0.1 (32)
   Date: Mon, 02 Mar 1998 21:39:47 -0500
   From: Aileen Tang <aileen@MIT.EDU>

   Hi,

   Question 4 defines the terminating condition as "the first afternoon when
   every man who proposed to a woman that morning ends up engaged to her in
   teh afternoon."

   Is this any different from the terminating condition specified in lecture
   when "no changes occur"?

   Thanks,

   Aileen @=)
   _________________________________________________________________________

   Aileen Tang '99                        MM      MM   IIIIIIII  TTTTTTTT  
   Massachusetts Institute of Technology   MM    MM    ~~ II        TT 
   320 Memorial Drive Rm 704               M M  M M    @@ II        TT 
   Cambridge, MA 02139                     M  MM  M    C  II        TT
   http://kwaibao.mit.edu/                MM  MM  MM    V IIIII     TT
   _________________________________________________________________________



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Summary-line:  2-Mar            to: mli@MIT.EDU  [36] #Re: #2b
*** EOOH ***
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From: "Albert R. Meyer" <meyer@theory.lcs.mit.edu>
To: mli@MIT.EDU
In-Reply-To: <199803030259.VAA02454@mass-toolpike.MIT.EDU> (message from
	Michael W Li on Mon, 02 Mar 1998 21:59:40 EST)
Subject: Re: #2b
Cc: 6042-help
Reply-To: 6042-meyer@theory.lcs.mit.edu

Oh, you mean SPRING 97!  Yes, m and n are cleverly chosen, but there isn't
any need for you to know how someone figured them out.  Our pset 4, prob 2
can be solved directly from the fact that gcd(a,b) = xa+yb for some
integers x,y.

Regards, A. 

   Date: Mon, 02 Mar 1998 21:59:40 EST
   From: Michael W Li <mli@MIT.EDU>


   can you explain Lemma 0.2 in Problem Set 4 solutions 97
   problem #5?
   I been staring for a while at it to get insight into problem #2
   on the set but I don't understand where they get m and n.

   thanks,
   Mike Li



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Summary-line:  2-Mar             ahuang@MIT.EDU  [23] #Problem Set 4
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To: 6042-help@theory.lcs.mit.edu
From: Angus Huang <ahuang@MIT.EDU>
Subject: Problem Set 4

I was just wondering how we should go about proving Problem 2c
(what method sould we use). Thanks for your help.

Angus Huang



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Summary-line:  2-Mar         to: ahuang@MIT.EDU  [31] #Re: Problem Set 4
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From: "Albert R. Meyer" <meyer@theory.lcs.mit.edu>
To: ahuang@MIT.EDU
In-Reply-To: <9803030430.AA05671@MIT.MIT.EDU> (message from Angus Huang on
	Mon, 2 Mar 98 23:30:53 EST)
Subject: Re: Problem Set 4
Reply-To: 6042-meyer@theory.lcs.mit.edu
Cc: 6042-help

describe a procedure for increasing the amount of water in the receptacle
by gcd(a,b), providing there is enough water in the receptacle.

   Date: Mon, 2 Mar 98 23:30:53 EST
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   From: Angus Huang <ahuang@MIT.EDU>

   I was just wondering how we should go about proving Problem 2c
   (what method sould we use). Thanks for your help.

   Angus Huang




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Summary-line:  3-Mar  ez=40mit.edu=3E?=@MIT.EDU  [20] #
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Date: Tue, 03 Mar 1998 00:04:23 -0500
To: 6042-help@theory.lcs.mit.edu
From: =?iso-8859-1?Q?=22Javier_S._L=F3pez=22_=3Cjslopez=40mit.edu=3E?=@MIT.EDU
Subject: 

What the N^3 means?



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Summary-line:  3-Mar            flattop@MIT.EDU  [84] #Re: 
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To: "Javier S. Lspez @MIT.EDU" <jslopez@MIT.EDU>
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It means a triple (a, b, c)
N^2 is (a, b)
N is just a


"Javier S. Lspez" @MIT.EDU wrote:
> 
> What the N^3 means?

-- 
MIT Class of 2000
http://web.mit.edu/flattop/www/From meyer@theory.lcs.mit.edu  Fri Mar  6 01:11:14 1998
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From: "Albert R. Meyer" <meyer@theory.lcs.mit.edu>
To: gtewari@MIT.EDU
In-Reply-To: <199803060434.XAA09766@M66-080-3.MIT.EDU> (message from Gaurav
	Tewari on Thu, 05 Mar 1998 23:34:18 EST)
Subject: Re: Prob. set 5
Cc: 6042-help
Reply-To: 6042-meyer@theory.lcs.mit.edu

   Date: Thu, 05 Mar 1998 23:34:18 EST
   From: Gaurav Tewari <gtewari@MIT.EDU>


   Hello Prof. Meyer,
           Couple of quick clarifications about PS5:

   1). In Prob. 1 do the Meng students start paying back 5 years after starting
   Meng or 5 years after finishing it (ie, 10 years after starting)? Its not clear
   what "Wait five years" means.

EITHER INTERPRETATION IS FINE, although it seems preety clear to me (I
didn't write this problem) that the intended interpretation is that the
loan should be paid back 5 years after starting, viz., immediately after
finishing the program.

   2). Prob. 8: Did you mean for the lower limit of the summation to be i = 0
   rather than 1?....It would make the differentiation a lot easier because : (a)
   there would be 'n' rather than (n-1) terms in the sum, and (b) would make the
   first term 1 rather than 'x'--with 'x' the differetiation is very hairy

LOOK AGAIN and you'll see it obviously makes no difference if the sum
starts at i= 0 or i = 1.

   Also are we to assume that Abs(x) < 1 ? (Condition for convergence)

NO.  It's a finite sum, so convergence is not an issue.

   Thanks very much,

   Gaurav

P.S. A better address for email about psets is
                  6042-help@theory.lcs.mit.edu.
You're welcome to use 6042-meyer@theory.lcs.mit.edu when you
really want my personal attention.


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Summary-line:  6-Mar               mroh@MIT.EDU  [35] #team problem 2a 
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To: 6042-meyer@theory.lcs
Cc: 6042-help@theory.lcs
Subject: team problem 2a 
Date: Fri, 06 Mar 1998 09:29:08 EST


Albert,

I'm curious about 2a. If I read the question right, then f(n)=0 for
even n, and g(n)=0 for odd n. Therefore we could even have f(n) =
(n mod 2), g(n) = (n+1 mod 2), and we'd satisfy the problem, right?
Just wanted to run this by you before I present it in class.

I'm confused because of the reference to f(n) being n times the size
of g(n) for odd n, even though g(n) is 0, not 1. (I suppose we could
add 1 to both f(n) and g(n) for clarity, though.)

Mark

-----------
Mark Roh, mroh@mit.edu
(617) 497-4876





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Summary-line:  6-Mar               mroh@MIT.EDU  [32] #Re: team problem 2a 
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To: 6042-help@theory.lcs
Subject: Re: team problem 2a 
In-Reply-To: Your message of "Fri, 06 Mar 1998 09:38:15 EST."
             <199803061438.JAA14275@Kings-College.MIT.edu> 
Date: Fri, 06 Mar 1998 09:56:50 EST


Clarification: When I suggested added 1 to both f and g, I meant f and
g as stated in the sol'n, not my 0/1 f and g. Adding 1 to the printed
sol'n would allow us to say that f and g are n (technically n+1) times
each other for appropriately chosen n, so that we're not multiplying
n and 0 to get 0.

Sorry about all the email.

Mark

-----------
Mark Roh, mroh@mit.edu
(617) 497-4876




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Summary-line:  6-Mar            flattop@MIT.EDU  [29] #hours
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I'll be logged on Sunday from 9:00 to 12 midnight Sunday 
	Monday 9-11

Wes Chao will be logged on from 11-2a.m.

jack


p.s. Wes, tell me if that's the correct time that you want to work. 
I'll probably be logged on from 11-2 also


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Summary-line:  6-Mar        to: flattop@MIT.EDU  [20] #Re: hours
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From: "Albert R. Meyer" <meyer@theory.lcs.mit.edu>
To: flattop@MIT.EDU
Cc: 6.042-help@theory.lcs.mit.edu
In-Reply-To: <35004CD1.7CE5@MIT.EDU> (flattop@MIT.EDU)
Subject: Re: hours
Reply-To: 6042-meyer@theory.lcs.mit.edu

FYI: 6042-staff also receives all email to 6042-students, so no need to
send a separate message to staff.

Regards, A.


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Summary-line:  7-Mar           ssadoway@MIT.EDU  [36] #Problem Set 5 Question 1
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Date: Sat, 07 Mar 1998 22:21:40 -0500
To: 6042-help@theory.lcs.mit.edu
From: Steve *Silent Bob* Sadoway <ssadoway@MIT.EDU>
Subject: Problem Set 5 Question 1
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This is kind of a dumb question, but I just want to make sure.  In problem
#1, it says that he'll pay you 23100 for 5 years... Then to pay him back,
one waits 5 years and then pays x for 10 years.  Does this mean that one
waits for 5 years after he's finished paying, or wait until 5 years from
now?  I say the latter here, but I'm not 100% sure...  Just trying to
clarify this.  Thanks in advance...

  -->Steve


~~~~~~~~~~~~~~~~~~~~~~~~~Steven Sadoway~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
E-mail: ssadoway@mit.edu  |  Homepage: http://web.mit.edu/ssadoway/www/
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
"We were talking 'bout something, seems like was funny, then Steven got 
quiet -  I think Steven was mad.  Maybe he wasn't mad, but we felt very
strange, in the moment, but the moment was passed and forgotten about."
                        --Ben Folds Five, "Steven's Last Night In Town"
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~


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Summary-line:  7-Mar               mroh@MIT.EDU  [28] #Re: Problem Set 5 Question 1 
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To: Steve *Silent Bob* Sadoway <ssadoway@MIT.EDU>
Cc: 6042-help@theory.lcs
Subject: Re: Problem Set 5 Question 1 
In-Reply-To: Your message of "Sat, 07 Mar 1998 22:21:40 EST."
             <3.0.2.32.19980307222140.007d9c60@hesiod> 
Date: Sat, 07 Mar 1998 22:41:45 EST


Steve, payments begin five years from today, just as you
suspected. Thanks for asking!

Mark

-----------
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(617) 497-4876




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Summary-line:  9-Mar             aileen@MIT.EDU  [35] #question #2
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Date: Mon, 09 Mar 1998 01:31:40 -0500
To: 6.042-help@theory.lcs.mit.edu
From: Aileen Tang <aileen@MIT.EDU>
Subject: question #2
Mime-Version: 1.0
Content-Type: text/plain; charset="us-ascii"

On problem 2, which property of Hn should we use?

Hn=ln(n) or |Hn-ln(n)-gamma| <= |1/2n + 1/12n^2 + 1/120n^4| and express the
closed form in terms of an inequality?

Thanks,

Aileen 

_________________________________________________________________________

Aileen Tang                            MM      MM   IIIIIIII  TTTTTTTT  
Massachusetts Institute of Technology   MM    MM    ~~ II        TT 
320 Memorial Drive Rm 704               M M  M M    @@ II        TT 
Cambridge, MA 02139                     M  MM  M    C  II        TT
http://kwaibao.mit.edu/                MM  MM  MM    V IIIII     TT
_________________________________________________________________________


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Summary-line:  9-Mar               mroh@MIT.EDU  [31] #Re: question #2 
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To: Aileen Tang <aileen@MIT.EDU>
Cc: 6042-help@theory.lcs
Subject: Re: question #2 
In-Reply-To: Your message of "Mon, 09 Mar 1998 01:31:40 EST."
             <3.0.1.32.19980309013140.006a94d8@po7.mit.edu> 
Date: Mon, 09 Mar 1998 03:05:04 EST


  Aileen, you shouldn't have to use any special formulas for
estimating Hn. Try evaluating the summation for n=1, 2, 3, 4 and see
if you can conjecture (and prove by induction) what the closed form
solution is. The hint given in the problem may be useful also.
  Thanks for the email!

Mark

-----------
Mark Roh, mroh@mit.edu
(617) 497-4876




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Date: Mon, 09 Mar 1998 14:07:31 -0500
To: 6042-help@theory.lcs.mit.edu
From: =?iso-8859-1?Q?=22Javier_S._L=F3pez=22_=3Cjslopez=40mit.edu=3E?=@MIT.EDU
Subject: 

 Hello,

        Why in the Lecture 8: Lecture Notes
the use p = 8; instead of p = .08 since
is 8%.

Thank you, 
Javier 



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Mail-from: From mroh@MIT.EDU  Mon Mar  9 09:11:49 1998
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To: jslopez@MIT.EDU
Cc: 6042-help@theory.lcs
Subject: Re: 
In-Reply-To: Your message of "Mon, 09 Mar 1998 14:07:31 EST."
             <2.2.32.19980309190731.00673f94@po10.mit.edu> 
Date: Mon, 09 Mar 1998 14:11:49 EST

*** EOOH ***
From: mroh@MIT.EDU
To: jslopez@MIT.EDU
Cc: 6042-help@theory.lcs
Subject: Re: 
In-Reply-To: Your message of "Mon, 09 Mar 1998 14:07:31 EST."
             <2.2.32.19980309190731.00673f94@po10.mit.edu> 
Date: Mon, 09 Mar 1998 14:11:49 EST


Javier, you're right: p= .08. Sorry about the typo.

Mark

-----------
Mark Roh, mroh@mit.edu
(617) 497-4876




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From: =?iso-8859-1?Q?=22Javier_S._L=F3pez=22_=3Cjslopez=40mit.edu=3E?=@MIT.EDU
Subject: 

Hello, 

        I am wondering is someone
could explain me how to do problem 3.
I tried to use ln and integrate, but it
results in a mess.

Thank you, Javier



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Summary-line:  9-Mar               mroh@MIT.EDU  [31] #prob 3
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Subject: prob 3
In-Reply-To: Your message of "Mon, 09 Mar 1998 18:45:44 EST."
             <2.2.32.19980309234544.0067ecc4@po10.mit.edu> 
Date: Mon, 09 Mar 1998 19:11:18 EST
From: "Mark C. Roh" <mroh@MIT.EDU>


Javier, you've got the right idea in taking logs, but I don't
think that the integral method is the right way to go for this
problem. Why don't you see if you can simplify the sum you get
upon taking logs? Since we're dealing with powers of 2 and 4,
you might try taking log to a different base than e.

Mark

-----------
Mark Roh, mroh@mit.edu
(617) 497-4876




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From: =?iso-8859-1?Q?=22Javier_S._L=F3pez=22_=3Cjslopez=40mit.edu=3E?=@MIT.EDU
Subject: 

hello again, 
For problem number 4, 
how can I get around the 
i=1, and j=1, to use the definition
for iand j=0. 
Javier



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Summary-line:  9-Mar            asomani@MIT.EDU  [24] #PS#5 problem #7
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To: 6042-help@theory.lcs.mit.edu
From: Ashutosh Somani <asomani@MIT.EDU>
Subject: PS#5 problem #7

Hi, I believe that the statement given in problem number 7 is true but how
does one go about proving something like that? Thanks.

Ashutosh Somani
asomani@mit.edu



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Summary-line:  9-Mar            flattop@MIT.EDU  [46] #Re: 
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hint:

sum from n=1 to infinity of x^i equals
	 sum from n=0 to infinity of x^(i+1)

Then now you can apply the formula

Hope this helps.

jack 



"Javier S. Lspez" @MIT.EDU wrote:
> 
> hello again,
> For problem number 4,
> how can I get around the
> i=1, and j=1, to use the definition
> for iand j=0.
> Javier

-- 
MIT Class of 2000
http://web.mit.edu/flattop/www/


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Summary-line:  9-Mar            flattop@MIT.EDU  [42] #Re: PS#5 problem #7
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Hi Ashutosh,

Start with what you know from the if statement:
	"If f(n) = theta(n)"
definition of theta is there exists 3 number a, b, and c all greater
than 0 such that for all n>c, 
	a*n <= f(n) <= b*n

hope this will help you get started,

jack



Ashutosh Somani wrote:
> 
> Hi, I believe that the statement given in problem number 7 is true but how
> does one go about proving something like that? Thanks.
> 
> Ashutosh Somani
> asomani@mit.edu


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Summary-line:  9-Mar              jjkim@MIT.EDU  [19] #
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To: 6042-help@theory.lcs
Date: Mon, 09 Mar 1998 20:13:12 EST
From: Janice J Kim <jjkim@MIT.EDU>

is the following an example of a closed form 
solution?

2^(2n!+n)

-janice


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Janice,

It's a closed form solution, but this answer does not look familiar to
any of the qustions????

jack


Janice J Kim wrote:
> 
> is the following an example of a closed form
> solution?
> 
> 2^(2n!+n)
> 
> -janice


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Summary-line:  9-Mar            flattop@MIT.EDU  [70] #Re: PS#5 problem #7
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you have to prove that 
a*n^2 <= sum of f(i) (i=1 to i=n) <= b*n^2

because this is the definition of the theta bounds.

jack



Ashutosh Somani wrote:
> 
> Hi again,
>         Well then if I can show that for 3 numbers a, b, and c all greater
> than 0 such that for all n>c,
> (a*n+a*n^2) <= sum of f(i) (i=1 to i=n) <= (b*n + b*n^2)
> this is true, have I proven that the statement holds?
> 
> Ashutosh Somani
> asomani@mit.edu
> 


> At 08:00 PM 3/9/98 -0500, you wrote:
> >Hi Ashutosh,
> >
> >Start with what you know from the if statement:
> >       "If f(n) = theta(n)"
> >definition of theta is there exists 3 number a, b, and c all greater
> >than 0 such that for all n>c,
> >       a*n <= f(n) <= b*n
> >
> >hope this will help you get started,
> >
> >jack



> >Ashutosh Somani wrote:
> >>
> >> Hi, I believe that the statement given in problem number 7 is true but how
> >> does one go about proving something like that? Thanks.
> >>
> >> Ashutosh Somani
> >> asomani@mit.edu
> >

-- 
MIT Class of 2000
http://web.mit.edu/flattop/www/


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Summary-line:  9-Mar            asomani@MIT.EDU  [24] #problem 7
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To: 6042-help@theory.lcs.mit.edu
From: Ashutosh Somani <asomani@MIT.EDU>
Subject: problem 7

For problem 7 of ps 5, I can't decide if the statement is true or if it is
false and the second part should read O(n^2). Which one is it?
Thanks so much.

Ashutosh Somani



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Summary-line:  9-Mar            flattop@MIT.EDU  [40] #Re: problem 7
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Hi Ashutosh,

If this statement is true, you gotta prove that it is theta(n^2).
If not, then show an counterexample.

If you think that it is 0(n^2), then the statement might not be true.
Then show an example that has a bound of (n )or even (log n).

jack



Ashutosh Somani wrote:
> 
> For problem 7 of ps 5, I can't decide if the statement is true or if it is
> false and the second part should read O(n^2). Which one is it?
> Thanks so much.
> 
> Ashutosh Somani


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From: =?iso-8859-1?Q?=22Javier_S._L=F3pez=22_=3Cjslopez=40mit.edu=3E?=@MIT.EDU
Subject: 

Hello,
How we fing a theta bound in general(Problem 6)

I didn't find about bounds either in the notes
or the book.

Thank you, Javier



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Javier,

A theta bound in general is the "biggest term" without the coeficcients

Example:
   if the equations is (n^2 + n)/2 for the sum from 1+2+3+ ... +n
	then the theta bound will be theta(n^2)
		substitute the word "theta" with the greek letter.

   if it is 14*e^x + 24132*x^40 +5x
	then it is theta(e^x)


jack


"Javier S. Lspez" @MIT.EDU wrote:
> 
> Hello,
> How we fing a theta bound in general(Problem 6)
> 
> I didn't find about bounds either in the notes
> or the book.
> 
> Thank you, Javier


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From: =?iso-8859-1?Q?=22Javier_S._L=F3pez=22_=3Cjslopez=40mit.edu=3E?=@MIT.EDU
Subject: 

Hello,    
    For problem 8 i figured
out the close form using derivatives,
but I got something extremly messy.
Therefore, tough to prove. 
Is there any other method that work 
better for this problem. 

For problem 7, I think that it holds
as long as x>1, but I don't have a clue of
how to prove it. Could you give me a hint?

Thank you, 
javier



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#8
Using derivatives is the right idea.  You should end up with some nice
solution.  Plug in some numbers first to make sure you solution works
before you start proving it.

For #7, hint to how you start the problem

Start with what you know from the if statement:
        "If f(n) = theta(n)"
definition of theta is there exists 3 number a, b, and c all greater
than 0 such that for all n>c, 
        a*n <= f(n) <= b*n


jack

"Javier S. Lspez" @MIT.EDU wrote:
> 
> Hello,
>     For problem 8 i figured
> out the close form using derivatives,
> but I got something extremly messy.
> Therefore, tough to prove.
> Is there any other method that work
> better for this problem.
> 
> For problem 7, I think that it holds
> as long as x>1, but I don't have a clue of
> how to prove it. Could you give me a hint?
> 
> Thank you,
> javier


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Date: Mon, 09 Mar 1998 22:55:10 -0500
To: 6.042-help@theory.lcs.mit.edu
From: Jamal Blackwell <jamalb@MIT.EDU>
Subject: pset 5 Q6 and Q9
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Can I have a hint as to how I can systematically find a theta bound for the
sum in question 6?  I understand the concept, but I am stumped as far as
guessing the function...
I also don't know how the integral method will help me to solve problem 9...

Thanks,
Jamal


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Summary-line:  9-Mar            flattop@MIT.EDU  [47] #Re: pset 5 Q6 and Q9
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Jamal,

Use the integral method to solve this.  Hopefully this was covered in
lecture last week.  What fuction should you use to calculate the area
under the curve of x^6?  Purpose is to find a function whose area is
slightly less than the summation of x^6 and one that is slightly more.

Hint for #8 (not #9) : don't use the integral method.  Try something
else.

jack


Jamal Blackwell wrote:
> 
> Can I have a hint as to how I can systematically find a theta bound for the
> sum in question 6?  I understand the concept, but I am stumped as far as
> guessing the function...
> I also don't know how the integral method will help me to solve problem 9...
> 
> Thanks,
> Jamal

-- 
MIT Class of 2000
http://web.mit.edu/flattop/www/


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Summary-line:  9-Mar              jjkim@MIT.EDU  [27] #problem 6
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Date: Mon, 09 Mar 1998 23:42:02 -0500
To: 6042-help@theory.lcs
From: Janice Kim <jjkim@MIT.EDU>
Subject: problem 6

I think I understand what 
f = theta (g)
means...

but could explain what a "theta bound" is?
Could you give examples too?

-janice



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Summary-line:  9-Mar            flattop@MIT.EDU  [52] #Re: problem 6
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Subject: Re: problem 6
References: <2.2.32.19980310044202.0068e214@po7.mit.edu>

Janice

A theta bound in general is the "biggest term" without the coeficients

Example:
   if the equations is (n^2 + n)/2 for the sum from 1+2+3+ ... +n
        then the theta bound will be theta(n^2)
                substitute the word "theta" with the greek letter.

   if it is 14*e^x + 24132*x^40 +5x
        then it is theta(e^x)


jack



Janice Kim wrote:
> 
> I think I understand what
> f = theta (g)
> means...
> 
> but could explain what a "theta bound" is?
> Could you give examples too?
> 
> -janice

-- 
MIT Class of 2000
http://web.mit.edu/flattop/www/


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Summary-line:  9-Mar            benchun@MIT.EDU  [35] #4 and 7
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Date: Mon, 09 Mar 1998 23:45:03 -0500
To: 6.042-help@theory.lcs.mit.edu
From: b e n c h u n <benchun@MIT.EDU>
Subject: 4 and 7
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Date: Mon, 09 Mar 1998 23:45:03 -0500
To: 6.042-help@theory.lcs.mit.edu
From: b e n c h u n <benchun@MIT.EDU>
Subject: 4 and 7

i am having trouble with problem 4 and 7.
here is what i know:

in problem 4, the higer-order terms approach zero in the limit as i and j
go to infinity. i can't figure how to evaluate that, the sum of things that
keep getting smaller and smaller and...

in problem 7, i know n^6 is omega of the sum and n^7 is big O of the sum. i
can't figure how to find something between those that the sum is going to
be theta with.

thanks for your help.


. . . . . . .
benchun@mit.edu
http://mdma.mit.edu/


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Summary-line: 10-Mar              cynic@mit.edu  [46] #Re: 4 and 7 
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To: b e n c h u n <benchun@MIT.EDU>
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Subject: Re: 4 and 7 
In-Reply-To: Your message of "Mon, 09 Mar 1998 23:45:03 EST."
             <3.0.32.19980309234502.00ab5830@po8.mit.edu> 
Date: Tue, 10 Mar 1998 00:05:46 EST

*** EOOH ***
From: Wesley S Chao <cynic@mit.edu>
To: b e n c h u n <benchun@MIT.EDU>
Cc: 6042-help@theory.lcs.MIT.EDU
Subject: Re: 4 and 7 
In-Reply-To: Your message of "Mon, 09 Mar 1998 23:45:03 EST."
             <3.0.32.19980309234502.00ab5830@po8.mit.edu> 
Date: Tue, 10 Mar 1998 00:05:46 EST

>in problem 4, the higer-order terms approach zero in the limit as i and j
>go to infinity. i can't figure how to evaluate that, the sum of things that
>keep getting smaller and smaller and...

Remember that when we have nested summations, it's generally easier to
evaluate the sum by grouping expressions with the same incremental variable
together (all expressions with i together, all expressions with j together,
etc.). It is often easier to find a closed form solution for those expressions,
which we can then combine.

>in problem 7, i know n^6 is omega of the sum and n^7 is big O of the sum. i
>can't figure how to find something between those that the sum is going to
>be theta with.

First things first. I think you've got the asymptotic expressions backwards;
if n^6 is omega of the sum, then n^6 grows as fast or faster than the sum,
and if n^7 is O of the sum, then n^7 grows as fast or slower than the sum.
These statements conflict, since n^7 grows strictly faster than n^6.

Second, if you know that one thing is omega (I assume you mean big omega),
of f(n), and something else is big O of f(n), then it is possible that f(n)
is theta of either thing. That is to say, big O and big omega leave open the
possibility that the two functions grow with the same speed.

Hope that helps.

Wes.




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Summary-line: 10-Mar              to: 6042-help  [53] #n!
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From: "Albert R. Meyer" <meyer@theory.lcs.mit.edu>
To: 6042-help
In-Reply-To: <35049488.4196@MIT.EDU> (flattop@MIT.EDU)
Subject: n!
Reply-To: 6042-meyer@theory.lcs.mit.edu

*** EOOH ***
Date: Tue, 10 Mar 98 00:08:34 EST
From: "Albert R. Meyer" <meyer@theory.lcs.mit.edu>
To: 6042-help
In-Reply-To: <35049488.4196@MIT.EDU> (flattop@MIT.EDU)
Subject: n!
Reply-To: 6042-meyer@theory.lcs.mit.edu

To: flattop@MIT.EDU
Cc: jjkim@MIT.EDU

NO, the expression (n!) doesn't count as a "closed form."  It's just an
abbreviation for (Pi_{i=1}^n i), and we don't want our closed forms to
have sums or products or whatever running over indices.

But (n!) can be an informative answer, and if it really can't be
simplified away, its presence indicates that there isn't a closed form of
the answer.  The best we can do with (n!) is assymptotically approximate
it with the closed form given by Sterling's formula.

Regards, A. 

   Sender: flattop@MIT.EDU
   Date: Mon, 09 Mar 1998 20:16:56 -0500
   From: "Jack V. Chung" <flattop@MIT.EDU>
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   Janice,

   It's a closed form solution, but this answer does not look familiar to
   any of the qustions????

   jack


   Janice J Kim wrote:
   > 
   > is the following an example of a closed form
   > solution?
   > 
   > 2^(2n!+n)
   > 
   > -janice
------- End of forwarded message -------


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Summary-line: 10-Mar              jjkim@MIT.EDU  [31] #Problem 6
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Date: Tue, 10 Mar 1998 00:21:34 -0500
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From: Janice Kim <jjkim@MIT.EDU>
Subject: Problem 6

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Date: Tue, 10 Mar 1998 00:21:34 -0500
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From: Janice Kim <jjkim@MIT.EDU>
Subject: Problem 6

Can we use the integral method to find the theta bound for number 6?
so, would k^7 be the uper bound by this method?

-janice
 -------------------------------------------------------
  Janice Juyeon Kim
  410 Memorial Drive
  Cambridge, MA 02139
  
  e-mail : jjkim@mit.edu
  web    : http://www.mit.edu/people/jjkim/Welcome.html
 -------------------------------------------------------



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Summary-line: 10-Mar              cynic@mit.edu  [35] #Re: Problem 6 
Mail-from: From cynic@mit.edu  Mon Mar  9 19:25:21 1998
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To: Janice Kim <jjkim@MIT.EDU>
Cc: 6042-help@theory.lcs.MIT.EDU
Subject: Re: Problem 6 
In-Reply-To: Your message of "Tue, 10 Mar 1998 00:21:34 EST."
             <2.2.32.19980310052134.0068a638@po7.mit.edu> 
Date: Tue, 10 Mar 1998 00:25:21 EST

*** EOOH ***
From: Wesley S Chao <cynic@mit.edu>
To: Janice Kim <jjkim@MIT.EDU>
Cc: 6042-help@theory.lcs.MIT.EDU
Subject: Re: Problem 6 
In-Reply-To: Your message of "Tue, 10 Mar 1998 00:21:34 EST."
             <2.2.32.19980310052134.0068a638@po7.mit.edu> 
Date: Tue, 10 Mar 1998 00:25:21 EST


>Can we use the integral method to find the theta bound for number 6?

Not only can you, you should. In general, when you're looking to find a theta
bound, the integral method is one of the first things to try. The very process
of using the integral method lends itself to the definition of a theta bound.

Anyway, the short answer, again, is yes.

>so, would k^7 be the uper bound by this method?

Sort of. I'm betting you mean n^7, so I'll be a little anal -- k is
being incremented towards n, so the expression k^7 doesn't really mean 
anything in the context of the question. You want to express your theta 
bound in n. 

Wes.



1,,
Summary-line: 10-Mar              jjkim@MIT.EDU  [23] #Integral Method
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Date: Tue, 10 Mar 1998 01:11:01 -0500
To: 6042-help@theory.lcs.MIT.EDU
From: Janice Kim <jjkim@MIT.EDU>
Subject: Integral Method

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Date: Tue, 10 Mar 1998 01:11:01 -0500
To: 6042-help@theory.lcs.MIT.EDU
From: Janice Kim <jjkim@MIT.EDU>
Subject: Integral Method

Is there a clear description of hte Integral method somewhere in the lecture
notes, Rosen, or Nuts and Bolts?

-janice



1,,
Summary-line: 10-Mar              cynic@mit.edu  [22] #Re: Integral Method 
Mail-from: From cynic@mit.edu  Mon Mar  9 20:16:28 1998
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To: Janice Kim <jjkim@MIT.EDU>
Cc: 6042-help@theory.lcs.MIT.EDU
Subject: Re: Integral Method 
In-Reply-To: Your message of "Tue, 10 Mar 1998 01:11:01 EST."
             <2.2.32.19980310061101.0069c664@po7.mit.edu> 
Date: Tue, 10 Mar 1998 01:16:28 EST

*** EOOH ***
From: Wesley S Chao <cynic@mit.edu>
To: Janice Kim <jjkim@MIT.EDU>
Cc: 6042-help@theory.lcs.MIT.EDU
Subject: Re: Integral Method 
In-Reply-To: Your message of "Tue, 10 Mar 1998 01:11:01 EST."
             <2.2.32.19980310061101.0069c664@po7.mit.edu> 
Date: Tue, 10 Mar 1998 01:16:28 EST

>Is there a clear description of hte Integral method somewhere in the lecture
>notes, Rosen, or Nuts and Bolts?

The best place to look would be the Fall '97 notes, a link to which ought to be
on the current 6.042 website. The exact date on which the notes were presented
escapes me at the moment, but if you are having trouble finding it, I can
look it up for you. I do remember that there are two sets of notes, from
lectures on consecutive days. One has an example of using the Integral Method
on a function which is increasing, and the other has an example of using it
on a function which is decreasing. There are some subtle differences between
the two.

Wes.


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References: <199803101504.AA08248@stork.lcs.mit.edu>
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*** EOOH ***
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References: <199803101504.AA08248@stork.lcs.mit.edu>

We'll talk more about this in our helpers meeting.
Is it this Thurday at 4:30?


jack


Albert R. Meyer wrote:
> 
> Do you intend to be available by zephyr as well as email during 6042-help
> hours?  If so, how about adding zephyr contact info to the help-info page?
> 
> Regards, A.

-- 
MIT Class of 2000
http://web.mit.edu/flattop/www/

From psomani@MIT.EDU  Sat Mar 14 19:36:24 1998
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To: 6042-help@theory.lcs.mit.edu
From: Paritosh Somani <psomani@MIT.EDU>
Subject: plug and chug

I am a little confused as to how you get theta bounds for functions for
which the master theorem does not apply.

I know that you plug/chug or use the interations to get a pattern/sum and
get a formula.....but then what? How do you get the theta bound from this?
Do you approximate along some time?

Also, I had a question regarding the integration method: Do you set the
limits of integration from 0 to n and 0 to (n+1) OR do you keep them 0 to n
for both but add a + 1 for the larger integral? this refers to probelm 15,
part (a) because the answers keep the same limits of integration (1 to n)
and just do +1 for the larger one.

thanks 
Paritosh Somani


From asomani@MIT.EDU  Sat Mar 14 19:36:31 1998
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To: 6042-help@theory.lcs.mit.edu
From: Ashutosh Somani <asomani@MIT.EDU>
Subject: 

Hi,
        I had a question regarding problem 18 d) on the practice
quiz...could you just give me a general explanantion of what approach they
are using to solve the problem and how they accomplished it? Thanks.

Ashutosh Somani


From cynic@mit.edu  Sun Mar 15 11:25:40 1998
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From: Wesley S Chao <cynic@mit.edu>
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To: 6042-help@theory.lcs.MIT.EDU
Subject: Theta bounds
Date: Sun, 15 Mar 1998 16:25:40 EST

>I am a little confused as to how you get theta bounds for functions for
>which the master theorem does not apply.

Did we go over the Akra-Bazzi formula for finding theta bounds on 
recursive functions? It would seem that Akra-Bazzi is the natural answer to the
question, but maybe we haven't covered it. It is in last term's curriculum,
is why I ask...

Wes.

From mroh@MIT.EDU  Sun Mar 15 12:05:58 1998
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To: Wesley S Chao <cynic@MIT.EDU>
Cc: 6042-help@theory.lcs
Subject: Re: Theta bounds 
In-Reply-To: Your message of "Sun, 15 Mar 1998 16:25:40 EST."
             <199803152125.QAA27145@SCHOPENHAUER.MIT.EDU> 
Date: Sun, 15 Mar 1998 17:05:58 EST


Wes, Akra-Bazzi is not part of this semester's curriculum.

Mark

-----------
Mark Roh, mroh@mit.edu
(617) 497-4876



From wchien@MIT.EDU  Mon Mar 16 14:46:12 1998
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To: 6042-help@theory.lcs.mit.edu
Subject: Re: plug and chug 
In-Reply-To: Your message of "Sun, 15 Mar 1998 00:36:24 EST."
             <9803150536.AA25109@MIT.MIT.EDU> 
Date: Mon, 16 Mar 1998 19:46:12 EST
From: Wendy S Chien <wchien@MIT.EDU>


*****I sent this to Paritosh already, but i forgot to cc it to
*****6042-help


Hi Paritosh,

Has anyone answered your question?

> I am a little confused as to how you get theta bounds for functions for
> which the master theorem does not apply.

> I know that you plug/chug or use the interations to get a pattern/sum and
> get a formula.....but then what? How do you get the theta bound from this?
> Do you approximate along some time?

When you use plug and chug you should get a summation of which you 
hopefully know the closed form (something like nlog(n) or n(n+1)/2).
From there you can find the theta bounds.  


> Also, I had a question regarding the integration method: Do you set the
> limits of integration from 0 to n and 0 to (n+1) OR do you keep them 0 to n
> for both but add a + 1 for the larger integral? this refers to probelm 15,
> part (a) because the answers keep the same limits of integration (1 to n)
> and just do +1 for the larger one.

It depends.  The reason why they added a "+1" to the integral in problem
15 is because the first block in the sum is at height 1.  If this is not
the case, then you cannot just add 1 to the integral.  As for the upper 
bound, it depends on what your function inside the integral is.  It is
usually easiest to determine the correct bounds by drawing out the
summation blocks and connecting the upper left corners to get the function
of one of the bounds and connecting the upper right corners of the
blocks for the function that serves as the other bound.  By looking at
these two functions you can read off what the right bounds are.



If any of this response is confusing or unclear, please email again.

Wendy


From wchien@MIT.EDU  Mon Mar 16 14:52:20 1998
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To: Ashutosh Somani <asomani@MIT.EDU>
Cc: 6042-help@theory.lcs.mit.edu
Subject: Re: 
In-Reply-To: Your message of "Sun, 15 Mar 1998 00:36:31 EST."
             <9803150536.AA25117@MIT.MIT.EDU> 
Date: Mon, 16 Mar 1998 19:52:20 EST
From: Wendy S Chien <wchien@MIT.EDU>


Hi Ashutosh,


>        I had a question regarding problem 18 d) on the practice
> quiz...could you just give me a general explanantion of what approach they
> are using to solve the problem and how they accomplished it? Thanks.


They are using the Guess and Verify (aka substitution) method.  They
make a guess as to what they think the bound is and then they use
induction to prove it.  They guess theta(n) probably because the g(n)
term is n and it seems like it would dominate the recurrence (there
would be more work due to n than the T(n/4) and T(n/2)).  

Wendy

From akl@MIT.EDU  Mon Mar 16 16:44:52 1998
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Date: Mon, 16 Mar 1998 21:44:52 -0500
To: 6042-help@theory.lcs.mit.edu
From: "Aimee K. Lee" <akl@MIT.EDU>
Subject: clarification
Mime-Version: 1.0
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hi,

do i need to know boolean assigments and divide-and-conquer
recurrences for the test?

thanks.

aimee lee


	            ***********************************************
					     Aimee K. Lee   <><  
		     320 Memorial Drive  Cambridge, MA 02139
					    MIT class of 2001


From kylee@mit.edu  Mon Mar 16 17:30:44 1998
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To: "Aimee K. Lee" <akl@MIT.EDU>
Cc: 6042-help@theory.lcs.mit.edu
Subject: Re: clarification 
In-Reply-To: Your message of "Mon, 16 Mar 1998 21:44:52 EST."
             <9803170246.AA29224@MIT.MIT.EDU> 
Date: Mon, 16 Mar 1998 22:30:44 EST
From: Edmond Kayi Lee          <kylee@mit.edu>

>do i need to know boolean assigments and divide-and-conquer
>recurrences for the test?

Divide and conquer recurrence is difinitely covered. You should be
familiar with the Master Theorem and Plug and Chuck method, and know how
to derive a recurrence as well.


Boolean assignment is not formally taught as a topic. But it is a concept 
that may appear and not too hard to understand. Informally, given a boolean
formula, e.g., (x^y)->z, where x, y, z are boolean variables, a boolean
assignment is the assignment of boolean values (T/F) of the variables in the 
formula. For instance, the assignment x=T, y=F, z=T is one of the boolean
assignments for the formula (there are other assignment for the formula.).
And that's what a boolean assignment means. 
Formally speaking, a boolean assignment is a function which maps the set
of boolean variables in a boolean formula to the set {T, F}.


So this is what it means, let me know if you have more questions.



Edmond

From meyer@theory.lcs.mit.edu  Mon Mar 16 17:33:00 1998
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From: "Albert R. Meyer" <meyer@theory.lcs.mit.edu>
To: akl@MIT.EDU
Cc: 6042-help@theory.lcs.mit.edu
In-Reply-To: <9803170246.AA29224@MIT.MIT.EDU> (akl@MIT.EDU)
Subject: Re: clarification
Reply-To: 6042-meyer@theory.lcs.mit.edu

Divide and Conquer: YES
Boolean assignments: NO
Regards, A.

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   Date: Mon, 16 Mar 1998 21:44:52 -0500
   From: "Aimee K. Lee" <akl@MIT.EDU>

   hi,

   do i need to know boolean assigments and divide-and-conquer
   recurrences for the test?

   thanks.

   aimee lee


                       ***********************************************
                                                Aimee K. Lee   <><  
                        320 Memorial Drive  Cambridge, MA 02139
                                               MIT class of 2001



From jjkim@KOA.MIT.EDU  Tue Mar 17 20:09:52 1998
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From: Janice J Kim <jjkim@mit.edu>
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To: 6042-help@theory.lcs.mit.edu
Subject: practice prob 9c
Date: Wed, 18 Mar 1998 01:09:52 EST

hello...

in the solution for practice problem 9c, they use the term odd cycle.
Could you define odd cycle and and explain why it cannot be bipartite.

Also, could you explain why a graph colored with two colors must be bipartite.

thanks :)

-janice

From kylee@MIT.EDU  Tue Mar 17 20:27:31 1998
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To: Janice J Kim <jjkim@MIT.EDU>
Cc: 6042-help@theory.lcs.mit.edu
Subject: Re: practice prob 9c 
In-Reply-To: Your message of "Wed, 18 Mar 1998 01:09:52 EST."
             <199803180609.BAA13694@KOA.MIT.EDU> 
Date: Wed, 18 Mar 1998 01:27:31 EST
From: Edmond Kayi Lee          <kylee@MIT.EDU>

An odd cycle is a cycle with odd number of vertices.

If C is an odd cycle, we can number the vertices as 1,2,3,...,2n+1 along the
cycle. Assume it is bipartite, then we know that vertex 1 and 2 have to be in
different sets, namely A and B, since they are adjacent. Then you should see 
that (and we can use induction to prove that) all odd numbers have to be in 
set A and even numbers have to be in set B. So we have both vertices 2n+1 
and 1 in set A. But they are adjacent, and it contradicts that all 
vertices in set A are not adjacent. So C cannot be bipartite. 

If a graph is 2 colorable, then the vertices of the graph can be divided into
2 sets according to their colors, namely A and B. By definition of coloring, 
nodes with same color are not adjacent to each other, so every node in set A
is not adjacent to each other. Similarly, every node in set B is not adjacent 
to each other. This satisfies the defintion of being a bipartite graph.

Let me know if you still have questions.

Edmond

From jslee@BBN.COM  Wed Mar 18 11:09:04 1998
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To: 6042-help@theory.lcs.mit.edu
Subject: Practice Quiz  Prob 19.
Date: Wed, 18 Mar 98 16:09:04 -0500
From: jslee@BBN.COM



(b). T(n) = 4T(n/3) + n.

     Solution shows  that the summation in the big parenthesis
     is Theta(4/3)**log3n.   Is it because a summation of geometric 
     sequence whose "x" term is greater than 1 is Theta(L) where L is 
     the upper bound for the index of the summation :
   
        i=L
       SIGMA x**i = Theta(x**L) , x< 1  ?
        i=0 



    Why is (4/3)**log(base3)n = Theta (n**(log(base3)(4/3)))  ?


     (4/3)**log(base3)n 

     =  [ 4 * (3**(-1)) ] ** log(base3)n

     =  (4 ** log(base3)n )  * (3**(-log(base3)n))

     =  (4 ** log(base3)n )  * 1/n

    so,  why is

    (4 ** log(base3)n )  ??=  Theta  (n**(log(base3)(4/3)))  
    



From brianlin@MIT.EDU  Wed Mar 18 11:01:43 1998
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Date: Wed, 18 Mar 1998 16:01:43 -0500
To: 6042-help@theory.lcs.mit.edu
From: Li-Kuo Lin <brianlin@MIT.EDU>
Subject: 8b, 18d, 19ab, 
Mime-Version: 1.0
Content-Type: text/plain; charset="us-ascii"

In the inductive step of part b of 8, you said that if G(n+1) was regular
then P(n+1) holds trivially, but didn't we already say that the graphs were
not regular? Plus, isn't a regular graph of degree k, only k+1 colorable?

For 18d, what method did you exactly use, that you were allowed to
substitute alpha*n for T(n)..and why does it work, and which type of
recurrences can you use it for?

For 19, why couldn't you have used the master theorem to solve them, also
if I was to write the recurrence as a sum...
for example, "a" would be (SUM from i=0 to k) (7^i)(n/3^i)^2

how would I come to the same conclusion using this method, or is that an
impossibility, can I also use the sum method for "b"?

For 19 and recurrences in general, after you iterate, is it true that you
can get rid of any term that doesn't have an "n" in them, even if they are
multiplied by some function of n when you change to theta notation?

Also in general, is it true that the theta bound of any sum is just the
integral of the function being summed (with limits as the limits of the
index of summation)?

Thanks a bunch

----------------------------------------------------------------------------
------------------

Li-Kuo (Brian) Lin
410 Memorial Drive
Cambridge MA, 02139
(617)-225-8265
brianlin@mit.edu

"The only thing that interferes with my learning is my education." -Albert
Einstein
                            /
	 \                     /  /
      \ \ \'  ,           /  / / 
       \ \ \ / /,      _/  / / ,
        \ _ -/ / '   /    / / <,
            \   / / /    </ / ` 
                /   >>   \ \ \` __/_
               /, ) -^>>  _\`  \ \ \
               ( /     \ \    / /\ \ 
                       / /  _/ / \ \ \ \
                     ( ( `  ( (


From kylee@MIT.EDU  Wed Mar 18 11:20:53 1998
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To: jslee@BBN.COM
Cc: 6042-help@theory.lcs.mit.edu
Subject: Re: Practice Quiz Prob 19. 
In-Reply-To: Your message of "Wed, 18 Mar 1998 16:09:04 EST."
             <199803182102.AA22729@theory.lcs.mit.edu> 
Date: Wed, 18 Mar 1998 16:20:53 EST
From: Edmond Kayi Lee          <kylee@MIT.EDU>

     Solution shows  that the summation in the big parenthesis
     is Theta(4/3)**log3n.   Is it because a summation of geometric 
     sequence whose "x" term is greater than 1 is Theta(L) where L is 
     the upper bound for the index of the summation :
   
        i=L
       SIGMA x**i = Theta(x**L) , x< 1  ?
        i=0 

What you have said is a Omega bound for the summation. For Theta, we need to 
find an uppen bound as well.

From the formula, we have


	i=L
	SIGMA x^i = (1-x^i)/(1-x)
	i=0

Here, x=(4/3) and L=log_3 n, so the summation becomes:

	(1-(4/3)^(log n))/(1-(4/3))

=3*(4/3)^(log n)-3

=Theta((4/3)^(log n))

This answers your first question.



For the second question,
    Why is (4/3)**log(base3)n = Theta (n**(log(base3)(4/3)))  ?


Let k=4/3

 (4/3)**log(base3)n 
=k^(log_3 n)
=(3^(log_3 k))^(log_3 n)
=(3^ ((log_3 k)(log_3 n)) )
=(3^ ((log_3 n)(log_3 k)) )
=n^(log_3 k)


which is what we want.





-Edmond

From kylee@MIT.EDU  Wed Mar 18 11:38:59 1998
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To: Li-Kuo Lin <brianlin@MIT.EDU>
Cc: 6042-help@theory.lcs.mit.edu
Subject: Re: 8b, 18d, 19ab, 
In-Reply-To: Your message of "Wed, 18 Mar 1998 16:01:43 EST."
             <Version.32.19980318010345.00e926a0@po8.mit.edu> 
Date: Wed, 18 Mar 1998 16:38:59 EST
From: Edmond Kayi Lee          <kylee@MIT.EDU>

>In the inductive step of part b of 8, you said that if G(n+1) was regular
>then P(n+1) holds trivially, but didn't we already say that the graphs were
>not regular? Plus, isn't a regular graph of degree k, only k+1 colorable?

The statement is in the form of "If A then B", where A is "G is a connected 
graph of n vertices and maximum node degree k that is not regular" and 
B is "G is k-colorable".

So in the prove, if G is regular, then A is false, so "If A then B" is trivially
true, even if it is only k+1 colorable.


>For 18d, what method did you exactly use, that you were allowed to
>substitute alpha*n for T(n)..and why does it work, and which type of
>recurrences can you use it for?

This is more like guessing. You assume that T(n) is linear (possibly by
playing around with the recurrence). Then you prove that the recurrence 
is always smaller than alpha*n for some alpha, thereby proving big O.

It is Omega(n) because of the term n in the recurrence. You have the recurrence
T(n)=T(n/2)+T(n/4)+n >= n for all n, so it is Omega.

Since it is both big O and big Omega, it is Theta of n.


>For 19, why couldn't you have used the master theorem to solve them, also
>if I was to write the recurrence as a sum...
>for example, "a" would be (SUM from i=0 to k) (7^i)(n/3^i)^2
>
>how would I come to the same conclusion using this method, or is that an
>impossibility, can I also use the sum method for "b"?


You can definitely use Master's Thm in Q 19. Your sum is basically the same
as the one is solution, after you simplify it a little bit, you will get the
same answer. part "b" is using the sum method in the solution. (I assume the
sum method you mean is iteration).


>For 19 and recurrences in general, after you iterate, is it true that you
>can get rid of any term that doesn't have an "n" in them, even if they are
>multiplied by some function of n when you change to theta notation?
 
I am not sure what you are asking. But in all cases you have to be careful 
with this. For example, if I get a summation like (1+1+...+1) with n terms 
in it. You cannot drop those 1's because if you drop them, the sum will become
0 which is not true. This is because there are n terms inside.

>Also in general, is it true that the theta bound of any sum is just the
>integral of the function being summed (with limits as the limits of the
>index of summation)?

Not true in general. For some weird functions you can't use the integral 
method to bound them. Every time you use the method you better draw a picture
to make sure the integrals you derive serve well as the upper bound and the
lower bound of the summation.


-Edmond

 

From brianlin@MIT.EDU  Wed Mar 18 11:52:42 1998
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From: Li-Kuo Lin <brianlin@MIT.EDU>
Subject: sums
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is the growth of n^ (log k) 

where k<1 

and it's the log of any base

constant?

so if you have n^2(n^l(log k))  is that theta n^2 ?
----------------------------------------------------------------------------
------------------

Li-Kuo (Brian) Lin
410 Memorial Drive
Cambridge MA, 02139
(617)-225-8265
brianlin@mit.edu

"The only thing that interferes with my learning is my education." -Albert
Einstein
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                /   >>   \ \ \` __/_
               /, ) -^>>  _\`  \ \ \
               ( /     \ \    / /\ \ 
                       / /  _/ / \ \ \ \
                     ( ( `  ( (


From kylee@MIT.EDU  Wed Mar 18 12:06:57 1998
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To: Li-Kuo Lin <brianlin@MIT.EDU>
Cc: 6042-help@theory.lcs.mit.edu
Subject: Re: sums 
In-Reply-To: Your message of "Wed, 18 Mar 1998 16:52:42 EST."
             <9803182152.AA17416@MIT.MIT.EDU> 
Date: Wed, 18 Mar 1998 17:06:57 EST
From: Edmond Kayi Lee          <kylee@MIT.EDU>

>is the growth of n^ (log k) 
>
>where k<1 
>
>and it's the log of any base
>
>constant?

I should say the growth of n^(log k) is just THETA(n^(log k)). There
is nothing more we can say about it. If log k<0, then it is O(1) but 
not THETA(1). IF you want to give a THETA bound, the function itself 
is the answer.


> so if you have n^2(n^l(log k))  is that theta n^2 ?
Again, the function itself is the answer. 



-Edmond



From jslee@BBN.COM  Mon Mar 23 08:54:31 1998
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Subject: course web site
Date: Mon, 23 Mar 98 13:54:31 -0500
From: jslee@BBN.COM


Could someone please post the writeup for last week's
recitation (Recitation 7?) on the Web site?   Thank you!

From meyer@theory.lcs.mit.edu  Mon Mar 23 12:10:30 1998
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From: "Albert R. Meyer" <meyer@theory.lcs.mit.edu>
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Reply-To: 6042-meyer@theory.lcs.mit.edu

It's been available on the web page for several days.

Yours truly,
Prof. Albert R. Meyer
MIT Lab. for Computer Science 

   Cc: mroh@mit.edu
   Date: Mon, 23 Mar 98 13:54:31 -0500
   From: jslee@BBN.COM


   Could someone please post the writeup for last week's
   recitation (Recitation 7?) on the Web site?   Thank you!


From mphil14@MIT.EDU  Mon Mar 23 16:15:13 1998
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To: 6042-help@theory.lcs.mit.edu
Subject: PS 6
Date: Mon, 23 Mar 1998 21:15:13 EST
From: Mark Phillip <mphil14@MIT.EDU>

Hi, for problem 3b) I end up with f(n)= f(n-1) + 2f(n-2) + 3(n-1).  When I am setting up the characteristic equation in 3c), what do I do with the 3(n-1)?  Any help would be appreciated...thanks...-mark



Mark Phillip
Phi Sigma Kappa
Boston MA, 02215


REEFPRODUCTIONS.mit.edu
web.mit.edu/mphil14/www


"near...far.....NEAR....FAR!!!"

From BLin922@aol.com  Tue Mar 24 13:20:18 1998
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I don't know if you guys are checking this mail during spring break but I
think there is an error in part b of problem 2.  It asks you to find a closed
form solution, given three initial conditions.  however, 2 of the roots of the
characteristic equations are identical, therefore I don't think there is a
possible way that all three initial conditions can be satisfied.  I have
worked on this problem for at least 5 hours now, and have tried several
methods and have come up with the same answer: I am only able to satisfy two
initial conditions, 0, and 16, but after that, my series does satisfy the
recurrence.  If there is an error, please reply to this e-mail or post it on
the web, or could you give me a hint if it is in fact possible?

Brian Lin
(Li-kuo)
brianlin@mit.edu


From flattop@MIT.EDU  Tue Mar 24 13:34:16 1998
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To: BLin922 <BLin922@aol.com>
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Hi Brian,

That was the intent of the problem.  If two of the roots are the same,
you do this:
	(let say it a double root of 5)
A*5^n + B*n*5^n

Do you remember this from lecture?  This is similar to what you would do
in 18.03.

Hope this helped.

jack


BLin922 wrote:
> 
> I don't know if you guys are checking this mail during spring break but I
> think there is an error in part b of problem 2.  It asks you to find a closed
> form solution, given three initial conditions.  however, 2 of the roots of the
> characteristic equations are identical, therefore I don't think there is a
> possible way that all three initial conditions can be satisfied.  I have
> worked on this problem for at least 5 hours now, and have tried several
> methods and have come up with the same answer: I am only able to satisfy two
> initial conditions, 0, and 16, but after that, my series does satisfy the
> recurrence.  If there is an error, please reply to this e-mail or post it on
> the web, or could you give me a hint if it is in fact possible?
> 
> Brian Lin
> (Li-kuo)
> brianlin@mit.edu

-- 
MIT Class of 2000
http://web.mit.edu/flattop/www/

From cynic@mit.edu  Wed Mar 25 10:12:54 1998
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From: Wesley S Chao <cynic@mit.edu>
Message-Id: <199803252012.PAA20257@SCHOPENHAUER.MIT.EDU>
To: Mark Phillip <mphil14@MIT.EDU>
Cc: 6042-help@theory.lcs.mit.edu
Subject: Re: PS 6 
In-Reply-To: Your message of "Mon, 23 Mar 1998 21:15:13 EST."
             <199803240215.VAA19864@scrubbing-bubbles.MIT.EDU> 
Date: Wed, 25 Mar 1998 15:12:54 EST

> for problem 3b) I end up with f(n)= f(n-1) + 2f(n-2) + 3(n-1).  When I am se
>tting up the characteristic equation in 3c) what do I do with the 3(n-1)?  Any
>help would be appreciated...thanks...-mark
                            
Has your question been answered yet? It seems a little old, but if not...

When we solve recurrences, we want to try and get a closed form; in doing so,
we want to find the characteristic equation, *but*, the characteristic equation
is only useful is solving for the *homogenous* solution (think differential
equations). For a simple recurrence, like, say, Fibonacci numbers, the 
homogenous solution is the total solution. But in the case of problem 3,
there is a particular solution. Your equation, properly rearranged, should
look like this:

f(n) - f(n-1) - 2f(n-2) = 3(n-1).

Then you can set the right hand side to 0 and solve as you would normally for
the homogenous solution. After that, you can solve for the particular solution
just as you would for differential equations (guess a form with undetermined
coefficients, then solve for the coefficients). 

Oh, and as a final note, check your equation for 3b. According to the copy of
the problem set I have, 3(n-3) physicists become professors, not 3(n-1).

Hope this is helpful.

Wes.

From psomani@MIT.EDU  Mon Apr  2 17:13:33 1998
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To: 6042-help@theory.lcs.mit.edu
From: Paritosh Somani <psomani@MIT.EDU>
Subject: #6

Hi,

I have no clue as to approaching question 6 on the problem set.
How would one use the hint?
How do you prove that a string is countable?
Thanks,
Paritosh


From flattop@MIT.EDU  Mon Apr  2 17:26:06 1998
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Hi

The definition of countable is to be able to list the set.  Even though
the set might be infinite, if you find a way to list that set such that
all the elements are listed, then it is countable.  
For example, the set of natural numbers in countable because you can
list them:
  { 0, 1, 2, 3, 4, 5, 6, 7 ... }

So the hint tells you to find a way to list these infinite binary
strings, which is the harder part.

Hope this sort of helps

jack


Paritosh Somani wrote:
> 
> Hi,
> 
> I have no clue as to approaching question 6 on the problem set.
> How would one use the hint?
> How do you prove that a string is countable?
> Thanks,
> Paritosh

-- 
MIT Class of 2000
http://web.mit.edu/flattop/www/

From asomani@MIT.EDU  Mon Apr  2 17:30:08 1998
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To: 6.042-help@theory.lcs.mit.edu
From: Ashutosh Somani <asomani@MIT.EDU>
Subject: PS #6 Problem 5

Hi,
        I had a question about problem 5 part a)....Can we assume that sin x
is defined over all x (so it would fail the horizontal line test) or do we
assume it is defined from -pi/2 to pi/2??

Thanks,

Ashutosh Somani
asomani@mit.edu


From flattop@MIT.EDU  Mon Apr  2 17:34:37 1998
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Hi,

sin x IS defined over all x
I think that you are confused regarding sine and inverse sine

Hope this helps.

jack


Ashutosh Somani wrote:
> 
> Hi,
>         I had a question about problem 5 part a)....Can we assume that sin x
> is defined over all x (so it would fail the horizontal line test) or do we
> assume it is defined from -pi/2 to pi/2??
> 
> Thanks,
> 
> Ashutosh Somani
> asomani@mit.edu

From jjkim@MIT.EDU  Mon Apr  2 18:46:31 1998
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Date: Mon, 30 Mar 1998 23:46:31 -0500
To: 6042-help@theory.lcs.mit.edu
From: Janice Kim <jjkim@MIT.EDU>
Subject: pset6, problem 5a

hello...

i have a question on number 5a.

f(x)= sin x

I can see that this is not an injection because both 
f(2pi) and f(0) equal the same thing... but 2pi does not equal 0.

Then, from this can we conclude that it is not a bijection?
(rosen says that a bijection is one-to-one and onto)

Also, can we conclude that it is not a surjection because f(x) never equals 2?

I'm trying to relate my thinking to the examples on page 62 and 63 in Rosen.
There, i think rosen says that f(x) = x^2 is neither a injection or surjection.

Is my reasoning correct?
I guess what's confusing me is that
  f(x) = sin x
can be a surjection between the range (-1,1), right?

and 
  f(x) = sin x
can be an bijection within a certain range because it has an inverse between
a certain range... is that right?
do we have to include this in our homework write-up?
hrmm....
:(

-janice
 -------------------------------------------------------
  Janice Juyeon Kim
  410 Memorial Drive
  Cambridge, MA 02139
  
  e-mail : jjkim@mit.edu
  web    : http://www.mit.edu/people/jjkim/Welcome.html
 -------------------------------------------------------


From cynic@mit.edu  Mon Apr  2 19:05:30 1998
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From: Wesley S Chao <cynic@mit.edu>
Message-Id: <199803310505.AAA28059@SCHOPENHAUER.MIT.EDU>
To: Janice Kim <jjkim@MIT.EDU>
Cc: 6042-help@theory.lcs.mit.edu
Subject: Re: pset6, problem 5a 
In-Reply-To: Your message of "Mon, 30 Mar 1998 23:46:31 EST."
             <2.2.32.19980331044631.00682b8c@po7.mit.edu> 
Date: Tue, 31 Mar 1998 00:05:30 EST

>I can see that this is not an injection because both 
>f(2pi) and f(0) equal the same thing... but 2pi does not equal 0.
>Then, from this can we conclude that it is not a bijection?
>(rosen says that a bijection is one-to-one and onto)

Yes, we can. As long as we can prove rigorously that a function is either not
an injection or not a surjection, we can simply state something to the effect
of, "since it is not an injection/surjection, it is not a bijection by
definition". 

>Also, can we conclude that it is not a surjection because f(x) never equals 2?

Yes, again.

>There, i think rosen says that f(x) = x^2 is neither a injection or surjection

Also correct. (Are you sure you need to be sending mail here? :)

>Is my reasoning correct?

Yes.

>I guess what's confusing me is that
>  f(x) = sin x
>can be a surjection between the range (-1,1), right?

Ah, yes. In general, you can make any function a surjection, IF you define the
domain and range to fit the function. For instance, mapping the reals to the
numbers between -1 and 1, inclusive, is a surjection for sin x. We can 
construct a similar example for making sin x an injection.

>can be an bijection within a certain range because it has an inverse between
>a certain range... is that right?

Yep, something like mapping the numbers between -pi/2 and pi/2 to the numbers
between -1 and 1, would make sin x a bijection. 

>do we have to include this in our homework write-up?

Since the question specifically states mapping numbers from the reals to the 
reals, no. You can simply say, "the function is not an injection and surjection
defined over the given range."

Wes.



From ecoder@MIT.EDU  Mon Apr  2 22:13:50 1998
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Subject: 6.042 questions
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Hello,
I know this is extremely late-notice, but I would appreciate any help you
can offer before lecture time tomorrow (Tuesday).
On Problem 4b, I have no idea how to deal with the n^(1/3) term in the
recurrence. It seems that we have only dealt with constant multiples of n
in the past.
And I don't really know how to approach problem 7; the book does not talk
about that stuff and the examples in the lecture notes are not very similar
to the problem -- so I would appreciate any help.

Thanks a lot and sorry for asking this so late.
Eugene

From cynic@mit.edu  Tue Apr  3 07:41:26 1998
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In-Reply-To: Your message of "Tue, 31 Mar 1998 03:13:50 EST."
             <3.0.32.19980331031349.0084dc10@po7.mit.edu> 
Date: Tue, 31 Mar 1998 12:41:26 EST

>I know this is extremely late-notice, but I would appreciate any help you
>can offer before lecture time tomorrow (Tuesday).

Hopefully, you'll have checked your mail after noon on Tuesday...

>On Problem 4b, I have no idea how to deal with the n^(1/3) term in the
>recurrence. It seems that we have only dealt with constant multiples of n
>in the past.

Yes, this is true. We can't solve recurrences with an n^1/3 term as is, so 
what we have to do is implement a change of variables. Define a new variable
m, such that n = 2^m. Rearrange the equation with that. Then you should have
something of the form f(2^m) = a(2^m/b) + g(m), where g(m) involves 2^m.
Define a new function S(m) = f(2^m) to get S(m) in a form you can solve via
Master Method. Substitute back in the relation n = 2^m, and you should be done.

Side note #1: When you do the master method on S(m), you will almost definitely
have to deal with g(m) having an exponential term (i.e., 2^m). This is case
#3 for Master Method.

>And I don't really know how to approach problem 7; the book does not talk
>about that stuff and the examples in the lecture notes are not very similar
>to the problem -- so I would appreciate any help.

We want to prove this by diagonalization. The idea behind diagonalization is
that we arrange a proof by contradiction: first, assume we can list whatever
it is we are trying to list. Then, create a new element which is different 
in some regard from every element already in the list. (When we do this with
numbers, we often make the new number different in every digit, so that the
ith digit is different from the ith number. When we draw this out, we get
a diagonal list of different numbers; hence, the name diagonalization.) Prove
that this element should be in the list, because it satisfies whatever
requirements the other elements satisfy. Then, show that this element is not
in the list, which ought to be easy, because it should differ from the ith
element in some way, if you have done the diagonalization right.

>Thanks a lot and sorry for asking this so late.

Hope this gets to you on time.

Wes.

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From asomani@MIT.EDU  Mon Apr  6 16:39:49 1998
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To: 6.042-help@theory.lcs.mit.edu
From: Ashutosh Somani <asomani@MIT.EDU>
Subject: 

I had a question regarding the formula for palcing r indistinguishable balls
into n distinguishable bins. Is it r-1 choose n-1 or is it r+n-1 choose r ? 
Thanks.

Ashutosh Somani


From flattop@MIT.EDU  Mon Apr  6 16:49:18 1998
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Hi,

It's the second one, r+n-1 choose r.

jack


Ashutosh Somani wrote:
> 
> I had a question regarding the formula for palcing r indistinguishable balls
> into n distinguishable bins. Is it r-1 choose n-1 or is it r+n-1 choose r ?
> Thanks.
> 
> Ashutosh Somani

From digital@sls.lcs.mit.edu  Mon Apr  6 18:00:29 1998
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To: 6042-help@theory.lcs.mit.edu
Subject: ps 7 problem 7
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Date: Mon, 06 Apr 1998 22:00:29 -0400
From: James Wood <digital@sls.lcs.mit.edu>


Do you have any hints for ps 7 problem 7 ?

Thanks in advance.
---

James F. Wood, Jr.
Athena: digital@mit.edu
SLS: digital@sls.lcs.mit.edu
http://web.mit.edu/digital/
http://www.sls.lcs.mit.edu/~digital/



From jslopez@MIT.EDU  Mon Apr  6 18:10:07 1998
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Date: Mon, 06 Apr 1998 22:10:07 -0400
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From: =?iso-8859-1?Q?=22Javier_S._L=F3pez=22_=3Cjslopez=40mit.edu=3E?=@MIT.EDU
Subject: Problem #7

Hello, 
        I have been trying to figure out
how to do problem #7, but i do not even know 
how to begin. Could you give me a hint 
on how to start the problem.

thank you,
Javier


From flattop@MIT.EDU  Mon Apr  6 18:16:38 1998
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To: James Wood <digital@sls.lcs.mit.edu>
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Subject: Re: ps 7 problem 7
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Here's a hint:

First ignore the constraint that the two subsets S, T are disjoint
How would you prove that there are two non-empty subsets A, B 
	such that A is not equal to B
	and their summations using these two subsets are equal?

Second, given that you have these two non-empty different subsets A,B,
how would you make them disjoint?

Hope this will direct you in the right direction.

jack



James Wood wrote:
> 
> Do you have any hints for ps 7 problem 7 ?
> 
> Thanks in advance.
> ---
> 
> James F. Wood, Jr.
> Athena: digital@mit.edu
> SLS: digital@sls.lcs.mit.edu
> http://web.mit.edu/digital/
> http://www.sls.lcs.mit.edu/~digital/

From flattop@MIT.EDU  Mon Apr  6 18:17:34 1998
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To: "Javier S. Lspez @MIT.EDU" <jslopez@MIT.EDU>
Cc: 6042-help@theory.lcs.mit.edu
Subject: Re: Problem #7
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Here's a hint:

First ignore the constraint that the two subsets S, T are disjoint
How would you prove that there are two non-empty subsets A, B 
        such that A is not equal to B
        and their summations using these two subsets are equal?

Second, given that you have these two non-empty different subsets A,B,
how would you make them disjoint?

Hope this will direct you in the right direction.

jack



"Javier S. Lspez" @MIT.EDU wrote:
> 
> Hello,
>         I have been trying to figure out
> how to do problem #7, but i do not even know
> how to begin. Could you give me a hint
> on how to start the problem.
> 
> thank you,
> Javier

From ecoder@MIT.EDU  Tue Apr  7 07:36:56 1998
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Date: Tue, 07 Apr 1998 11:36:56 -0400
To: 6042-help@theory.lcs.mit.edu
From: Eugene Vaynshteyn <ecoder@MIT.EDU>
Subject: PS7, questions 7 and 8
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Hi,
I know that this is extremely late notice, but if someone could reply
before lecture with any hints on questions 7 and 8, I would really
appreciate it. I did the rest of the problem set with very few problems,
but I am totally clueless on these two.

Thanks,
Eugene

From meyer@theory.lcs.mit.edu  Tue Apr  7 08:12:11 1998
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In-Reply-To: <3.0.32.19980407113654.00859e20@po7.mit.edu> (message from Eugene
	Vaynshteyn on Tue, 07 Apr 1998 11:36:56 -0400)
Subject: Re: PS7, questions 7 and 8
Reply-To: 6042-meyer@theory.lcs.mit.edu

For prob 7, initially ignore the disjointness condition.  Then use
pigeonholing.  That's all I have time to write now.
Regards, A.

From flattop@MIT.EDU  Sat Apr 11 07:59:00 1998
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This message of primarily for the course assistants.

During meeting last Thursday with Prof. Meyer, he decided to have only
three hours of online help on Monday night.  I went ahead and updated
the web page and stated that the online help session will be from 8pm to
11pm monday night.  So who wants to do which hour?

For convience sake, it will be a first come fist serve basis, so please
e-mail to this mailing list.  If all the hours are not taken Sunday
night, I will man the left over hours.

thanks

jack

From ssadoway@MIT.EDU  Sun Apr 12 21:10:56 1998
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Date: Mon, 13 Apr 1998 01:10:56 -0400
To: 6042-help@theory.lcs.mit.edu
From: Steve *Silent Bob* Sadoway <ssadoway@MIT.EDU>
Subject: Pset 8, Problem 4c
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A quick question... it asks for the 17th coefficient...  is this assuming
the first one listed is the zero-th coefficient?  I'm getting a sequence
that looks something like <0, -8, 0 -32, 0, ...>  Is that first 0 the
zero-th coefficient?  Is it the first coefficient, or is the -8 the 1st
coefficient and the -32 the 2nd coefficient?  Maybe it's just too late for
me right now, but I just wanted to clear that up.  Thanks!

  -->Steve


~~~~~~~~~~~~~~~~~~~~~~~~~Steven Sadoway~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
E-mail: ssadoway@mit.edu  |  Homepage: http://web.mit.edu/ssadoway/www/
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
"We were talking 'bout something, seems like was funny, then Steven got 
quiet -  I think Steven was mad.  Maybe he wasn't mad, but we felt very
strange, in the moment, but the moment was passed and forgotten about."
                        --Ben Folds Five, "Steven's Last Night In Town"
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

From meyer@theory.lcs.mit.edu  Mon Apr 13 04:59:20 1998
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From: "Albert R. Meyer" <meyer@theory.lcs.mit.edu>
To: ssadoway@MIT.EDU
In-Reply-To: <3.0.2.32.19980413011056.008136a0@hesiod> (message from Steve
	*Silent Bob* Sadoway on Mon, 13 Apr 1998 01:10:56 -0400)
Subject: Re: Pset 8, Problem 4c
Reply-To: 6042-meyer@theory.lcs.mit.edu
Cc: 6042-help

your choice to start w/ 0 or 1, but say which.
Regards, A.

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   Date: Mon, 13 Apr 1998 01:10:56 -0400
   From: Steve *Silent Bob* Sadoway <ssadoway@MIT.EDU>

   A quick question... it asks for the 17th coefficient...  is this assuming
   the first one listed is the zero-th coefficient?  I'm getting a sequence
   that looks something like <0, -8, 0 -32, 0, ...>  Is that first 0 the
   zero-th coefficient?  Is it the first coefficient, or is the -8 the 1st
   coefficient and the -32 the 2nd coefficient?  Maybe it's just too late for
   me right now, but I just wanted to clear that up.  Thanks!

     -->Steve


   ~~~~~~~~~~~~~~~~~~~~~~~~~Steven Sadoway~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
   E-mail: ssadoway@mit.edu  |  Homepage: http://web.mit.edu/ssadoway/www/
   ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
   "We were talking 'bout something, seems like was funny, then Steven got 
   quiet -  I think Steven was mad.  Maybe he wasn't mad, but we felt very
   strange, in the moment, but the moment was passed and forgotten about."
                           --Ben Folds Five, "Steven's Last Night In Town"
   ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

From jslopez@MIT.EDU  Mon Apr 13 13:51:13 1998
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From: =?iso-8859-1?Q?=22Javier_S._L=F3pez=22_=3Cjslopez=40mit.edu=3E?=@MIT.EDU
Subject: Problem 4c,d

Hello, 
        I do not undertsand
this question. Could you tell 
me what are they asking for?

Thank you,
Javier


From wchien@MIT.EDU  Mon Apr 13 16:20:40 1998
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To: jslopez@MIT.EDU
Cc: 6042-help@theory.lcs.mit.edu
Subject: Re: Problem 4c,d 
In-Reply-To: Your message of "Mon, 13 Apr 1998 17:51:13 EDT."
             <2.2.32.19980413215113.006a4dbc@po10.mit.edu> 
Date: Mon, 13 Apr 1998 20:20:40 EDT
From: Wendy S Chien <wchien@MIT.EDU>


> Hello, 
>         I do not undertsand
> this question. Could you tell 
> me what are they asking for?
 
> Thank you,
> Javier


	Part (a) and (b)  of problem 4 have you write the partial fraction
decomposition of the functions given.  In that form you will see that
they look like the sum of a sequence.  Once you change this into
polynomial form, you will be able to read off the coefficients that the
question is asking for.  Last term's Lecture 17 on OGF's do a problem 
very similar to this that you can see as an example.  

Hope this helps.  

Wendy

From ecoder@MIT.EDU  Mon Apr 13 18:46:05 1998
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To: 6.042-help@theory.lcs
From: Eugene Vaynshteyn <ecoder@MIT.EDU>
Subject: PS8, problem 3
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Hi!
In problem 3 on the problem set, are we required to find a closed form for
the ogf?
e.g., for (a) can we just say:
<1,1,1,1,1,...>   <-->  1+x+x^2+x^3+...
or do we need to say  1/(1-x)  ?

Thanks,
Eugene

From wchien@MIT.EDU  Mon Apr 13 18:59:45 1998
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To: Eugene Vaynshteyn <ecoder@MIT.EDU>
Cc: 6042-help@theory.lcs.mit.edu
Subject: Re: PS8, problem 3 
In-Reply-To: Your message of "Mon, 13 Apr 1998 22:46:05 EDT."
             <3.0.32.19980413224605.008c0150@po7.mit.edu> 
Date: Mon, 13 Apr 1998 22:59:45 EDT
From: Wendy S Chien <wchien@MIT.EDU>



> Hi!
> In problem 3 on the problem set, are we required to find a closed form for
> the ogf?
> e.g., for (a) can we just say:
> <1,1,1,1,1,...>   <-->  1+x+x^2+x^3+...
> or do we need to say  1/(1-x)  ?
 
> Thanks,
> Eugene


Hi Eugene,

You should find the closed form solution.

Wendy

From jjkim@MIT.EDU  Mon Apr 13 21:39:52 1998
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Date: Tue, 14 Apr 1998 01:39:52 -0400
To: 6042-help@theory.lcs.mit.edu
From: Janice Kim <jjkim@MIT.EDU>
Subject: Pset8, prob 6

hello....
I was wondering, for this problem, are we supposed to take a, b, c, d, e as
having it's own restrictions? or is this problem a combination of
restrictions from a..e 

for example, does each a<k> occur an even number of times AND a multiple of
five times AND (c.) AND (d.) AND (e.)?

or

for (a.) each a<k> occur as even number of times
for (b.) each a<k> occurs a multiple of 5 times, but not each a<k> occur as
even number of times.
?

sorry, if this is confusing... I don't know if I stated my questions
correctly...
thanks anyway!

-janice
 -------------------------------------------------------
  Janice Juyeon Kim
  410 Memorial Drive
  Cambridge, MA 02139
  
  e-mail : jjkim@mit.edu
  web    : http://www.mit.edu/people/jjkim/Welcome.html
 -------------------------------------------------------


From ecoder@MIT.EDU  Tue Apr 14 00:13:46 1998
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Date: Tue, 14 Apr 1998 04:13:46 -0400
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From: Eugene Vaynshteyn <ecoder@MIT.EDU>
Subject: PS8 questions
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Hi,
If someone could reply before lecture tomorrow (Tues) about these
questions, I would really appreciate it:

Problem 3:
I did parts a-g just fine, but I don't know how to generalize h, or even
how to approach i-l. Mainly, I think I'm having problems going from the
generating function to the actual sequence it represents, as we have to do
in i-l.

Problem 5:
I solved it, but I don't know how to use induction on it. Once again, this
is because I don't know how to go from the gen. function to the sequence...

Problem 6:
No idea. What is it saying? Did we cover this stuff?

Thanks a lot,
Eugene

From mroh@MIT.EDU  Tue Apr 14 06:52:01 1998
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To: Janice Kim <jjkim@MIT.EDU>
Cc: 6042-help@theory.lcs
Subject: Re: Pset8, prob 6 
In-Reply-To: Your message of "Tue, 14 Apr 1998 01:39:52 EDT."
             <2.2.32.19980414053952.00674df0@po7.mit.edu> 
Date: Tue, 14 Apr 1998 10:52:01 EDT


Janice, you should treat each part of problem 6 independently. For
example, valid values for a_k in part a are 0,2,4,6,8...  Valid values
for a_k in part b are 0,5,10,15,20,...  The only valid value for a_1
in part c is 0, etc.

Mark

-----------
Mark Roh, mroh@mit.edu
(617) 497-4876



From ssadoway@MIT.EDU  Sat Apr 25 13:49:21 1998
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Date: Sat, 25 Apr 1998 17:49:21 -0400
To: 6042-help@theory.lcs.mit.edu
From: Steve *Silent Bob* Sadoway <ssadoway@MIT.EDU>
Subject: Recitation notes, please!
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Hi, I'm trying to work on the problem set, but the notes from yesterday's
tutorial aren't up on the web yet...  Could somebody post them?  Please?
:)  I don't know whose job it is to update the web page... sorry if I'm
emailing this list in error.  Thanks!

  -->Steve


~~~~~~~~~~~~~~~~~~~~~~~~~Steven Sadoway~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
E-mail: ssadoway@mit.edu  |  Homepage: http://web.mit.edu/ssadoway/www/
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
"We were talking 'bout something, seems like was funny, then Steven got 
quiet -  I think Steven was mad.  Maybe he wasn't mad, but we felt very
strange, in the moment, but the moment was passed and forgotten about."
                        --Ben Folds Five, "Steven's Last Night In Town"
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

From luca@theory.lcs.mit.edu  Sat Apr 25 14:14:43 1998
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To: Steve *Silent Bob* Sadoway <ssadoway@MIT.EDU>
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Steve *Silent Bob* Sadoway wrote:
> 
> Hi, I'm trying to work on the problem set, but the notes from yesterday's
> tutorial aren't up on the web yet...  Could somebody post them?  Please?
> :)  I don't know whose job it is to update the web page... sorry if I'm
> emailing this list in error.  Thanks!
> 
>   -->Steve

Hi Steve,

we normally put handouts online the same day they are
distributed, which in this case would have been next monday.

given your request, i just posted the tutorial notes now.

Best
-Luca

From brianlin@MIT.EDU  Sun Apr 26 17:24:43 1998
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Date: Sun, 26 Apr 1998 21:24:43 -0400
To: 6042-help@theory.lcs.mit.edu
From: Li-Kuo Lin <brianlin@MIT.EDU>
Subject: 
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Hi,

   I have a question concerning #3 on the pset...
when it says, maximum 'k', does it mean that all of the 6 #s chosen are
<=k, or that one of the 6 #s is k, and the
other chosen 5 are less than k?

-Brian
----------------------------------------------------------------------------
------------------
                            / 		Li-Kuo (Brian) Lin
	 \                     /  /		410 Memorial Drive, Apt. 254F
      \ \ \'  ,           /  / / 		Cambridge MA, 02139
       \ \ \ / /,      _/  / / ,		(617)-225-8265
        \ _ -/ / '   /    / / <,	brianlin@mit.edu
            \   / / /    </ / ` 
                /   >>   \ \ \` __/_
               /, ) -^>>  _\`  \ \ \
               ( /     \ \    / /\ \ 
                       / /  _/ / \ \ \ \
                     ( ( `  ( (

"To laugh often and much, to win the respect of intelligent people and the
affection of children, to earn the appreciation of honest critics and 
endure the betrayal of false friends, to appreciate beauty, to find the 
best in others, to leave the world a bit better, whether by a healthy 
child, a garden patch, or a redeemed social condition; to know even one 
life has breathed easier because you have lived. This is to have succeeded!" 
--Ralph Waldo Emerson



From meyer@theory.lcs.mit.edu  Sun Apr 26 18:24:31 1998
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From: "Albert R. Meyer" <meyer@theory.lcs.mit.edu>
To: brianlin@MIT.EDU
Cc: 6042-help@theory.lcs.mit.edu
In-Reply-To: <9804270124.AA00779@MIT.MIT.EDU> (message from Li-Kuo Lin on Sun,
	26 Apr 1998 21:24:43 -0400)
Subject: Re: 
Reply-To: 6042-meyer@theory.lcs.mit.edu

The maximum of the set of six numbers is defined to be the largest of
them, so your second interpretation is the correct one.

Regards, A. 

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   Date: Sun, 26 Apr 1998 21:24:43 -0400
   From: Li-Kuo Lin <brianlin@MIT.EDU>

   Hi,

      I have a question concerning #3 on the pset...
   when it says, maximum 'k', does it mean that all of the 6 #s chosen are
   <=k, or that one of the 6 #s is k, and the
   other chosen 5 are less than k?

   -Brian
   ----------------------------------------------------------------------------
   ------------------
                               / 		Li-Kuo (Brian) Lin
            \                     /  /		410 Memorial Drive, Apt. 254F
         \ \ \'  ,           /  / / 		Cambridge MA, 02139
          \ \ \ / /,      _/  / / ,		(617)-225-8265
           \ _ -/ / '   /    / / <,	brianlin@mit.edu
               \   / / /    </ / ` 
                   /   >>   \ \ \` __/_
                  /, ) -^>>  _\`  \ \ \
                  ( /     \ \    / /\ \ 
                          / /  _/ / \ \ \ \
                        ( ( `  ( (

   "To laugh often and much, to win the respect of intelligent people and the
   affection of children, to earn the appreciation of honest critics and 
   endure the betrayal of false friends, to appreciate beauty, to find the 
   best in others, to leave the world a bit better, whether by a healthy 
   child, a garden patch, or a redeemed social condition; to know even one 
   life has breathed easier because you have lived. This is to have succeeded!" 
   --Ralph Waldo Emerson

From flattop@MIT.EDU  Sun Apr 26 18:42:59 1998
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From: "Jack V. Chung" <flattop@MIT.EDU>
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To: Li-Kuo Lin <brianlin@MIT.EDU>
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Subject: Re:  PS9 #3
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Hey,

Let me try to explain the problem again.  You pick 6 numbers of the 45. 
All 6 of these numbers are different and less then 45.  

So k is the maximum of the 6 numbers chosen. 

Hope this is useful.

jack


Li-Kuo Lin wrote:
> 
> Hi,
> 
>    I have a question concerning #3 on the pset...
> when it says, maximum 'k', does it mean that all of the 6 #s chosen are
> <=k, or that one of the 6 #s is k, and the
> other chosen 5 are less than k?
> 
> -Brian

From joycelin@MIT.EDU  Sun Apr 26 20:48:07 1998
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Date: Mon, 27 Apr 1998 00:48:07 -0400
To: 6042-help@theory.lcs.mit.edu
From: Joyce Lin <joycelin@MIT.EDU>
Subject: 

Hi,
 
  I have a question regarding #4....can the following scenario exist in
the problem? 
Could the probability of a component failing be dependent on the success
of other components? If the are, take this scenario:
The probability that a component fails given that a component succeeds is
equal to 1. Therefore, the probability of the system failing becomes 1, which
is above the upper bound of 1/10 ..and we can't prove that 1/10 is an upper
bound because of this counterexample.



From cynic@mit.edu  Sun Apr 26 21:01:44 1998
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To: Joyce Lin <joycelin@MIT.EDU>
Cc: 6042-help@theory.lcs.mit.edu
Subject: Re: 
In-Reply-To: Your message of "Mon, 27 Apr 1998 00:48:07 EDT."
             <2.2.32.19980427044807.006fdb80@po9.mit.edu> 
Date: Mon, 27 Apr 1998 01:01:44 EDT

>  I have a question regarding #4....can the following scenario exist in
>the problem? 
>Could the probability of a component failing be dependent on the success
>of other components? If the are, take this scenario:

Yes, this scenario can indeed exist, in a way. However, the counterexample you
provide is not valid, and here's why:

>The probability that a component fails given that a component succeeds is
>equal to 1. Therefore, the probability of the system failing becomes 1, which

(This part is a nuance:)
Yes, but you don't know that any given component's probability of success
is 1, so while the probability of a component failing given that the component
it is dependent on succeeds is indeed 1, the probability of that component 
failing, period, is the probability of the other component succeeding, which 
is no less than 1- 1/10000. 

So what, you say, 9999/10000 is still a lot bigger than our supposed upper
bound of 1/10. Well, I did say it was a nuance. The real reason why the
counterexample is invalid is because it states in the problem that each
component is known to fail with probability AT MOST 1/10000. Thus, if a 
component fails every time another component succeeds, it fails with 
probability at least 1-1/10000, which violates the above condition.

The reason I say a component's probability of failure can depend on another
component's probability of success (in a way) is that the component's
probability of failure can be affected by the probability of the other 
component's probability of failure, which is just the opposite of success. :)

Hope this helps..if you have any more difficulty with problem 4, feel free to
ask the help line some more.




From kylee@mit.edu  Sun Apr 26 22:37:27 1998
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From: Edmond Kayi Lee <kylee@MIT.EDU>
To: Joyce Lin <joycelin@MIT.EDU>
Cc: 6042-help@theory.lcs.mit.edu
Subject: Re: 
In-Reply-To: Your message of "Mon, 27 Apr 1998 00:48:07 EDT."
             <2.2.32.19980427044807.006fdb80@po9.mit.edu> 

Hi Joyce,

	Your scenerio does not satisfy the condition given in the question.

Let A_i be the event that component i does not fail. We denote ~A_i to be 
"Not A_i".  So we have P(~A_i)<=1/1000. 

Without loss of generality assume your scenerio says P(~A_1|A_2)=1. 

P(~A_1) = P(~A_1|A_2)P(A_2)+P(~A_1|A_3)P(A_3)+many other terms
       >= P(~A_1|A_2)P(A_2)
       >= 1*999/1000

This does not satisfy our condition. So your scenerio does not really make
a contradiction.


Edmond

From wchien@MIT.EDU  Tue May 19 14:17:46 1998
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To: 6042-help@theory.lcs.mit.edu
Subject: help line hours
Date: Tue, 19 May 1998 18:17:46 EDT
From: Wendy S Chien <wchien@MIT.EDU>


I am sorry, but it looks like I won't have time to man the help line for
a specific block of time.  I will try to log in every now and then
though on Thursday to check for any questions.  

Wendy

From 851977@uCCTJq.com  Sat Aug 15 14:13:34 1998
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