From meyer@imap.theory.csail.mit.edu  Wed Sep 21 23:14:32 2005
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I found it interesting that the three proof methods: induction, strong 
induction, and the well ordering principle, can be used to prove the same 
theorems. I would like to understand why this is so. The equivalence 
between induction and strong induction is relatively simple, but I wouldn´t 
know how to prove that the well ordering principle can be used in place of 
the other methods.

Sergio Bacallado
Group 1



From meyer@imap.theory.csail.mit.edu  Wed Sep 21 23:17:33 2005
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I found the well ordered proof interesting, because we've been using it so 
much without even thinking about it. Even though it seems useless, it does 
have an important purpose.

Jehan


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X-Keywords: NonJunk                                                                                                    

Week 3, Section 4: The Well Ordering Principle

p.12:

"Well Ordering proofs typically involve proof by contradiction, so using it is
not always the best approach."

Are there proofs that can be done only by contradiction and not induction? (Or
not as easily.)



From meyer@imap.theory.csail.mit.edu  Wed Sep 21 23:57:37 2005
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I completely understand everything in this week's readings, although I had to
reread the false horse proof (section 2.5) before I really got how we were
trying to prove it. It occured to me that if you take any set of elements for
whom any pair of elements share a certain trait, then every element in that set
must have that trait. Is this called by any certain name? It seems obvious, but
so does the Well Ordering Principle.
Also, I look forward to learning the difference between choosability and
colorability. And I found "The country Inductia, whose unit of currency is the
Strong" to be hilariously unimaginative. Keep up the good work.

Neil Dowgun

From meyer@imap.theory.csail.mit.edu  Thu Sep 22 01:10:28 2005
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I woul like the proof of product of primes explained again in class.

From meyer@imap.theory.csail.mit.edu  Thu Sep 22 02:17:49 2005
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X-Keywords: NonJunk                                                                                                    

I found the passage on the well ordering principle to be the most  
surprising because i dont see how such a simple principle can be used  
to provide proofs that are shorter than using proof by induction.

Hamidou Soumare

From meyer@imap.theory.csail.mit.edu  Thu Sep 22 02:28:43 2005
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Reading comments for this week on induction reading:
  The thing that I found hardest in this weeks reading were the concepts of
strong induction, presented on pages 9 and 10, and the product of primes proof
on page 10.  I would appreciate going over the definition of strong induction
and this proof in class.
-Dave

From meyer@imap.theory.csail.mit.edu  Thu Sep 22 10:28:42 2005
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From: Harrison King Hall <hkhall@MIT.EDU>
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X-Keywords: NonJunk                                                                                                    

After reading the notes I still can't differentiate readily between 
when or how to use induction and strong induction.  I can tell you what 
the difference is, but the application of each is baffling to me.  
Further I can't figure out when there is an error in the logic of an 
induction proof, some added time on that would be very beneficial.
-Harrison Hall


From meyer@imap.theory.csail.mit.edu  Wed Sep 21 17:37:07 2005
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No, I don't think it would "make it more clear": it's better illustrated 
with examples.  Let me know if you still disagree after Friday lecture.

Regards, A

Akari Kameyama wrote:
>  In other words, any theorem that can be proved with strong induction 
> could also be proved with ordinary 
> induction (using a slightly more complicated indcution hypothesis).  
>  -page 9
> 
> An example of proving the same thing with ordinary then strong (or vice 
> versa) would help to make it more clear how one can be better than the 
> other.
> --Apple-Ma


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X-Keywords: NonJunk                                                                                                    


--Apple-Mail-1-799499547
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  In other words, any theorem that can be proved with strong  
induction could also be proved with ordinary
induction (using a slightly more complicated indcution hypothesis).    
-page 9

An example of proving the same thing with ordinary then strong (or  
vice versa) would help to make it more clear how one can be better  
than the other.
--Apple-Mail-1-799499547
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	charset=ISO-8859-1

<HTML><BODY style=3D"word-wrap: break-word; -khtml-nbsp-mode: space; =
-khtml-line-break: after-white-space; "><DIV style=3D"margin-top: 0px; =
margin-right: 0px; margin-bottom: 0px; margin-left: 0px; "><FONT =
class=3D"Apple-style-span" size=3D"3"><SPAN class=3D"Apple-style-span" =
style=3D"font-size: 11px;">=A0</SPAN></FONT><FONT =
class=3D"Apple-style-span" size=3D"3"><SPAN class=3D"Apple-style-span" =
style=3D"font-size: 11px;">In other</SPAN></FONT><FONT =
class=3D"Apple-style-span" size=3D"3"><SPAN class=3D"Apple-style-span" =
style=3D"font-size: 11px;">=A0</SPAN></FONT><FONT =
class=3D"Apple-style-span" size=3D"3"><SPAN class=3D"Apple-style-span" =
style=3D"font-size: 11px;">words, any theorem that can be proved with =
strong induction could also be proved with ordinary</SPAN></FONT><FONT =
class=3D"Apple-style-span" size=3D"3"><SPAN class=3D"Apple-style-span" =
style=3D"font-size: 11px;">=A0</SPAN></FONT></DIV><DIV =
style=3D"margin-top: 0px; margin-right: 0px; margin-bottom: 0px; =
margin-left: 0px; "><FONT class=3D"Apple-style-span" size=3D"3"><SPAN =
class=3D"Apple-style-span" style=3D"font-size: 11px;">induction (using a =
slightly more complicated indcution hypothesis).</SPAN></FONT><FONT =
class=3D"Apple-style-span" size=3D"3"><SPAN class=3D"Apple-style-span" =
style=3D"font-size: 11px;">=A0 =A0-page 9</SPAN></FONT></DIV><DIV =
style=3D"margin-top: 0px; margin-right: 0px; margin-bottom: 0px; =
margin-left: 0px; "><FONT class=3D"Apple-style-span" size=3D"3"><SPAN =
class=3D"Apple-style-span" style=3D"font-size: 11px;"><BR =
class=3D"khtml-block-placeholder"></SPAN></FONT></DIV><DIV =
style=3D"margin-top: 0px; margin-right: 0px; margin-bottom: 0px; =
margin-left: 0px; "><FONT class=3D"Apple-style-span" size=3D"3"><SPAN =
class=3D"Apple-style-span" style=3D"font-size: 11px;">An example of =
proving the same thing with ordinary then strong (or vice versa) would =
help to make it more clear how one can be better than the =
other.</SPAN></FONT></DIV></BODY></HTML>=

--Apple-Ma
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Any further comment now you've seen one?
regards, A.

Amanda Seybold wrote:
> I would like to hear more about these other induction hypotheses 
> mentioned on page 7.

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I'm confused on how the Well Ordering Principle (pg. 12) is actually 
useful. I get the idea, but what do I use it with?

-chris wong


From meyer@imap.theory.csail.mit.edu  Wed Sep 21 19:47:54 2005
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X-Keywords: NonJunk                                                                                                    

I find the concept of strong induction to still be confusing. From  
what I've gathered, it's simply an induction proof that has more  
assumptions.

From meyer@imap.theory.csail.mit.edu  Wed Sep 21 22:00:54 2005
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yes that's right; so what's confusing you?
regards, A.

Sheldon Chan wrote:

> I find the concept of strong induction to still be confusing. From  
> what I've gathered, it's simply an induction proof that has more  
> assumptions.


From meyer@imap.theory.csail.mit.edu  Wed Sep 21 21:59:56 2005
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wait till lecture& class probs on fri for some more examples.  ask me or 
your TA again after if that's not enough.

regards, A.

Chris Wong wrote:

> I'm confused on how the Well Ordering Principle (pg. 12) is actually 
> useful. I get the idea, but what do I use it with?
>
> -chris wong
>

From meyer@imap.theory.csail.mit.edu  Wed Sep 21 22:13:49 2005
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Perhaps its simply an expectation that the "strong" in the name implies
that it should be more direct and supportive evidence in the proof.
It makes sense making assumptions allows us to more easily prove
something, but counterintuitive in producing a sound proof, since it could
leave more room for faulty assumptions. I think it would be good if
there were more examples or a clarification of the criteria for such
assumptions made in a strong induction proof.

Thanks,

Sheldon

On Wed, 21 Sep 2005, Prof. Albert R. Meyer wrote:

> yes that's right; so what's confusing you?
> regards, A.
>
> Sheldon Chan wrote:
>
> > I find the concept of strong induction to still be confusing. From
> > what I've gathered, it's simply an induction proof that has more
> > assumptions.
>
>


From meyer@imap.theory.csail.mit.edu  Thu Sep 22 01:32:35 2005
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Compare the two induction rules, leaving aside the base cases:

Regular induction:
[P(n) => P(n+1) ] => \forall n P(n)

Strong induction:
[P(1),...,P(n) => P(n+1)] => \forall n P(n)

Now the antecedent of the implication inside the [ ]'s is stronger for 
strong induction, making the [ ] implication itself weaker, right ?
Therefore, if you look at the overall statement, the antecedent of the 
strong induction principle is weaker, and so, the strong induction as a rule
(the outer implication) is stronger. Makes sense ?

-Sayan

> Sheldon Chan wrote:
>
>> I find the concept of strong induction to still be confusing. From  
>> what I've gathered, it's simply an induction proof that has more  
>> assumptions.
>


From meyer@imap.theory.csail.mit.edu  Thu Sep 22 10:37:54 2005
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Yes, could use simple induction to PROVE that P(0),...,P(n) hold if you've
proved P(0) and P(k) ==> P(k+1) for all k <n.  But simple induction doesn't
say this explicitly, and if you wanted to use only simple induction, you'd
need to clog up your proof either with the subproof by simple induction
about P(0)...P(n), or else you would have to cite your Lemma, which you
would naturally have called your Strong Induction Lemma :-), which 
asserted it was
ok to assume them all.
 
To avoid this, we simply identify and name Strong Induction as a sound
proof method.
 
Make sense?
 
Regards, A.  
 
 
Arup Sarma wrote:
 
 > Section 3, page 10:
 > I found this difficult to understand, because I'm still not sure what 
the difference between simple and strong induction is.  Doesn't simple 
induction imply that P(0), P(1), ..., P(n) are true as well?
 >
 > |Arup|
 >



From meyer@imap.theory.csail.mit.edu  Thu Sep 22 10:41:10 2005
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not sure what kind of further "clarification" you're looking for, but 
you'll see several more examples Friday.  Let me know if you're not 
satisfied after you've seen them.

regards, A.

Sheldon Chan wrote:

>Perhaps its simply an expectation that the "strong" in the name implies
>that it should be more direct and supportive evidence in the proof.
>It makes sense making assumptions allows us to more easily prove
>something, but counterintuitive in producing a sound proof, since it could
>leave more room for faulty assumptions. I think it would be good if
>there were more examples or a clarification of the criteria for such
>assumptions made in a strong induction proof.
>
>Thanks,
>
>Sheldon
>
>On Wed, 21 Sep 2005, Prof. Albert R. Meyer wrote:
>
>  
>
>>yes that's right; so what's confusing you?
>>regards, A.
>>
>>Sheldon Chan wrote:
>>
>>    
>>
>>>I find the concept of strong induction to still be confusing. From
>>>what I've gathered, it's simply an induction proof that has more
>>>assumptions.
>>>      
>>>
>>    
>>
>
>  
>


From meyer@imap.theory.csail.mit.edu  Thu Sep 22 11:00:30 2005
Message-ID: <4332C711.2000700@csail.mit.edu>
Date: Thu, 22 Sep 2005 11:00:33 -0400
From: "Prof. Albert R. Meyer" <meyer@csail.mit.edu>
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Subject: Re: Email comments for reading
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we used to teach this, and students found it more confusing than 
helpful.  Since it's not important, except foundationally, I now leave 
out the details.
If you're really curious, I can sketch it for you after class some time.

regards, A.

Katherine A Romer wrote:

>"...there's a routine way to transform any proof using the Well Ordering
>Principle into a proof using Strong Induction, and vice-versa." (p.11)
>I'd like to see an example in lecture of how one of the theorems we've proved
>using induction could be proved using the Well Ordering Principle--I'm having a
>hard time seeing how this might be done.
>
>Katherine Romer
>  
>


From meyer@imap.theory.csail.mit.edu  Thu Sep 22 10:38:44 2005
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"...there's a routine way to transform any proof using the Well Ordering
Principle into a proof using Strong Induction, and vice-versa." (p.11)
I'd like to see an example in lecture of how one of the theorems we've proved
using induction could be proved using the Well Ordering Principle--I'm having a
hard time seeing how this might be done.

Katherine Romer

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I would like to hear more about these other induction hypotheses 
mentioned on page 7.

From meyer@imap.theory.csail.mit.edu  Wed Sep 21 17:38:52 2005
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No, I don't think it would "make it more clear": I think it's better 
illustrated with examples.  Let me know if you still disagree after 
Friday lecture.

Regards, A

Akari Kameyama wrote:
>  In other words, any theorem that can be proved with strong induction 
> could also be proved with ordinary 
> induction (using a slightly more complicated indcution hypothesis).  
>  -page 9
> 
> An example of proving the same thing with ordinary then strong (or vice 
> versa) would help to make it more clear how one can be better than the 
> other.
> --Apple-Ma



From meyer@imap.theory.csail.mit.edu  Thu Sep 22 05:45:33 2005
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I'm a bit confused about the difference between simple induction and strong 
induction. I'm not sure how the proof of Lemma 3.1 on page 10 qualifies as 
strong induction rather than simple.

--Chieu 


From meyer@imap.theory.csail.mit.edu  Thu Sep 22 02:54:49 2005
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Section 3, page 10:
I found this difficult to understand, because I'm still not sure what 
the difference between simple and strong induction is.  Doesn't 
simple induction imply that P(0), P(1), ..., P(n) are true as well?

|Arup|


From meyer@imap.theory.csail.mit.edu  Thu Sep 22 11:16:04 2005
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we used to teach this, and students found it more confusing than 
helpful.  Since it's not important, except foundationally, I now leave 
out the details.
If you're really curious, I can sketch it for you after class some time.

regards, A.

Sergio Bacallado wrote:

> I found it interesting that the three proof methods: induction, strong 
> induction, and the well ordering principle, can be used to prove the 
> same theorems. I would like to understand why this is so. The 
> equivalence between induction and strong induction is relatively 
> simple, but I wouldn´t know how to prove that the well ordering 
> principle can be used in place of the other methods.
>
> Sergio Bacallado
> Group 1
>
>


From meyer@imap.theory.csail.mit.edu  Thu Sep 22 13:55:55 2005
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If you're still feeling shaky about using and/or debugging induction 
proofs, I suggest you take it up in office hours with your TA at the 
next opportunity.

regards, A.

Harrison King Hall wrote:
> After reading the notes I still can't differentiate readily between when 
> or how to use induction and strong induction.  I can tell you what the 
> difference is, but the application of each is baffling to me.  Further I 
> can't figure out when there is an error in the logic of an induction 
> proof, some added time on that would be very beneficial.
> -Harrison Hall
> 


From meyer@imap.theory.csail.mit.edu  Thu Sep 22 14:28:49 2005
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"2.5 A Faulty Induction Proof

False Theorem. All horses are the same color.
Notice that no n is mentioned in this assertion, so we're going to 
have to reformulate it in a way
that makes an n explicit. In particular, we'll (falsely) prove that

False Theorem 2.4. In every set of n  1 horses, all are the same color.
This a statement about all integers n  1 rather  0, so it's natural 
to use a slight variation on
induction: prove P(1) in the base case and then prove that P(n) 
implies P(n + 1) for all n  1 in
the inductive step. This is a perfectly valid variant of induction 
and is not the problem with the
proof below."

I would like to see more mathematical faulty inductions and see why 
certain assertions by induction are false; I didn't think the "horse 
theorems" were good examples.



From meyer@imap.theory.csail.mit.edu  Thu Sep 22 15:33:11 2005
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I thought the reading was interesting, but there was one portion that was a
little confusing.  On page 5, the paragraph under equation (3) does the
equivalent of a lot of fast talk and hand-waving, and while if you go through
it it is most certainly correct, if one or two steps were actually written out
it would have helped.

-Paul Groudas

From meyer@imap.theory.csail.mit.edu  Thu Sep 22 15:38:17 2005
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I have a question about the horse color problem.

What if you start with the base case of n=2?  Can you from there begin the 
same logic and show that all horses are again the same color?  What would be 
the problem in this proof?

-Andrew
----------------------------
Illegitmitatum Non Carborundum Est
Andrew Shafer, MIT Blog
http://shaferandrew.blogspot.com
Si hoc legere scis numium eruditionis habes.
----------------------------


From meyer@imap.theory.csail.mit.edu  Thu Sep 22 16:03:49 2005
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On page 10, the comment that strong induction is not more powerful than
weak induction is surprising. There is a conflict between logic, which
says that every true statement is provable in infinitely many ways, and
intuition, which demands One True Proof.

-Ben

From meyer@imap.theory.csail.mit.edu  Thu Sep 22 16:18:07 2005
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you'll see quite a few more false proofs, including by induction,as the 
term progresses.  But why was the "horses" example not good?

Regards, A.

Kamil Sindi wrote:

> "2.5 A Faulty Induction Proof
>
> False Theorem. All horses are the same color.
> Notice that no n is mentioned in this assertion, so we're going to 
> have to reformulate it in a way
> that makes an n explicit. In particular, we'll (falsely) prove that
>
> False Theorem 2.4. In every set of n  1 horses, all are the same color.
> This a statement about all integers n  1 rather  0, so it's natural to 
> use a slight variation on
> induction: prove P(1) in the base case and then prove that P(n) 
> implies P(n + 1) for all n  1 in
> the inductive step. This is a perfectly valid variant of induction and 
> is not the problem with the
> proof below."
>
> I would like to see more mathematical faulty inductions and see why 
> certain assertions by induction are false; I didn't think the "horse 
> theorems" were good examples.
>
>
> From - Thu



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Great question!

The answer is, there is nothing wrong with the proof!  But think about 
what that proves:

"IF any set of 2 horses is the same color, THEN all horses are the same 
color."

Since the IF part is false, the statement as a whole is vacuously true, 
regardless of what comes in the THEN part.

Andrew Shafer wrote:

> I have a question about the horse color problem.
>
> What if you start with the base case of n=2?  Can you from there begin 
> the same logic and show that all horses are again the same color?  
> What would be the problem in this proof?
>
> -Andrew
> ----------------------------
> Illegitmitatum Non Carborundum Est
> Andrew Shafer, MIT Blog
> http://shaferandrew.blogspot.com
> Si hoc legere scis numium eruditionis habes.
> ----------------------------
>


From meyer@imap.theory.csail.mit.edu  Thu Sep 22 14:40:47 2005
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To: Harrison King Hall <hkhall@mit.edu>
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If you're still feeling shaky about using and/or debugging induction 
proofs, I suggest you take it up in office hours with your TA at the 
next opportunity.

regards, A.

Harrison King Hall wrote:
> After reading the notes I still can't differentiate readily between when 
> or how to use induction and strong induction.  I can tell you what the 
> difference is, but the application of each is baffling to me.  Further I 
> can't figure out when there is an error in the logic of an induction 
> proof, some added time on that would be very beneficial.
> -Harrison Hall
> 

From meyer@imap.theory.csail.mit.edu  Thu Sep 22 15:54:39 2005
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Did you think they weren't good examples because the flaws were too 
obvious?  If so, I think you're in great shape - that means you have a 
good grasp of induction.  If it was something else, please let us know 
it was about the examples that bothered you.

DS

> I would like to see more mathematical faulty inductions and see why 
> certain assertions by induction are false; I didn't think the "horse 
> theorems" were good examples.


From meyer@imap.theory.csail.mit.edu  Thu Sep 22 16:22:28 2005
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 <4331D1D6.1080403@csail.mit.edu>
Date: Thu, 22 Sep 2005 16:21:24 -0400
To: "Albert R. Meyer" <meyer@csail.mit.edu>
From: Amanda Seybold <vixen@MIT.EDU>
Subject: Re: week 3 Notes, p.7
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It would be nice to see more?  Perhaps ones with more than one 
variable, so one has to figure out what to assign n to.

>Any further comment now you've seen one?
>regards, A.
>
>Amanda Seybold wrote:
>>I would like to hear more about these other induction hypotheses 
>>mentioned on page 7.

From meyer@imap.theory.csail.mit.edu  Thu Sep 22 16:25:32 2005
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Date: Thu, 22 Sep 2005 16:25:33 -0400
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you'll see more tmw, and lots during the term: induction is a pretty 
basic proof technique we use all the time.

regards, A

Amanda Seybold wrote:

> It would be nice to see more?  Perhaps ones with more than one 
> variable, so one has to figure out what to assign n to.
>
>> Any further comment now you've seen one?
>> regards, A.
>>
>> Amanda Seybold wrote:
>>
>>> I would like to hear more about these other induction hypotheses 
>>> mentioned on page 7.
>>


From meyer@imap.theory.csail.mit.edu  Thu Sep 22 16:58:54 2005
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Date: Thu, 22 Sep 2005 16:58:57 -0400
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To: Paul Groudas <pgroudas@MIT.EDU>
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Subject: Re: reading comments
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I agree, and I just revised a bit.  See if new version helps.

Thx for the feedback.
regards, A.

Paul Groudas wrote:

>I thought the reading was interesting, but there was one portion that was a
>little confusing.  On page 5, the paragraph under equation (3) does the
>equivalent of a lot of fast talk and hand-waving, and while if you go through
>it it is most certainly correct, if one or two steps were actually written out
>it would have helped.
>
>-Paul Groudas
>  
>


From meyer@imap.theory.csail.mit.edu  Thu Sep 22 10:41:11 2005
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not sure what kind of further "clarification" you're looking for, but 
you'll see several more examples Friday.  Let me know if you're not 
satisfied after you've seen them.

regards, A.

Sheldon Chan wrote:

>Perhaps its simply an expectation that the "strong" in the name implies
>that it should be more direct and supportive evidence in the proof.
>It makes sense making assumptions allows us to more easily prove
>something, but counterintuitive in producing a sound proof, since it could
>leave more room for faulty assumptions. I think it would be good if
>there were more examples or a clarification of the criteria for such
>assumptions made in a strong induction proof.
>
>Thanks,
>
>Sheldon
>
>On Wed, 21 Sep 2005, Prof. Albert R. Meyer wrote:
>
>  
>
>>yes that's right; so what's confusing you?
>>regards, A.
>>
>>Sheldon Chan wrote:
>>
>>    
>>
>>>I find the concept of strong induction to still be confusing. From
>>>what I've gathered, it's simply an induction proof that has more
>>>assumptions.
>>>      
>>>
>>    
>>
>
>  
>

From meyer@imap.theory.csail.mit.edu  Thu Sep 22 10:45:30 2005
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The k and m in the proof are only known to be SMALLER than n+2 (in fact,
they cannot equal n+2).  Strong induction let's us assume both k & m are
products of primes.  Simple induction would only let us assume that n+2 was
a product of primes, which isn't much use in attacking n+3.
 
Make sense now?
 
Regards, A.
 
Chieu Nguyen wrote:
 
 > I'm a bit confused about the difference between simple induction and 
strong induction. I'm not sure how the proof of Lemma 3.1 on page 10 
qualifies as strong induction rather than simple.
 >
 > --Chieu

From meyer@imap.theory.csail.mit.edu  Thu Sep 22 10:54:07 2005
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Yes, could use simple induction to PROVE that P(0),...,P(n) hold if you've
proved P(0) and P(k) ==> P(k+1) for all k <n.  But simple induction doesn't
say this explicitly, and if you wanted to use only simple induction, you'd
need to clog up your proof either with the subproof by simple induction
about P(0)...P(n), or else you would have to cite your Lemma, which you
would naturally have called your Strong Induction Lemma :-), which 
asserted it was
ok to assume them all.
 
To avoid this, we simply identify and name Strong Induction as a sound
proof method.
 
Make sense?
 
Regards, A.  
 
 
Arup Sarma wrote:
 
 > Section 3, page 10:
 > I found this difficult to understand, because I'm still not sure what 
the difference between simple and strong induction is.  Doesn't simple 
induction imply that P(0), P(1), ..., P(n) are true as well?
 >
 > |Arup|
 >


From meyer@imap.theory.csail.mit.edu  Thu Sep 22 11:00:31 2005
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we used to teach this, and students found it more confusing than 
helpful.  Since it's not important, except foundationally, I now leave 
out the details.
If you're really curious, I can sketch it for you after class some time.

regards, A.

Katherine A Romer wrote:

>"...there's a routine way to transform any proof using the Well Ordering
>Principle into a proof using Strong Induction, and vice-versa." (p.11)
>I'd like to see an example in lecture of how one of the theorems we've proved
>using induction could be proved using the Well Ordering Principle--I'm having a
>hard time seeing how this might be done.
>
>Katherine Romer
>  
>

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Hi Albert,
I have been working on ps3 in the week4 directory.
It doesn't latex well, because I still have the
problem including the pdf diagram.  However,
if you use latex (instead of pdflatex, which doesn't
work at all), you can get something without the figure.
Here are some comments on questions/modifications that 
came up:

Relations course notes:
in section 5 of the spring 04 notes, lemma 5.3 says
that every partial order is reflexive and transitive,
but I think it would be good to specify that this
lemma only applies to weak partial orders.

problem 1:
I had them do both weak and strict partial orders in part (b).  

problem 2:
for part (a), should we have them prove it is a maximum length
chain?
for part (b), changed wording, so that hopefully it is clear
that they don't have to prove that the antichain is maximum.
Do they have the math background to prove that it is at least as
big as 2^n/n?

problem 4 didn't change anything, since will cover DAG's in 
class.

best,
Ronitt


	From meyer@csail.mit.edu  Wed Sep 21 09:33:54 2005
	Date: Wed, 21 Sep 2005 09:33:54 -0400
	From: "Prof. Albert R. Meyer" <meyer@csail.mit.edu>
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	Prob 1 is ok if reworded to say "which are p.o.'s? which are equiv 
	rels?  which are equiv rels on their domain?" because
	I'd prefer to focus on these kinds of relations we use and deemphasize 
	pure relational axioms/properties in in isolation.

	For this reason, I wouldn't use Prob 2 (unless we can rework it into a 
	false proof like the one that was in lecture).

	Prob 3(b) seems very tricky TO PROVE as Eric pointed out -- he said it 
	requires Sperner's Lemma or similar cleverness to show you can' t beat 
	the size n choose n/2 antichain of subsets of size n/2 (though I suspect 
	there might be a more elementary induction argument lurking around 
	there).  But I like your idea to derive a 2^n/n lower bound, which is 
	not a bad bound: using Stirling's formula I get 2^n/sqrt{2 pi n}.

	I like prob 4, though for 4(c) I'd give them the power of 2 chain and 
	ask that they prove it's maximal.  Then for 4(d), I'd say: "let c be the 
	length of the  power of 2 chain.  By Dilworth Lemma, there must be an 
	antichain of length 2^n/c.  Describe one."

	But these probs are all theoretical, and it would be nice to have 
	something reflecting possible applications, eg, scheduling.  Take a look at
	F05 pset5, prob 5.  It's writeup uses a lot of DAG/graph terminology, 
	but shouldn't be hard to express purely in partial order language.
	If you go with this one, I'd suggest dropping Prob 3 above, which seems 
	unmotivated.

	I'll work on finding an intro-to-graphs problem or two.  If you agree to 
	go with probs 1, 4, and F04 ps5, prob 5, that should do it for a 
	reasonable ps4.

	regards, A.

	P.S. please delete latex-macros-ronitt from devel/week3 (baffled me for 
	a while why my edits to course.dat were not working.)  Much better to 
	link to the single copy of  the macros in pub/staff/ than make your own 
	that can get out of sync.



	Ronitt Rubinfeld wrote:

	>on problem 3 of the proposed homework,
	>there is a partial order on subsets of {1..n}.
	>couldn't we get them to lower bound the
	>size of a max length antichain by dilworth's
	>thm by 2^n/(n+1) (since there is no chain of length > n+1)
	>
	>maybe problem 3 and problem 4 are too similar...
	>in that case, I would probably go with problem 4.
	>  
	>

From meyer@imap.theory.csail.mit.edu  Thu Sep 22 17:18:48 2005
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I thought the reading on induction and strong induction were pretty  
clear, but I'm still not sure how the Well Ordering Principle is used  
to prove things. More examples would've been nice. It would've been  
cool also to see one thing proved three different ways, just to  
compare and contrast.

~Crystal

From meyer@imap.theory.csail.mit.edu  Thu Sep 22 18:07:27 2005
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 From page 12 of the reading:

"4 The Well Ordering Principle
Another proof method closely related to induction depends on the
Well Ordering Principle. Every nonempty subset of natural numbers
has a smallest element.
The Well Ordering Principle looks nothing like the induction axiom,  
and it may seem obvious but
useless.
But as for obvious, note that this axiom would be false if the set of  
non-negative integers, N, were
replaced by, say, the set, Z, of all integers, or the set, Q+, of  
positive rational numbers. Neither
of these sets has a least element. So the Well Ordering Principle  
does capture something special
about the natural numbers.
As for useless, it turns out that thereâ€™s a routine way to transform  
any proof using the Well Or-
dering Principle into a proof using Strong Induction, and vice-versa.  
(We wonâ€™t take the time to
describe the transformations, though they are not hard.) So Well  
Ordering could have been used
instead of induction in all the previous proofs.
In fact, looking back, we implicitly relied on the Well Ordering  
Principle in the proof in Week 2
Notes that âˆš2 is irrational. That proof assumed that any rational  
number, q, could be written as
a fraction in lowest terms, that is, q = m/n where m and n are  
integers with no common factors.
How do we know this is always possible?
First, we can assume m
â‰¥ 0 (otherwise, replace m/n by âˆ’m/(âˆ’n)), so the set of natural  
numbers,
m, such that q = m/n for some integer, n, is not empty. Therefore, by  
Well Ordering, there must
be a least natural number, m0 , such that q = m0 /n0 for some  
integer, n0 . Now if m0 and n0 had
a common factor, p > 1, then (m0 /p)/(n0 /p) would be another way to  
express q as a quotient of
integers. But since 0
â‰¤ (m0 /p) < m0 . this contradicts the minimality of m0 .
Weâ€™ve using the Well-ordering Principle on the sly from early on!
Mathematicians often use Well Ordering because it often leads to  
shorter proofs than induction.
On the other hand, Well Ordering proofs typically involve proof by  
contradiction, so using it is not
always the best approach. The choice of method is really a matter of  
styleâ€”but style does matter."

This seemed to be the most difficult passage to grasp simply because  
it does not concretely explain what "The Well Ordering Principle" is,  
because of this I would personally like to have this discussed or  
elaborating upon in lecture. Thanks.

Rian Hunter

From meyer@imap.theory.csail.mit.edu  Thu Sep 22 18:22:44 2005
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passage: Section 4 The Well Ordering Principle pg 12
The principle seems obvious and easy enough but I would like to see
more examples on how it could be used or even an example on how it
could be used instead of induction

Also I am having trouble understanding being vacuously true from page
11.  It seems like a contradiction that when the hypothesis for
something is false the whole thing is true.

Cynthia Bossard

From meyer@imap.theory.csail.mit.edu  Thu Sep 22 18:53:53 2005
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"Despite the name, strong induction is actually no more powerful than ordinary
induction. In other words, any theorem that can be proved with strong induction
could also be proved with ordinary induction (using a slightly more complicated
indcution hypothesis)."

I found this very surprising, I have seen induction and strong induction before
and always thought that strong induction was more powerful, that is, that some
problems could be solved using strong induction but not ordinary induction.  I
have never actually seen a problem be given two different solutions: one with
strong induction and another with ordinary induction.  I wonder how much
stronger the hypothesis is in ordinary induction than it is in strong
induction.

Adriana Lopez

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I thought the section on simple induction was just fine.  I am still having
trouble understanding the well ordering principle, and might like to see a
different example of strong induction in class.

-Rob Crowell




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I found the strong induction examples (3.2 and 3.3 on pages 10 and 11) a
bit confusing.  The idea of strong induction was cleared up somewhat on
the problem set, however.


Zev
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From meyer@imap.theory.csail.mit.edu  Thu Sep 22 19:15:32 2005
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I found the section on the well-ordering principle (page 12) most interesting.
I'm concurrently enrolled in 18.100b, and we've covered some proofs that use
this principle, but never had it directly named. I'd be interested to see what
other kinds of proofs can use this principle as a main tenet.

From meyer@imap.theory.csail.mit.edu  Thu Sep 22 19:33:44 2005
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" it does not concretely explain what "The Well Ordering Principle" is"  
I thought the box labeled "The Well Ordering Principle" was about as 
concrete as it gets.  Can you explain what kind of further statement of 
the Principle you're looking for?

Rian Hunter wrote:

> From page 12 of the reading: ....
>
> This seemed to be the most difficult passage to grasp simply because  
> it does not concretely explain what "The Well Ordering Principle" is,  
> because of this I would personally like to have this discussed or  
> elaborating upon in lecture. Thanks.
>
> Rian Hunter



From meyer@imap.theory.csail.mit.edu  Thu Sep 22 20:05:34 2005
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Theorem 2.2 was an interesting point for me, I was aware that Fibonacci 
numbers had weird properties but this was even beyond my expectations.

By the way, the theorem states that
For all n greater than or equal to 2, F_0^2+F_1^2+...+F_n^2=F_n+F_(n+1)

best

yasin


From meyer@imap.theory.csail.mit.edu  Thu Sep 22 20:43:07 2005
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Date: Thu, 22 Sep 2005 20:43:00 -0400
From: Lohith Kini <lkini@MIT.EDU>
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Hi,

After reading the week's lecture notes, I found the /well-ordering 
principle/ the most confusing topic to date. I didn't fully understand 
its connection with Induction and I was confused with the Tutor problem 
related to this principle. I would appreciate it if you could possibly 
explain this topic in more detail.

Thanks,
Lohith

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-------- Original Message --------
Subject: Re: Reading Comments Week 3
Date: Thu, 22 Sep 2005 20:20:47 -0400
From: Chieu Nguyen <cvnguyen@MIT.EDU>
To: Prof. Albert R. Meyer <meyer@csail.mit.edu>
References: <00f601c5bf5a$5ee931f0$e905ee12@addressisp.com> 
<4332BFC5.1000706@csail.mit.edu>

Dear Prof. Meyer,

That was very helpful. Thanks for clearing things up.

--Chieu

----- Original Message -----
From: "Prof. Albert R. Meyer" <meyer@csail.mit.edu>
To: "Chieu Nguyen" <cvnguyen@mit.edu>
Cc: <6042-staff@theory.csail.mit.edu>
Sent: Thursday, September 22, 2005 10:29 AM
Subject: Re: Reading Comments Week 3


> The k and m in the proof are only known to be SMALLER than n+2 (in fact,
> they cannot equal n+2).  Strong induction let's us assume both k & m are
> products of primes.  Simple induction would only let us assume that n+2 
> was
> a product of primes, which isn't much use in attacking n+3.
>
> Make sense now?
>
> Regards, A.
>
> Chieu Nguyen wrote:
>
> > I'm a bit confused about the difference between simple induction and
> strong induction. I'm not sure how the proof of Lemma 3.1 on page 10 
> qualifies as strong induction rather than simple.
> >
> > --Chieu
>
> 


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Dear Prof. Meyer,

That was very helpful. Thanks for clearing things up.

--Chieu

----- Original Message ----- 
From: "Prof. Albert R. Meyer" <meyer@csail.mit.edu>
To: "Chieu Nguyen" <cvnguyen@mit.edu>
Cc: <6042-staff@theory.csail.mit.edu>
Sent: Thursday, September 22, 2005 10:29 AM
Subject: Re: Reading Comments Week 3


> The k and m in the proof are only known to be SMALLER than n+2 (in fact,
> they cannot equal n+2).  Strong induction let's us assume both k & m are
> products of primes.  Simple induction would only let us assume that n+2 
> was
> a product of primes, which isn't much use in attacking n+3.
>
> Make sense now?
>
> Regards, A.
>
> Chieu Nguyen wrote:
>
> > I'm a bit confused about the difference between simple induction and
> strong induction. I'm not sure how the proof of Lemma 3.1 on page 10 
> qualifies as strong induction rather than simple.
> >
> > --Chieu
>
> 

From meyer@imap.theory.csail.mit.edu  Thu Sep 22 21:25:53 2005
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"...there?s a routine way to transform any proof using the Well Ordering
Principle into a proof using Strong Induction, and vice-versa. So Well Ordering
could have been used instead of induction in all the previous proofs."

I would like to see some more examples of this, it's confusing to me.

-Hector Beltran




From meyer@imap.theory.csail.mit.edu  Thu Sep 22 21:27:10 2005
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Reference: Section 3.3 Pg 11

I clearly understood normal induction, however I did have some difficulty with
strong induction (especially this problem) and would like to discuss it in more
detail in class. I did understand it after close reading but I was hoping we
could go over it in class.

-Rahul Shroff

From meyer@imap.theory.csail.mit.edu  Thu Sep 22 22:12:55 2005
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Hi,

Even after reading about Strong Inductions twice, I did not feel the 
example was explained clearly in class. Perhaps it is my own fault but I 
  was not able to make more sense of it even from the reading. I think I 
will come to office hours.

Thanks,

Scot

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--Apple-Mail-34-958248826
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"First, we can assume m   0 (otherwise, replace m/n by =E2=88=92m/(=E2=88=92=
n)), =20
so the set of natural numbers,
m, such that q =3D m/n for some integer, n, is not empty. Therefore, by =20=

Well Ordering, there must
be a least natural number, m0, such that q =3D m0/n0 for some integer, =20=

n0. Now if m0 and n0 had
a common factor, p > 1, then (m0/p)/(n0/p) would be another way to =20
express q as a quotient of
integers. But since 0   (m0/p) < m0. this contradicts the minimality =20
of m0."

I did not fully understand this paragraph  because i do not =20
understand how we reach a contradiction.  This was the part in the =20
notes that I found most confusing.

MIchael Murray




--Apple-Mail-34-958248826
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<HTML><BODY style=3D"word-wrap: break-word; -khtml-nbsp-mode: space; =
-khtml-line-break: after-white-space; "><DIV style=3D"margin-top: 0px; =
margin-right: 0px; margin-bottom: 0px; margin-left: 0px; "><FONT =
class=3D"Apple-style-span" size=3D"3"><SPAN class=3D"Apple-style-span" =
style=3D"font-size: 11px;">"First, we can assume m </SPAN></FONT><FONT =
class=3D"Apple-style-span" size=3D"3"><SPAN class=3D"Apple-style-span" =
style=3D"font-size: 11px;">=C2=A0 </SPAN></FONT><FONT =
class=3D"Apple-style-span" size=3D"3"><SPAN class=3D"Apple-style-span" =
style=3D"font-size: 11px;">0 (otherwise, replace m/n by =E2=88=92m/(=E2=88=
=92n)), so the set of natural numbers,</SPAN></FONT></DIV><DIV =
style=3D"margin-top: 0px; margin-right: 0px; margin-bottom: 0px; =
margin-left: 0px; "><FONT class=3D"Apple-style-span" size=3D"3"><SPAN =
class=3D"Apple-style-span" style=3D"font-size: 11px;">m, such that q =3D =
m/n for some integer, n, is not empty. Therefore, by Well Ordering, =
there must</SPAN></FONT></DIV><DIV style=3D"margin-top: 0px; =
margin-right: 0px; margin-bottom: 0px; margin-left: 0px; "><FONT =
class=3D"Apple-style-span" size=3D"3"><SPAN class=3D"Apple-style-span" =
style=3D"font-size: 11px;">be a least natural number, =
m</SPAN></FONT><FONT class=3D"Apple-style-span" size=3D"1"><SPAN =
class=3D"Apple-style-span" style=3D"font-size: =
8px;">0</SPAN></FONT><FONT class=3D"Apple-style-span" size=3D"3"><SPAN =
class=3D"Apple-style-span" style=3D"font-size: 11px;">, such that q =3D =
m</SPAN></FONT><FONT class=3D"Apple-style-span" size=3D"1"><SPAN =
class=3D"Apple-style-span" style=3D"font-size: =
8px;">0</SPAN></FONT><FONT class=3D"Apple-style-span" size=3D"3"><SPAN =
class=3D"Apple-style-span" style=3D"font-size: =
11px;">/n</SPAN></FONT><FONT class=3D"Apple-style-span" size=3D"1"><SPAN =
class=3D"Apple-style-span" style=3D"font-size: 8px;">0 =
</SPAN></FONT><FONT class=3D"Apple-style-span" size=3D"3"><SPAN =
class=3D"Apple-style-span" style=3D"font-size: 11px;">for some integer, =
n</SPAN></FONT><FONT class=3D"Apple-style-span" size=3D"1"><SPAN =
class=3D"Apple-style-span" style=3D"font-size: =
8px;">0</SPAN></FONT><FONT class=3D"Apple-style-span" size=3D"3"><SPAN =
class=3D"Apple-style-span" style=3D"font-size: 11px;">. Now if =
m</SPAN></FONT><FONT class=3D"Apple-style-span" size=3D"1"><SPAN =
class=3D"Apple-style-span" style=3D"font-size: 8px;">0 =
</SPAN></FONT><FONT class=3D"Apple-style-span" size=3D"3"><SPAN =
class=3D"Apple-style-span" style=3D"font-size: 11px;">and =
n</SPAN></FONT><FONT class=3D"Apple-style-span" size=3D"1"><SPAN =
class=3D"Apple-style-span" style=3D"font-size: 8px;">0 =
</SPAN></FONT><FONT class=3D"Apple-style-span" size=3D"3"><SPAN =
class=3D"Apple-style-span" style=3D"font-size: =
11px;">had</SPAN></FONT></DIV><DIV style=3D"margin-top: 0px; =
margin-right: 0px; margin-bottom: 0px; margin-left: 0px; "><FONT =
class=3D"Apple-style-span" size=3D"3"><SPAN class=3D"Apple-style-span" =
style=3D"font-size: 11px;">a common factor, p &gt; 1, then =
(m</SPAN></FONT><FONT class=3D"Apple-style-span" size=3D"1"><SPAN =
class=3D"Apple-style-span" style=3D"font-size: =
8px;">0</SPAN></FONT><FONT class=3D"Apple-style-span" size=3D"3"><SPAN =
class=3D"Apple-style-span" style=3D"font-size: =
11px;">/p)/(n</SPAN></FONT><FONT class=3D"Apple-style-span" =
size=3D"1"><SPAN class=3D"Apple-style-span" style=3D"font-size: =
8px;">0</SPAN></FONT><FONT class=3D"Apple-style-span" size=3D"3"><SPAN =
class=3D"Apple-style-span" style=3D"font-size: 11px;">/p) would be =
another way to express q as a quotient of</SPAN></FONT></DIV><DIV =
style=3D"margin-top: 0px; margin-right: 0px; margin-bottom: 0px; =
margin-left: 0px; "><FONT class=3D"Apple-style-span" size=3D"3"><SPAN =
class=3D"Apple-style-span" style=3D"font-size: 11px;">integers. But =
since 0 </SPAN></FONT><FONT class=3D"Apple-style-span" size=3D"3"><SPAN =
class=3D"Apple-style-span" style=3D"font-size: 11px;">=C2=A0 =
</SPAN></FONT><FONT class=3D"Apple-style-span" size=3D"3"><SPAN =
class=3D"Apple-style-span" style=3D"font-size: =
11px;">(m</SPAN></FONT><FONT class=3D"Apple-style-span" size=3D"1"><SPAN =
class=3D"Apple-style-span" style=3D"font-size: =
8px;">0</SPAN></FONT><FONT class=3D"Apple-style-span" size=3D"3"><SPAN =
class=3D"Apple-style-span" style=3D"font-size: 11px;">/p) &lt; =
m</SPAN></FONT><FONT class=3D"Apple-style-span" size=3D"1"><SPAN =
class=3D"Apple-style-span" style=3D"font-size: =
8px;">0</SPAN></FONT><FONT class=3D"Apple-style-span" size=3D"3"><SPAN =
class=3D"Apple-style-span" style=3D"font-size: 11px;">. this contradicts =
the minimality of m</SPAN></FONT><FONT class=3D"Apple-style-span" =
size=3D"1"><SPAN class=3D"Apple-style-span" style=3D"font-size: =
8px;">0</SPAN></FONT><FONT class=3D"Apple-style-span" size=3D"3"><SPAN =
class=3D"Apple-style-span" style=3D"font-size: =
11px;">."</SPAN></FONT></DIV><DIV style=3D"margin-top: 0px; =
margin-right: 0px; margin-bottom: 0px; margin-left: 0px; "><FONT =
class=3D"Apple-style-span" size=3D"3"><SPAN class=3D"Apple-style-span" =
style=3D"font-size: 11px;"><BR =
class=3D"khtml-block-placeholder"></SPAN></FONT></DIV><DIV =
style=3D"margin-top: 0px; margin-right: 0px; margin-bottom: 0px; =
margin-left: 0px; "><FONT class=3D"Apple-style-span" size=3D"3"><SPAN =
class=3D"Apple-style-span" style=3D"font-size: 11px;">I did not fully =
understand this paragraph=C2=A0 because i do not understand how we reach =
a contradiction.=C2=A0 This was the part in the notes that I found most =
confusing.</SPAN></FONT></DIV><DIV style=3D"margin-top: 0px; =
margin-right: 0px; margin-bottom: 0px; margin-left: 0px; "><FONT =
class=3D"Apple-style-span" size=3D"3"><SPAN class=3D"Apple-style-span" =
style=3D"font-size: 11px;"><BR =
class=3D"khtml-block-placeholder"></SPAN></FONT></DIV><DIV =
style=3D"margin-top: 0px; margin-right: 0px; margin-bottom: 0px; =
margin-left: 0px; "><FONT class=3D"Apple-style-span" size=3D"3"><SPAN =
class=3D"Apple-style-span" style=3D"font-size: 11px;">MIchael =
Murray</SPAN></FONT></DIV><DIV style=3D"margin-top: 0px; margin-right: =
0px; margin-bottom: 0px; margin-left: 0px; "><FONT =
class=3D"Apple-style-span" size=3D"3"><SPAN class=3D"Apple-style-span" =
style=3D"font-size: 11px;"><BR =
class=3D"khtml-block-placeholder"></SPAN></FONT></DIV><DIV =
style=3D"margin-top: 0px; margin-right: 0px; margin-bottom: 0px; =
margin-left: 0px; "><FONT class=3D"Apple-style-span" size=3D"3"><SPAN =
class=3D"Apple-style-span" style=3D"font-size: 11px;"><BR =
class=3D"khtml-block-placeholder"></SPAN></FONT></DIV><DIV =
style=3D"margin-top: 0px; margin-right: 0px; margin-bottom: 0px; =
margin-left: 0px; "><FONT class=3D"Apple-style-span" size=3D"3"><SPAN =
class=3D"Apple-style-span" style=3D"font-size: =
11px;"></SPAN></FONT></DIV><DIV style=3D"margin-top: 0px; margin-right: =
0px; margin-bottom: 0px; margin-left: 0px; "><BR =
class=3D"khtml-block-placeholder"></DIV></BODY></HTML>=

--Apple-Mail-34-958248826--

From meyer@imap.theory.csail.mit.edu  Thu Sep 22 23:12:33 2005
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Date: Thu, 22 Sep 2005 23:12:29 -0400
From: Boris E Revzin <brevzin@MIT.EDU>
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Regarding the induction lecture, it seems excessive to me to have to write out
the entire induction template. By showing a base case and P(n)->P(n+1), it is
pretty clear to anyone reading the proof that it is by induction. I just want
to know if it's enough to show P(0), P(n)->P(n+1), QED. I just think that's all
that is necessary, oftentimes writing out the template will take more time than
writing out the actual proof...

Boris "Barry" Revzin

From meyer@imap.theory.csail.mit.edu  Thu Sep 22 23:15:58 2005
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Page 10, "Strong Induction"
This is the only thing I had a problem with, since it seems so similar to simple
induction. I found it somewhat difficult to see the difference between the two.
If there's an extra example that can be seen in lecture, I'm sure it'd clarify
things!

Page 12, "The Well Ordering Principle"
Interesting; I wonder if there's a principle that says there's a greatest
element in a nonempty subset? Just made me think.

- John Marrero




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Date: Thu, 22 Sep 2005 23:36:22 -0400
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Page 12, well ordering principle (section 4)
I am pretty sure that I underrstood everything, but a little bit more work on
the well ordering principle could potentially be helpful.

    -Forrest Green

From meyer@imap.theory.csail.mit.edu  Thu Sep 22 23:49:46 2005
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Subject: reading comments
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I found the whole topic of induction to be such an elegant yet sound way to 
prove stuff. For example the courtyard problem amazed me since without 
knowing about induction I would still be brute forcing my way to tile the 
whole courtyard with L-shaped tiles. I'm only a bit confused on reasoning 
and claims which would make a proof using induction wrong. It could be made 
much clearer when induction would not be valid.

Josh Monzon




Joshua Jen C. Monzon
Massachusetts Institute of Technology
Electrical Engineering with Computer Science
jjmonzon@mit.edu   617-803-7497


From meyer@imap.theory.csail.mit.edu  Thu Sep 22 23:53:43 2005
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I would like to see more practices in Induction in class, and more 
particular cases when induction fails (like the horse example in class)

- Steve


From meyer@imap.theory.csail.mit.edu  Thu Sep 22 23:57:05 2005
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Date: Thu, 22 Sep 2005 23:57:13 -0400
From: "Prof. Albert R. Meyer" <meyer@csail.mit.edu>
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we'll relax the template discipline in a week or so, but for now and 
through ps2, please string along with us and use the template. A 
surprising number of students in the class need the template when they 
begin learning induction proofs.

regards, A.

Boris E Revzin wrote:
> Regarding the induction lecture, it seems excessive to me to have to write out
> the entire induction template. By showing a base case and P(n)->P(n+1), it is
> pretty clear to anyone reading the proof that it is by induction. I just want
> to know if it's enough to show P(0), P(n)->P(n+1), QED. I just think that's all
> that is necessary, oftentimes writing out the template will take more time than
> writing out the actual proof...
> 
> Boris "Barry" Revzin


From meyer@imap.theory.csail.mit.edu  Fri Sep 23 00:02:57 2005
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Date: Fri, 23 Sep 2005 00:02:58 -0400
To: 6042-probs@theory.csail.mit.edu
From: Tony Ng <tonyng@MIT.EDU>
Subject: Week 3 Comments
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The "All Horses are the Same Color", starting on page 9, proof kind of 
bothered me. The flaw with the proof is that it is not true for n = 1. 
However, is it legitimate to try to prove some add horse function (which 
doesn't seem really related to mathematics and numbers)? I can imagine 
someone clever figuring out some proof that satisfy the n=1 case and prove 
all horses are the same color.


From meyer@imap.theory.csail.mit.edu  Fri Sep 23 00:12:46 2005
Message-ID: <433380C7.9000400@csail.mit.edu>
Date: Fri, 23 Sep 2005 00:12:55 -0400
From: "Prof. Albert R. Meyer" <meyer@csail.mit.edu>
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I don't know what you mean when you say "try to prove some add horse 
function."  Propositions get proved; functions don't get proved, they 
get applied.  But you seem to be saying that a clever person could prove 
something that wasn't true.  Do you really mean that?

Regards, A.

Tony Ng wrote:
> The "All Horses are the Same Color", starting on page 9, proof kind of 
> bothered me. The flaw with the proof is that it is not true for n = 1. 
> However, is it legitimate to try to prove some add horse function (which 
> doesn't seem really related to mathematics and numbers)? I can imagine 
> someone clever figuring out some proof that satisfy the n=1 case and 
> prove all horses are the same color.
> 


From meyer@imap.theory.csail.mit.edu  Fri Sep 23 00:06:23 2005
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Induction is always valid :-).  What you have to watch out for are 
proofs that claim to be by induction but do it wrong: they skip some 
cases or make a mistake in proving the cases.  We'll discuss additional 
mistakes in induction proofs as the term progresses.

regards, A.

Joshua Jen C. Monzon wrote:
> I found the whole topic of induction to be such an elegant yet sound way 
> to prove stuff. For example the courtyard problem amazed me since 
> without knowing about induction I would still be brute forcing my way to 
> tile the whole courtyard with L-shaped tiles. I'm only a bit confused on 
> reasoning and claims which would make a proof using induction wrong. It 
> could be made much clearer when induction would not be valid.
> 
> Josh Monzon
> 
> 
> 
> 
> Joshua Jen C. Monzon
> Massachusetts Institute of Technology
> Electrical Engineering with Computer Science
> jjmonzon@mit.edu   617-803-7497
> 

From meyer@imap.theory.csail.mit.edu  Thu Sep 22 23:59:30 2005
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From: "Prof. Albert R. Meyer" <meyer@csail.mit.edu>
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we let m0 be the smallest numerator in a fraction for and rational 
number, q, and then we found a smaller one -- that's the contradiction.

Does that help?

regards, A.

Michael Murray wrote:
> "First, we can assume m   0 (otherwise, replace m/n by âˆ’m/(âˆ’n)), so the 
> set of natural numbers,
> m, such that q = m/n for some integer, n, is not empty. Therefore, by 
> Well Ordering, there must
> be a least natural number, m0, such that q = m0/n0 for some integer, n0. 
> Now if m0 and n0 had
> a common factor, p > 1, then (m0/p)/(n0/p) would be another way to 
> express q as a quotient of
> integers. But since 0   (m0/p) < m0. this contradicts the minimality of m0."
> 
> I did not fully understand this paragraph  because i do not understand 
> how we reach a contradiction.  This was the part in the notes that I 
> found most confusing.
> 
> MIchael Murray
> 
> 
> 

From meyer@imap.theory.csail.mit.edu  Thu Sep 22 23:57:06 2005
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we'll relax the template discipline in a week or so, but for now and 
through ps2, please string along with us and use the template. A 
surprising number of students in the class need the template when they 
begin learning induction proofs.

regards, A.

Boris E Revzin wrote:
> Regarding the induction lecture, it seems excessive to me to have to write out
> the entire induction template. By showing a base case and P(n)->P(n+1), it is
> pretty clear to anyone reading the proof that it is by induction. I just want
> to know if it's enough to show P(0), P(n)->P(n+1), QED. I just think that's all
> that is necessary, oftentimes writing out the template will take more time than
> writing out the actual proof...
> 
> Boris "Barry" Revzin

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Proofs by induction are completely foriegn to me.  Even after class, I still
have no clue how to figure out where th flaws in the tutor quesiton #3 is.
-Daniel Gutierrez

From meyer@imap.theory.csail.mit.edu  Fri Sep 23 00:48:34 2005
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Page 12's discussion of the Well Ordering Principle is quite fascinating.
How do you prove the principle, in a general sense?  Straightforward subsets
(like even numbers) are pretty obviously true, but what about more
complicated sets?

 

Chris Yang


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<p class=3DMsoNormal><font size=3D2 face=3DArial><span =
style=3D'font-size:10.0pt;
font-family:Arial'>Page 12&#8217;s discussion of the Well Ordering =
Principle is
quite fascinating.&nbsp; How do you prove the principle, in a general =
sense?&nbsp;
Straightforward subsets (like even numbers) are pretty obviously true, =
but what
about more complicated sets?<o:p></o:p></span></font></p>

<p class=3DMsoNormal><font size=3D2 face=3DArial><span =
style=3D'font-size:10.0pt;
font-family:Arial'><o:p>&nbsp;</o:p></span></font></p>

<p class=3DMsoNormal><font size=3D2 face=3DArial><span =
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For me the most confusing part of the reading was the Well Ordering
Principle.  Particularly, how it was presented as a parallel method to
induction, whereas said method merely depends on it.  Additionally the tutor
problems seemed to reinforce its presentation as a regular proof method
rather than a tool used by one.

 

Peter Bilodeau


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<p class=3DMsoNormal><font size=3D2 face=3DArial><span =
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<p class=3DMsoNormal><font size=3D2 face=3DArial><span =
style=3D'font-size:10.0pt;
font-family:Arial'>For me the most confusing part of the reading was the =
Well
Ordering Principle.&nbsp; Particularly, how it was presented as a =
parallel method to
induction, whereas said method merely depends on it.&nbsp; Additionally =
the tutor
problems seemed to reinforce its presentation as a regular proof method =
rather
than a tool used by one.<o:p></o:p></span></font></p>

<p class=3DMsoNormal><font size=3D2 face=3DArial><span =
style=3D'font-size:10.0pt;
font-family:Arial'><o:p>&nbsp;</o:p></span></font></p>

<p class=3DMsoNormal><font size=3D2 face=3DArial><span =
style=3D'font-size:10.0pt;
font-family:Arial'>Peter Bilodeau<o:p></o:p></span></font></p>

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From meyer@imap.theory.csail.mit.edu  Fri Sep 23 00:56:20 2005
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From: Rian Hunter <rian@MIT.EDU>
Subject: Re: Assigned Reading
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Actually I guess the reading tricked me. I was used to the proof  
methods being explained how to be used step by step, while the Well  
Ordering Principle is just a simple statement. I thought the  
statement in the box "Every nonempty subset..." was a statement that  
could be proved using the Well Ordering Principle; I wasn't expecting  
that it was the Well Ordering Principle itself. Actually it's unclear  
to me whether or not the Well Ordering Principle is a proof method  
itself or just a principle used in other proof methods (proof by  
contradiction for example), but after re-reading and looking at the  
context it seems that it isn't.
-rian

On Sep 22, 2005, at 7:33 PM, Prof. Albert R. Meyer wrote:

> " it does not concretely explain what "The Well Ordering Principle"  
> is"  I thought the box labeled "The Well Ordering Principle" was  
> about as concrete as it gets.  Can you explain what kind of further  
> statement of the Principle you're looking for?
>
> Rian Hunter wrote:
>
>
>> From page 12 of the reading: ....
>>
>> This seemed to be the most difficult passage to grasp simply  
>> because  it does not concretely explain what "The Well Ordering  
>> Principle" is,  because of this I would personally like to have  
>> this discussed or  elaborating upon in lecture. Thanks.
>>
>> Rian Hunter
>>
>
>


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I found myself confused by the explanation of Strong
Induction. Although maybe the fibbonaci proof helped that. (The
definition made sense, but it took far to long for me to figure out
the answer to the fibbonaci misproof)


From meyer@imap.theory.csail.mit.edu  Fri Sep 23 01:12:35 2005
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Hi,=20

I found the reading hard especially the "Well order reading" part. I =
didn't understand how it is related to induction

Adnaan Jiwaji
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From meyer@imap.theory.csail.mit.edu  Fri Sep 23 01:27:00 2005
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From: Timothy Mwangi <mwangi@MIT.EDU>
Subject: Week 3 Comments
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Passage:  2.4 Courtyard Tiling
Page:       6
I found this passage most surprising because it used induction to prove a 
geometric predicate. I knew that induction could be used to prove 
mathematical predicates but I did not think it was possible to use 
induction to prove a geometric predicate.

Sincerely,
Timothy M. Mwangi


From meyer@imap.theory.csail.mit.edu  Fri Sep 23 01:28:15 2005
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Date: Fri, 23 Sep 2005 01:28:25 -0400
From: "Prof. Albert R. Meyer" <meyer@csail.mit.edu>
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I encourage you to go to TA office hours and go over this.
regards,A.

Daniel A Gutierrez wrote:
> Proofs by induction are completely foriegn to me.  Even after class, I still
> have no clue how to figure out where th flaws in the tutor quesiton #3 is.
> -Daniel Gutierrez


From meyer@imap.theory.csail.mit.edu  Fri Sep 23 01:26:15 2005
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-------- Original Message --------
Subject: Re: Assigned Reading
Date: Fri, 23 Sep 2005 00:56:15 -0400
From: Rian Hunter <rian@MIT.EDU>
To: 6042-probs@theory.csail.mit.edu
References: <D899535F-8088-46AE-8FCD-10908D96C9DC@mit.edu> 
<43333F5B.4040601@csail.mit.edu>

Actually I guess the reading tricked me. I was used to the proof
methods being explained how to be used step by step, while the Well
Ordering Principle is just a simple statement. I thought the
statement in the box "Every nonempty subset..." was a statement that
could be proved using the Well Ordering Principle; I wasn't expecting
that it was the Well Ordering Principle itself. Actually it's unclear
to me whether or not the Well Ordering Principle is a proof method
itself or just a principle used in other proof methods (proof by
contradiction for example), but after re-reading and looking at the
context it seems that it isn't.
-rian

On Sep 22, 2005, at 7:33 PM, Prof. Albert R. Meyer wrote:

> " it does not concretely explain what "The Well Ordering Principle"  
> is"  I thought the box labeled "The Well Ordering Principle" was  
> about as concrete as it gets.  Can you explain what kind of further  
> statement of the Principle you're looking for?
>
> Rian Hunter wrote:
>
>
>> From page 12 of the reading: ....
>>
>> This seemed to be the most difficult passage to grasp simply  
>> because  it does not concretely explain what "The Well Ordering  
>> Principle" is,  because of this I would personally like to have  
>> this discussed or  elaborating upon in lecture. Thanks.
>>
>> Rian Hunter
>>
>
>



From meyer@imap.theory.csail.mit.edu  Fri Sep 23 00:06:22 2005
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Date: Fri, 23 Sep 2005 00:06:32 -0400
From: "Prof. Albert R. Meyer" <meyer@csail.mit.edu>
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Induction is always valid :-).  What you have to watch out for are 
proofs that claim to be by induction but do it wrong: they skip some 
cases or make a mistake in proving the cases.  We'll discuss additional 
mistakes in induction proofs as the term progresses.

regards, A.

Joshua Jen C. Monzon wrote:
> I found the whole topic of induction to be such an elegant yet sound way 
> to prove stuff. For example the courtyard problem amazed me since 
> without knowing about induction I would still be brute forcing my way to 
> tile the whole courtyard with L-shaped tiles. I'm only a bit confused on 
> reasoning and claims which would make a proof using induction wrong. It 
> could be made much clearer when induction would not be valid.
> 
> Josh Monzon
> 
> 
> 
> 
> Joshua Jen C. Monzon
> Massachusetts Institute of Technology
> Electrical Engineering with Computer Science
> jjmonzon@mit.edu   617-803-7497
> 


From meyer@imap.theory.csail.mit.edu  Fri Sep 23 01:28:18 2005
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I encourage you to go to TA office hours and go over this.
regards,A.

Daniel A Gutierrez wrote:
> Proofs by induction are completely foriegn to me.  Even after class, I still
> have no clue how to figure out where th flaws in the tutor quesiton #3 is.
> -Daniel Gutierrez

From meyer@imap.theory.csail.mit.edu  Fri Sep 23 01:36:08 2005
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 From this week's notes, I found the proof that we went over last class 
re: the tiling (Section 2.4, page 8) to be the most surprising, since it 
was a very elegant and easy to prove answer to what I thought initially 
was going to be a hard to prove conjecture.

From meyer@imap.theory.csail.mit.edu  Fri Sep 23 01:36:52 2005
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From: "Clinton Blackburn" <clintonb@MIT.EDU>
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Well Ordering is well.not understandable. If we study it tomorrow (later
today) in class, perhaps I'll get it. Now the passage just looks like a
bunch of words that I do not comprehend. Could you provide an example, or
two?

 

---

Clinton Blackburn

 <http://www.dlp.com/> DLP - Have you seen it? 

 


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<p class=3DMsoNormal><font size=3D2 face=3DArial><span =
style=3D'font-size:10.0pt;
font-family:Arial'>Well Ordering is well&#8230;not understandable. If we =
study
it tomorrow (later today) in class, perhaps I&#8217;ll get it. Now the =
passage
just looks like a bunch of words that I do not comprehend. Could you =
provide an
example, or two?<o:p></o:p></span></font></p>

<p class=3DMsoNormal><font size=3D2 face=3DArial><span =
style=3D'font-size:10.0pt;
font-family:Arial'><o:p>&nbsp;</o:p></span></font></p>

<p class=3DMsoNormal><font size=3D2 face=3DArial><span =
style=3D'font-size:10.0pt;
font-family:Arial'>---</span></font><o:p></o:p></p>

<p class=3DMsoNormal><st1:City w:st=3D"on"><font size=3D2 =
face=3DArial><span
 =
style=3D'font-size:10.0pt;font-family:Arial'>Clinton</span></font></st1:C=
ity><font
size=3D2 face=3DArial><span =
style=3D'font-size:10.0pt;font-family:Arial'> <st1:place
w:st=3D"on">Blackburn</st1:place></span></font><o:p></o:p></p>

<p class=3DMsoNormal><font size=3D3 face=3D"Times New Roman"><span =
style=3D'font-size:
12.0pt'><a href=3D"http://www.dlp.com/"><font size=3D2 =
face=3DArial><span
style=3D'font-size:10.0pt;font-family:Arial'>DLP &#8211; Have you seen =
it?</span></font>&nbsp;</a></span><o:p></o:p></font></p>

<p class=3DMsoNormal><font size=3D3 face=3D"Times New Roman"><span =
style=3D'font-size:
12.0pt'><o:p>&nbsp;</o:p></span></font></p>

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Sorry there isn't as much this time, its just rather more familiar material.
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Induction was covered in about as much detail as a highschool can cover it.  I'm familiar with it, although its been a while.  The in class problems were much easier for me than those of previous lectures.  Strong induction is new, but its not hard to grasp.  So, I think I understand pretty well whats going on with induction.  
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From meyer@imap.theory.csail.mit.edu  Fri Sep 23 01:53:29 2005
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I would like to see an application of the well ordering principle in lecture
(possibly in a proof or solution to a problem)
Lana

From meyer@imap.theory.csail.mit.edu  Fri Sep 23 02:00:17 2005
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I found the discussion of the Well-Ordering principle (last page, p. 12) 
most surprising. Although the statement itself makes perfect sense, it's 
really interesting how many other things depend on this 
seemingly-obvious principle.

From meyer@imap.theory.csail.mit.edu  Fri Sep 23 02:27:02 2005
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On page 12 of the notes, you discuss the well ordering principle
(section 4). Please discuss this further in class, as well as
applications of this principle.

~Isaac Charny



From meyer@imap.theory.csail.mit.edu  Fri Sep 23 02:31:26 2005
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Subject: Reading Comments #3
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One thing I found that was particularly surprising about the reading was
the discussion of the Well Ordering Principle on page 12. While (aside
from the described caveats) it does seem obvious, I found it
particularly interesting that the Well Ordering Principle could be used
to replace strong induction. Though it's only out of curiosity, it might
be good to see an example or two of this.

-- Matt


From meyer@imap.theory.csail.mit.edu  Fri Sep 23 02:32:21 2005
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Could you please go over 2.5 A Faulty Induction Proof (pages 8-9 of ln3).
I'm not sure I understand it.


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From meyer@imap.theory.csail.mit.edu  Fri Sep 23 02:38:03 2005
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From: Jesus I Medrano <medrano@MIT.EDU>
To: 6042-probs@theory.lcs.MIT.EDU
Subject: Induction
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Induction is more formulaic than deductive proofs and thus much easier to
grasp.  There is not much else I can say about it.  The reading was
straightforward and easy to understand.

Jesus Medrano

From meyer@imap.theory.csail.mit.edu  Fri Sep 23 02:57:52 2005
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While the well-ordering principle (p. 12) is fairly straight forward, I
am wondering if we can see some more examples of what it can be used
for.


From meyer@imap.theory.csail.mit.edu  Fri Sep 23 03:06:32 2005
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Hi Prof Meyer and Rubinfeld,

I found sections 3.2 and 3.3 on pages 10-12 to be confusing. I didn't 
grasp the usage of strong induction in these proofs, though I had 
some vague idea of how they came into play (the P(n+2) for the primes 
and argument: Case (n+1 > 35): etc ... were very confusing). If you 
could go into detail about them, then that would be great.

Thanks,
Kevin


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I would like to have the principle of strong induction, specifically the Product
of Primes example (pp. 10-11) explained more fully. I am a bit confused as to
why you can assume more with the strong induction principle, and also when to
use strong induction as opposed to regular induction.

From meyer@imap.theory.csail.mit.edu  Fri Sep 23 03:51:37 2005
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From: Rachel Shearer <rshearer@MIT.EDU>
Subject: Comment on Induction Reading
Date: Fri, 23 Sep 2005 03:51:31 -0400
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I thought the sections on Strong Induction were confusing and the 
example given didn't make sense to me.  I would appreciate more time 
spent on this in class, especially as it was a large part of the tutor 
problems.

Rachel Shearer


From meyer@imap.theory.csail.mit.edu  Fri Sep 23 03:58:10 2005
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X-Keywords: NonJunk                                                                                                    

I'm still a little confused on the Well Ordering Principle on page 12  
of the reading and how it works.

From meyer@imap.theory.csail.mit.edu  Fri Sep 23 04:11:33 2005
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Subject: Comments for Course Notes, Week 3 (Induction)
From: Moira Racich <mracich@MIT.EDU>
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X-Keywords: NonJunk                                                                                                    

I found section 4, The Well Ordering Principle, (located on page 12)
very surprising.  I was surprised that Strong Induction can be
transformed into the Well Ordering Principle (and vice versa).  I would
be interested in seeing how this is done.  

Moira Racich




From meyer@imap.theory.csail.mit.edu  Fri Sep 23 04:21:32 2005
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On page 12, the notes say:
	"...it turns out that there's a routine way to transform any proof
          using the Well Ordering Principle into a proof using Strong Induction,
          and vice-versa.  (We won't take the time to describe the
          transformations...)"

This surprised me at first, and it is definitely intruiging to me.  When I have
the time, if it isn't covered in class, I think I'll look it up or try it
myself.

From meyer@imap.theory.csail.mit.edu  Fri Sep 23 05:17:22 2005
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Subject: Reading #3 Comments
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The difference between strong induction and simple induction is not 
too clear. If possible, it would be great to have a brief explanation 
of the proof of Lemma 3.1 Every integer greater than 1 is a product 
of primes and why if this is implied why can't we prove that there 
are infinite number of primes?

Thanks,
Manuel Rivas


From meyer@imap.theory.csail.mit.edu  Fri Sep 23 07:51:42 2005
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X-Keywords: NonJunk                                                                                                    

I felt this week's reading was fairly straightforward, so I don't have much to
really complain about.  It might be nice to see the same proposition get proven
by both strong induction and regular induction, since on p11 (product of
primes) it says that if you can do one you can do the other ... just to
compare, I guess, see what situation is best to use which one on, etc.

-Ryan Young

From meyer@imap.theory.csail.mit.edu  Fri Sep 23 08:03:37 2005
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Date: Fri, 23 Sep 2005 07:57:32 -0400
From: Nancy L Keuss <nancyk@MIT.EDU>
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Subject: Reading assignment -- Week 3
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Hi,

The proof of Theorem 2.2 on pages 5-6 (in the "Fibonacci Identity" section)
surprised me. Before the proof you do some work until you reach a useful
assertion (equation 5), and then you begin the proof in the opposite direction,
using your new assertion as a link between P(n) and P(n+1). For the beginner
like me, it was good to see this backwards "scratch work," because a lot of
times proofs look so clean and clever but are not logical flows that would have
occurred to me in the direction in which they're presented in texts, papers,
etc.

Nancy Keuss

From meyer@imap.theory.csail.mit.edu  Fri Sep 23 08:39:31 2005
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From: Alton Torregano <letrec@MIT.EDU>
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X-Keywords: NonJunk                                                                                                    

The section on Inductia proved a little difficult as I'm generally 
unexposed to proof by induction, by cases. Though the proof makes sense, 
I feel that maybe strong induction hides alot of the machinery and 
therefore makes it harder to process. Also, I was confused as to whether 
or not the cases need be made explicit (formally) before use in the 
inductive step. If possible, I would like for this to be explained more 
fully in the next lecture.

From meyer@imap.theory.csail.mit.edu  Fri Sep 23 08:44:28 2005
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Subject: 18.062J Reading Assignment 3
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18.062J Reading Assignment 3

On pg. 10 of the reading, the proof that every integer greater than 1 is a
product of primes confused me.  This reminded me of the false proof that every
horse has the same color.  I don't see how P(0) is true implies P(1) is true.

~Thu Duong

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From: Zachary Adam Ozer <zozer@mit.edu>
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I don't really undertand the horses of the same color theorem. I
understand that the proof fails to show that all horses are of the
same color since it operates on two different sets, and fails to show
that the first set implies the other. Howver, my problem lies with the
assumption that the first n horses are the same color and then that
the last n horses are of the same color on pages 7 and 8 of the course
notes. It seems analagous to assuming that the charachteristic is true
for an n size set and then assuming it it true for the n+1 element and
through these assumption, proving that the assumed charachteristic was
true for all elements to begin with when, in fact, it was just assumed
to be true. In summation, it seems as though an assumption is being
proven with another assumption, which bothers me.

-zozer


From meyer@imap.theory.csail.mit.edu  Fri Sep 23 09:45:25 2005
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From: "David A. Nedzel" <nedzel@MIT.EDU>
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In section 4, I understand the Well Ordering Principle, but what is its
significance to induction?

- David


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X-Keywords: NonJunk                                                                                                    

Strong Induction pg 9

Having learned a bit about induction before I initially thought Strong 
Induction would be more difficult to do because you're working towards a 
more specific goal. However, seeing its applications I was surprised at 
how much simpler and more powerful it is.

From meyer@imap.theory.csail.mit.edu  Fri Sep 23 10:32:20 2005
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From: "Anton Katz" <antonk@MIT.EDU>
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Subject: slightly unclear
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X-Keywords: NonJunk                                                                                                    

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Hi,

 

Two topics are still slightly unclear for me:

Well-ordering and how is it possible to transfer way of proof to another
way. Is it done by math or is there a template to be used in the
transaction? Does this mean that everything that can be proved using
well-ordering can be proved using induction?

 

Second topic is the false proof, I understand that the problem with the
horses proof was that we did not take into account different horses at P(1)
both in the tutorial problems and in the proof in the reading I don't fully
understand where exactly the proof becomes false.

 

Thank you in advance,

 

Anton.

 


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<p class=3DMsoNormal><font size=3D2 face=3DArial><span =
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font-family:Arial'>Hi,<o:p></o:p></span></font></p>

<p class=3DMsoNormal><font size=3D2 face=3DArial><span =
style=3D'font-size:10.0pt;
font-family:Arial'><o:p>&nbsp;</o:p></span></font></p>

<p class=3DMsoNormal><font size=3D2 face=3DArial><span =
style=3D'font-size:10.0pt;
font-family:Arial'>Two topics are still slightly unclear for =
me:<o:p></o:p></span></font></p>

<p class=3DMsoNormal><font size=3D2 face=3DArial><span =
style=3D'font-size:10.0pt;
font-family:Arial'>Well-ordering and how is it possible to transfer way =
of
proof to another way. Is it done by math or is there a template to be =
used in
the transaction? Does this mean that everything that can be proved using
well-ordering can be proved using =
induction?<o:p></o:p></span></font></p>

<p class=3DMsoNormal><font size=3D2 face=3DArial><span =
style=3D'font-size:10.0pt;
font-family:Arial'><o:p>&nbsp;</o:p></span></font></p>

<p class=3DMsoNormal><font size=3D2 face=3DArial><span =
style=3D'font-size:10.0pt;
font-family:Arial'>Second topic is the false proof, I understand that =
the
problem with the horses proof was that we did not take into account =
different horses
at P(1) both in the tutorial problems and in the proof in the reading I =
don&#8217;t
fully understand where exactly the proof becomes =
false.<o:p></o:p></span></font></p>

<p class=3DMsoNormal><font size=3D2 face=3DArial><span =
style=3D'font-size:10.0pt;
font-family:Arial'><o:p>&nbsp;</o:p></span></font></p>

<p class=3DMsoNormal><font size=3D2 face=3DArial><span =
style=3D'font-size:10.0pt;
font-family:Arial'>Thank you in advance,<o:p></o:p></span></font></p>

<p class=3DMsoNormal><font size=3D2 face=3DArial><span =
style=3D'font-size:10.0pt;
font-family:Arial'><o:p>&nbsp;</o:p></span></font></p>

<p class=3DMsoNormal><font size=3D2 face=3DArial><span =
style=3D'font-size:10.0pt;
font-family:Arial'>Anton.<o:p></o:p></span></font></p>

<p class=3DMsoNormal><font size=3D2 face=3DArial><span =
style=3D'font-size:10.0pt;
font-family:Arial'><o:p>&nbsp;</o:p></span></font></p>

</div>

</body>

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Section 3.1
   I'd like to see this discussed in lecture, as I don't think we've 
seen it yet and it'd be good to illuminate the difference between itself 
and regular induction.  Incidentally, I also think that these readings 
and tutor problems should be announced in lecture as well :)

-Pete

-- 
Pete Kruskall
28 The Fenway
Boston, MA 02215

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<font size="-1">Section 3.1<br>
&nbsp;&nbsp; I'd like to see this discussed in lecture, as I don't think we've
seen it yet and it'd be good to illuminate the difference between
itself and regular induction.&nbsp; Incidentally, I also think that these
readings and tutor problems should be announced in lecture as well :)<br>
<br>
-Pete<br>
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<pre class="moz-signature" cols="72">-- 
Pete Kruskall
28 The Fenway
Boston, MA 02215

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508.843.5861 ::::Cell Phone::
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From meyer@imap.theory.csail.mit.edu  Fri Sep 23 10:46:54 2005
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I was wondering if it would be possible to go over Strong Induction more
thoroughly in class.  While I understand that in principle, it is a more
general method of induction, I do not exactly understand how it can be proved
and, well, exactly how one goes about using strong induction.

- Karena

--
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I forgot to include in my last e-mail: I refer to the passage that defines
Strong Induction at the top of page 10.  Specifically, the part that confuses
me is:

"The only change from the ordinary induction principle is that strong induction
allows you to assume more stuff in the inductive step of your proof! ...In a
strong induction argument, you may assume that P(0), P(1), ..., and P(n) are
all true when you go to prove P(n + 1)."

Why are you allowed to assume all these cases?

- Karena

-- 
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Dear .042,
 
It would be great if you give some more examples on the Well Ordered
Problems theorem- in particular, how to convert it from Strong and back. On
paper it seems reasonable, but it'll sink in better with more examples.
 
Thanks!
 
_Yaser

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.042,<o:p></o:p></span></font></p>

<p class=3DMsoNormal><font size=3D2 color=3Dnavy face=3DVerdana><span =
style=3D'font-size:
10.0pt;font-family:Verdana;color:navy'><o:p>&nbsp;</o:p></span></font></p=
>

<p class=3DMsoNormal><font size=3D2 color=3Dnavy face=3DVerdana><span =
style=3D'font-size:
10.0pt;font-family:Verdana;color:navy'>It would be great if you give =
some more
examples on the Well Ordered Problems theorem- in particular, how to =
convert it
from Strong and back. On paper it seems reasonable, but it&#8217;ll sink =
in
better with more examples.<o:p></o:p></span></font></p>

<p class=3DMsoNormal><font size=3D2 color=3Dnavy face=3DVerdana><span =
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<p class=3DMsoNormal><font size=3D2 color=3Dnavy face=3DVerdana><span =
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<p class=3DMsoNormal><font size=3D2 color=3Dnavy face=3DVerdana><span =
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From meyer@imap.theory.csail.mit.edu  Fri Sep 23 11:01:13 2005
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The part I found most confusing was the difference between simple and strong
induction.  I understand both, but I am confused about how to distinguish
between the two like on the pset.

From meyer@imap.theory.csail.mit.edu  Fri Sep 23 11:01:43 2005
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From: Kushan K Surana <kushan@MIT.EDU>
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I am unclear about the well ordering principle. How is it relevant for proofs?

Kushan

From meyer@imap.theory.csail.mit.edu  Fri Sep 23 11:04:11 2005
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In section 3.2 of the reading,  I don't understand the proof entirely.  The 
step that troubles me is the one where we just jump from "k-2  is a natural 
number less than n+1" to "(k-2) +2 is a product of primes by induction 
hypothesis."  I could use more explanation.


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On page 10: "The only change from the ordinary induction principle is
that strong induction allows you to assume more stuff in the inductive
step of your proof!"

So then why do we bother making a distinction between simple induction
and strong induction?

Jason.

From meyer@imap.theory.csail.mit.edu  Fri Sep 23 11:10:24 2005
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Referring to 2.4 Courtyard Tiling (page 6).

I think this is really cool. Its interesting how with induction you can
prove that a certain solution exists even though it does not show you
exactly how to get there (in this case how you would lay the L shaped
tiles).

Jon Stritar

From meyer@imap.theory.csail.mit.edu  Fri Sep 23 11:11:29 2005
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From: "Natalia Chernenko" <natalia3@MIT.EDU>
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The most interesting part of the reading was the tiling problem (section
2.4). I really like visual techniques and it was fun to see a mathematical
proof of a graphic layout. 

 

I am still a bit confused as to the difference between strong induction and
simple induction, though. 

 

Natalia Chernenko


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<p class=3DMsoNormal><font size=3D2 face=3DArial><span =
style=3D'font-size:10.0pt;
font-family:Arial'>The most interesting part of the reading was the =
tiling
problem (section 2.4). I really like visual techniques and it was fun to =
see a
mathematical proof of a graphic layout. <o:p></o:p></span></font></p>

<p class=3DMsoNormal><font size=3D2 face=3DArial><span =
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<p class=3DMsoNormal><font size=3D2 face=3DArial><span =
style=3D'font-size:10.0pt;
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between
strong induction and simple induction, though. =
<o:p></o:p></span></font></p>

<p class=3DMsoNormal><font size=3D2 face=3DArial><span =
style=3D'font-size:10.0pt;
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<p class=3DMsoNormal><font size=3D2 face=3DArial><span =
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font-family:Arial'>Natalia Chernenko<o:p></o:p></span></font></p>

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From meyer@imap.theory.csail.mit.edu  Fri Sep 23 16:53:43 2005
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X-Keywords: NonJunk                                                                                                    

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Hi,

My comments on this week's reading below. I'm sorry for the tardiness, I
didn't check the course website to see when the reading comments were due. =
I
learned my lesson and will check the website more often in the future.
Thanks for your understanding.

The part I found most difficult in the reading was in the last section,
using the Well Ordering Principle to transform a proof into Proof by Strong
Induction. Taken from the reading: "As for useless, it turns out that
there's a routine way to transform any proof using the Well Ordering
Principle into a proof using Strong Induction, and vice-versa. (We won't
take the time to
describe the transformations, though they are not hard.)" (page 12).
I don't quite understand how this transformation can take place, as when
doing Proof by Induction, the base case we choose is usually the least
element (like 0). I think I'd be cool to see some examples of applying the
Principle in Proofs by Strong Induction.

Thanks,
Shreyes Seshasai
Group 7

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Hi,<br>
<br>
My comments on this week's reading below.&nbsp; I'm sorry for the
tardiness, I didn't check the course website to see when the reading
comments were due.&nbsp; I learned my lesson and will check the website
more often in the future.&nbsp; Thanks for your understanding.<br>
<br>
The part I found most difficult in the reading was in the last section,
using the Well Ordering Principle to transform a proof into Proof by
Strong Induction.&nbsp; Taken from the reading: &quot;As for useless, it
turns out that there's a routine way to transform any proof using the
Well Ordering<br>
Principle into a proof using Strong Induction, and vice-versa. (We won't ta=
ke the time to<br>
describe the transformations, though they are not hard.)&quot; (page 12).<b=
r>
I don't quite understand how this transformation can take place, as
when doing Proof by Induction, the base case we choose is usually the
least element (like 0).&nbsp; I think I'd be cool to see some examples
of applying the Principle in Proofs by Strong Induction.<br>
<br>
Thanks,<br>
Shreyes Seshasai<br>
Group 7<br>
<br>
<br>


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From meyer@imap.theory.csail.mit.edu  Fri Sep 23 16:55:07 2005
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I found the comment on page 11 about the ability to prove anything with
ordinary induction that you can with strong induction extremely interesting.
I'm not so clear, though, on how that's possible.

 

            - Aston


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<p class=3DMsoNormal><font size=3D2 face=3DArial><span =
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prove
anything with ordinary induction that you can with strong induction =
extremely
interesting. I&#8217;m not so clear, though, on how that&#8217;s =
possible.<o:p></o:p></span></font></p>

<p class=3DMsoNormal><font size=3D2 face=3DArial><span =
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&nbsp;&nbsp; - Aston<o:p></o:p></span></font></p>

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From meyer@imap.theory.csail.mit.edu  Fri Sep 23 13:25:07 2005
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My simple response would be that when you present a proof, you shouldn't 
state extraneous assumptions.  There's nothing wrong with it logically, 
but it's not good style.

For example,

"a=b, therefore, a^2 = b^2."

is good, but

"a=b, and b=c, therefore, a^2 = b^2."

is not really ideal.

Distinguishing between strong and simple induction allows us to follow 
this "minimal-assumption" convention. 

Let me know if you're still confused.

DS

Jason K Juang wrote:

>On page 10: "The only change from the ordinary induction principle is
>that strong induction allows you to assume more stuff in the inductive
>step of your proof!"
>
>So then why do we bother making a distinction between simple induction
>and strong induction?
>
>Jason.
>  
>


From meyer@imap.theory.csail.mit.edu  Fri Sep 23 13:19:55 2005
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You will see a good example of the WOP today in class - let us know if 
it still confuses you.

The horse proof has a step P(n) -> P(n+1), but the proof of that step 
demanded n>2.  So, what we've proved is:

P(1)
P(3) -> P(4)
P(4) -> P(5)
P(5) -> P(6)
P(6) -> P(7)
...

Do you see that this does not imply P(n) for all n?

DS

Anton Katz wrote:

> Hi,
>
>  
>
> Two topics are still slightly unclear for me:
>
> Well-ordering and how is it possible to transfer way of proof to 
> another way. Is it done by math or is there a template to be used in 
> the transaction? Does this mean that everything that can be proved 
> using well-ordering can be proved using induction?
>
>  
>
> Second topic is the false proof, I understand that the problem with 
> the horses proof was that we did not take into account different 
> horses at P(1) both in the tutorial problems and in the proof in the 
> reading I don't fully understand where exactly the proof becomes false.
>
>  
>
> Thank you in advance,
>
>  
>
> Anton.
>
>  
>


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You will see a good example of the WOP today in class - let us know if
it still confuses you.<br>
<br>
The horse proof has a step P(n) -&gt; P(n+1), but the proof of that
step demanded n&gt;2.&nbsp; So, what we've proved is:<br>
<br>
P(1)<br>
P(3) -&gt; P(4)<br>
P(4) -&gt; P(5)<br>
P(5) -&gt; P(6)<br>
P(6) -&gt; P(7)<br>
...<br>
<br>
Do you see that this does not imply P(n) for all n?<br>
<br>
DS<br>
<br>
Anton Katz wrote:
<blockquote cite="mid200509231432.j8NEWEi0025629@outgoing.mit.edu"
 type="cite">
  <meta http-equiv="Content-Type" content="text/html; ">
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  <p class="MsoNormal"><font face="Arial" size="2"><span
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  <p class="MsoNormal"><font face="Arial" size="2"><span
 style="font-size: 10pt; font-family: Arial;"><o:p>&nbsp;</o:p></span></font></p>
  <p class="MsoNormal"><font face="Arial" size="2"><span
 style="font-size: 10pt; font-family: Arial;">Two topics are still
slightly unclear for me:<o:p></o:p></span></font></p>
  <p class="MsoNormal"><font face="Arial" size="2"><span
 style="font-size: 10pt; font-family: Arial;">Well-ordering and how is
it possible to transfer way of
proof to another way. Is it done by math or is there a template to be
used in
the transaction? Does this mean that everything that can be proved
using
well-ordering can be proved using induction?<o:p></o:p></span></font></p>
  <p class="MsoNormal"><font face="Arial" size="2"><span
 style="font-size: 10pt; font-family: Arial;"><o:p>&nbsp;</o:p></span></font></p>
  <p class="MsoNormal"><font face="Arial" size="2"><span
 style="font-size: 10pt; font-family: Arial;">Second topic is the false
proof, I understand that the
problem with the horses proof was that we did not take into account
different horses
at P(1) both in the tutorial problems and in the proof in the reading I
don&#8217;t
fully understand where exactly the proof becomes false.<o:p></o:p></span></font></p>
  <p class="MsoNormal"><font face="Arial" size="2"><span
 style="font-size: 10pt; font-family: Arial;"><o:p>&nbsp;</o:p></span></font></p>
  <p class="MsoNormal"><font face="Arial" size="2"><span
 style="font-size: 10pt; font-family: Arial;">Thank you in advance,<o:p></o:p></span></font></p>
  <p class="MsoNormal"><font face="Arial" size="2"><span
 style="font-size: 10pt; font-family: Arial;"><o:p>&nbsp;</o:p></span></font></p>
  <p class="MsoNormal"><font face="Arial" size="2"><span
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From meyer@imap.theory.csail.mit.edu  Fri Sep 23 12:44:05 2005
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From: Sayan Mitra <mitras@theory.csail.mit.edu>
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If a set W is well ordered then you can induct on its
elements to prove the property in question.
This may sound a little vague now but it will become clearer as we do more examples in class and in problem sets. Drop by in the office hours if you still have questions.

-Sayan


>From nedzel@MIT.EDU Fri Sep 23 09:45:25 2005
From: "David A. Nedzel" <nedzel@MIT.EDU>
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Subject: Week 3 Comments
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In section 4, I understand the Well Ordering Principle, but what is its
significance to induction?

- David



From meyer@imap.theory.csail.mit.edu  Fri Sep 23 12:25:48 2005
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you'll see one very nice application of the well ordering principle today.
-sayan


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From: Jelani Nelson <minilek@mit.edu>
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Ok.  If you find anything unclear later, feel free to ask.

-Jelani

On 9/23/05, r n jacobs <rnjacobs@mit.edu> wrote:
>
> The one on the tutor questions. I identified what was wrong fairly
> fast (It wasn't proven for n=1), but it took me /forever/ to figure
> out which line technically had the flaw.
>
> (I also still find the "every number is a product of primes" proof
> (3.2, pg10) confusing. But I /think/ I understand strong induction
> now.)
>
>  - robert
>
> > Which fibonacci misproof?  If you are talking about the fibonacci
> > identity proven in the lecture notes, the identity is correct, and it is
> > correctly proven using plain old induction (not strong induction).
> >
> > -Jelani
> >
> > r n jacobs wrote:
> >
> > >I found myself confused by the explanation of Strong
> > >Induction. Although maybe the fibbonaci proof helped that. (The
> > >definition made sense, but it took far to long for me to figure out
> > >the answer to the fibbonaci misproof)
>


From meyer@imap.theory.csail.mit.edu  Fri Sep 23 18:34:50 2005
Message-ID: <43348308.5040000@csail.mit.edu>
Date: Fri, 23 Sep 2005 18:34:48 -0400
From: "Prof. Albert R. Meyer" <meyer@csail.mit.edu>
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To: Karena Tyan <kktyan@MIT.EDU>
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Subject: Re: Reading 3: Induction
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I hope today's class clarified things some, but here's one way to 
understand why all the extra P's can be assumed:

think of the falling dominoes explanation of induction: if you knock 
over the 1st domino, and knocking over the nth domino will cause the 
next (n+1st) one to get knocked over, then you can conclude by simple 
induction that they all will get knocked over.  But when the cascade of 
falling dominoes gets to the n+1st, all the previous ones will have been 
knocked over already, so it's perfectly ok to use that fact in reasoning 
about how the n+1st one falls.

If you're still feeling shaky about this, I'll second Hanson's 
suggestion that you take it up with a TA is office hours.  I'd also be 
happy to meet you after classs or make some other appt with you to talk 
about this.

regards, A.

Karena Tyan wrote:

>I forgot to include in my last e-mail: I refer to the passage that defines
>Strong Induction at the top of page 10.  Specifically, the part that confuses
>me is:
>
>"The only change from the ordinary induction principle is that strong induction
>allows you to assume more stuff in the inductive step of your proof! ...In a
>strong induction argument, you may assume that P(0), P(1), ..., and P(n) are
>all true when you go to prove P(n + 1)."
>
>Why are you allowed to assume all these cases?
>
>- Karena
>
>  
>


From meyer@imap.theory.csail.mit.edu  Fri Sep 23 18:23:07 2005
BCC: Ronitt Rubinfeld <ronitt@theory.csail.mit.edu>
Message-ID: <43348049.9070206@csail.mit.edu>
Date: Fri, 23 Sep 2005 18:23:05 -0400
From: "Prof. Albert R. Meyer" <meyer@csail.mit.edu>
Organization: MIT CSAIL
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Subject: Re: Reading 3: Induction
References: <20050923104849.gdiofdwamw0kwco8@webmail.mit.edu> <Pine.LNX.4.58.0509231144590.16089@blackbird.csail.mit.edu>
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I think your answer to this student is insulting: she has done the 
reading and is asking about it -- and your advice is to do the reading 
(again?).  I'll respond to her further.
regards, A.

Hanson Zhou wrote:

>You are essentially asking what strong induction is and you should read
>about it.  If it remains confusing, go to office hours to get this cleared
>up.
>
>-Hanson
>
>On Fri, 23 Sep 2005, Karena Tyan wrote:
>
>  
>
>>I forgot to include in my last e-mail: I refer to the passage that defines
>>Strong Induction at the top of page 10.  Specifically, the part that confuses
>>me is:
>>
>>"The only change from the ordinary induction principle is that strong induction
>>allows you to assume more stuff in the inductive step of your proof! ...In a
>>strong induction argument, you may assume that P(0), P(1), ..., and P(n) are
>>all true when you go to prove P(n + 1)."
>>
>>Why are you allowed to assume all these cases?
>>
>>- Karena
>>
>>--
>>410 Memorial Drive
>>Cambridge, MA 02139
>>(585)957-5923
>>
>>    
>>


From meyer@imap.theory.csail.mit.edu  Fri Sep 23 13:25:09 2005
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My simple response would be that when you present a proof, you shouldn't 
state extraneous assumptions.  There's nothing wrong with it logically, 
but it's not good style.

For example,

"a=b, therefore, a^2 = b^2."

is good, but

"a=b, and b=c, therefore, a^2 = b^2."

is not really ideal.

Distinguishing between strong and simple induction allows us to follow 
this "minimal-assumption" convention. 

Let me know if you're still confused.

DS

Jason K Juang wrote:

>On page 10: "The only change from the ordinary induction principle is
>that strong induction allows you to assume more stuff in the inductive
>step of your proof!"
>
>So then why do we bother making a distinction between simple induction
>and strong induction?
>
>Jason.
>  
>

From meyer@imap.theory.csail.mit.edu  Fri Sep 23 13:19:57 2005
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You will see a good example of the WOP today in class - let us know if 
it still confuses you.

The horse proof has a step P(n) -> P(n+1), but the proof of that step 
demanded n>2.  So, what we've proved is:

P(1)
P(3) -> P(4)
P(4) -> P(5)
P(5) -> P(6)
P(6) -> P(7)
...

Do you see that this does not imply P(n) for all n?

DS

Anton Katz wrote:

> Hi,
>
>  
>
> Two topics are still slightly unclear for me:
>
> Well-ordering and how is it possible to transfer way of proof to 
> another way. Is it done by math or is there a template to be used in 
> the transaction? Does this mean that everything that can be proved 
> using well-ordering can be proved using induction?
>
>  
>
> Second topic is the false proof, I understand that the problem with 
> the horses proof was that we did not take into account different 
> horses at P(1) both in the tutorial problems and in the proof in the 
> reading I don't fully understand where exactly the proof becomes false.
>
>  
>
> Thank you in advance,
>
>  
>
> Anton.
>
>  
>


--------------000209080207090105030401
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</head>
<body bgcolor="#ffffff" text="#000000">
You will see a good example of the WOP today in class - let us know if
it still confuses you.<br>
<br>
The horse proof has a step P(n) -&gt; P(n+1), but the proof of that
step demanded n&gt;2.&nbsp; So, what we've proved is:<br>
<br>
P(1)<br>
P(3) -&gt; P(4)<br>
P(4) -&gt; P(5)<br>
P(5) -&gt; P(6)<br>
P(6) -&gt; P(7)<br>
...<br>
<br>
Do you see that this does not imply P(n) for all n?<br>
<br>
DS<br>
<br>
Anton Katz wrote:
<blockquote cite="mid200509231432.j8NEWEi0025629@outgoing.mit.edu"
 type="cite">
  <meta http-equiv="Content-Type" content="text/html; ">
  <meta name="Generator" content="Microsoft Word 11 (filtered medium)">
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  <p class="MsoNormal"><font face="Arial" size="2"><span
 style="font-size: 10pt; font-family: Arial;">Hi,<o:p></o:p></span></font></p>
  <p class="MsoNormal"><font face="Arial" size="2"><span
 style="font-size: 10pt; font-family: Arial;"><o:p>&nbsp;</o:p></span></font></p>
  <p class="MsoNormal"><font face="Arial" size="2"><span
 style="font-size: 10pt; font-family: Arial;">Two topics are still
slightly unclear for me:<o:p></o:p></span></font></p>
  <p class="MsoNormal"><font face="Arial" size="2"><span
 style="font-size: 10pt; font-family: Arial;">Well-ordering and how is
it possible to transfer way of
proof to another way. Is it done by math or is there a template to be
used in
the transaction? Does this mean that everything that can be proved
using
well-ordering can be proved using induction?<o:p></o:p></span></font></p>
  <p class="MsoNormal"><font face="Arial" size="2"><span
 style="font-size: 10pt; font-family: Arial;"><o:p>&nbsp;</o:p></span></font></p>
  <p class="MsoNormal"><font face="Arial" size="2"><span
 style="font-size: 10pt; font-family: Arial;">Second topic is the false
proof, I understand that the
problem with the horses proof was that we did not take into account
different horses
at P(1) both in the tutorial problems and in the proof in the reading I
don&#8217;t
fully understand where exactly the proof becomes false.<o:p></o:p></span></font></p>
  <p class="MsoNormal"><font face="Arial" size="2"><span
 style="font-size: 10pt; font-family: Arial;"><o:p>&nbsp;</o:p></span></font></p>
  <p class="MsoNormal"><font face="Arial" size="2"><span
 style="font-size: 10pt; font-family: Arial;">Thank you in advance,<o:p></o:p></span></font></p>
  <p class="MsoNormal"><font face="Arial" size="2"><span
 style="font-size: 10pt; font-family: Arial;"><o:p>&nbsp;</o:p></span></font></p>
  <p class="MsoNormal"><font face="Arial" size="2"><span
 style="font-size: 10pt; font-family: Arial;">Anton.<o:p></o:p></span></font></p>
  <p class="MsoNormal"><font face="Arial" size="2"><span
 style="font-size: 10pt; font-family: Arial;"><o:p>&nbsp;</o:p></span></font></p>
  </div>
</blockquote>
<br>
</body>
</html>

--------------000209080207090105030401--

From meyer@imap.theory.csail.mit.edu  Fri Sep 23 18:54:04 2005
Message-ID: <4334878A.6000409@csail.mit.edu>
Date: Fri, 23 Sep 2005 18:54:02 -0400
From: "Prof. Albert R. Meyer" <meyer@csail.mit.edu>
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It was a dense 10 or so pages of reading, and even if you knew and 
understood it all, I can't believe you found it all equally well :-) 
explained, with enough examples, etc.  Also, do you see how Well 
Ordering proofs can be converted to Induction proofs, and vice-versa?-- 
that was tricky.

 I'll look forward to more responsive comments from you next week.

regards, A.

Angelique E Moscicki wrote:

>Sorry there isn't as much this time, its just rather more familiar material.
>


From meyer@imap.theory.csail.mit.edu  Sat Sep 24 02:41:44 2005
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Hello,

My apologies for the late comment, I completely forgot to send this earlier.

"The Well Ordering Principle looks nothing like the induction axiom, and 
it may seem obvious but useless" -pg 12

I agreed with this sentiment, probably because using Well Ordering in 
proofs seems so backwards and counterintuitive. I think it would be cool 
to do a bunch of Well Ordering proofs to try and develop a little more 
intuition for them.

Cheers,
~Ben

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On page 3-4 i nthe reading is the template for the induction proof. When  we do
proofs in clas, I don't completely understand which parts of the proof
correspond to which parts of the template.

-Rebecca Idell
-- 
Rebecca Idell
Massachusetts Institute of Technology
Electrical Engineering and Computer Science, Class of 2007

479 Commonwealth Avenue
Boston, MA 02215
(617) 875-0889

From meyer@imap.theory.csail.mit.edu  Mon Sep 26 08:23:25 2005
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Date: Mon, 26 Sep 2005 08:23:26 -0400
From: "Prof. Albert R. Meyer" <meyer@csail.mit.edu>
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To: Benjamin Lu <benlu@MIT.EDU>
Subject: Re: [6.042] comments on reading 3
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Was Friday lecture cool enough? :-)
Regards, A.

Benjamin Lu wrote:

> Hello,
>
> My apologies for the late comment, I completely forgot to send this 
> earlier.
>
> "The Well Ordering Principle looks nothing like the induction axiom, 
> and it may seem obvious but useless" -pg 12
>
> I agreed with this sentiment, probably because using Well Ordering in 
> proofs seems so backwards and counterintuitive. I think it would be 
> cool to do a bunch of Well Ordering proofs to try and develop a little 
> more intuition for them.
>
> Cheers,
> ~Ben



