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From: Jelani Nelson <minilek@mit.edu>
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Nancy,

Regarding why false implies everything. A-->B in English basically means=20
"whenever A is true, B is true". But if A is actually the literal "False",=
=20
then A is never true. So the statement that "whenever A is true, B is true"=
=20
is what we call *vacuously true*. In other words, it is true that whenever =
A=20
is true B is true, because A is never true. Let me know if this cleared=20
things up.

-Jelani
------------------------------------------------------------------------
Hi, here are my Week 2 and Week 1 comments:


Week 2 Reading -- "Predicates and Sets":

Passage 3.5 "Functions -- Lemma (Mapping Rule)," pg 12:

At first I struggled with the implication in the first bullet ( If f : A ->=
=20
B
is surjective, then |A| >=3D |B|. ). I thought the proposition needed to=20
mention
surjective *and* total. Only after doing the online tutor problems did I
realize that the implication is valid because a function can only have one
y-value for each x-value (or only one resulting value for each argument to=
=20
the
function).

---------------------------------------------------------------------------


Week 1 Reading -- "Proofs":

Passage 7.1.2 "Implies," pg. 12:

Even after careful reading, for some reason I still don't understand the=20
truth
table results of "P implies Q" or "if P then Q." The summary statement at=
=20
the
end of 7.1.2 ("An implication is true when the if-part is false or the
then-part is true") is a very helpful rule, but I found the basic logic of=
=20
the
table difficult. Why does false imply true and false imply false?




-- Nancy Keuss

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Nancy,<br>
<br>
Regarding why false implies everything.&nbsp; A--&gt;B in English
basically means &quot;whenever A is true, B is true&quot;.&nbsp; But if A i=
s
actually the literal &quot;False&quot;, then A is never true.&nbsp; So the
statement that &quot;whenever A is true, B is true&quot; is what we call
*vacuously true*.&nbsp; In other words, it is true that whenever A is
true B is true, because A is never true.&nbsp; Let me know if this
cleared things up.<br>
<br>
-Jelani<br>
------------------------------------------------------------------------<br=
>
Hi, here are my Week 2 and Week 1 comments:<br>
<br>
<br>
Week 2 Reading -- &quot;Predicates and Sets&quot;:<br>
<br>
Passage 3.5 &quot;Functions -- Lemma (Mapping Rule),&quot; pg 12:<br>
<br>
At first I struggled with the implication in the first bullet ( If&nbsp; f =
: A -&gt; B<br>
is surjective, then |A| &gt;=3D |B|. ). I thought the proposition needed to=
 mention<br>
surjective *and* total. Only after doing the online tutor problems did I<br=
>
realize that the implication is valid because a function can only have one<=
br>
y-value for each x-value (or only one resulting value for each argument to =
the<br>
function).<br>
<br>
---------------------------------------------------------------------------=
<br>
<br>
<br>
Week 1 Reading -- &quot;Proofs&quot;:<br>
<br>
Passage 7.1.2 &quot;Implies,&quot; pg. 12:<br>
<br>
Even after careful reading, for some reason I still don't understand the tr=
uth<br>
table results of &quot;P implies Q&quot; or &quot;if P then Q.&quot; The su=
mmary statement at the<br>
end of 7.1.2 (&quot;An implication is true when the if-part is false or the=
<br>
then-part is true&quot;) is a very helpful rule, but I found the basic logi=
c of the<br>
table difficult. Why does false imply true and false imply false?<br>
<br>
<br>
<br>
<br>
-- Nancy Keuss

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Ben,

S =3D {x | P(x) } is the set of all elements x such that P(x) is true. If=
=20
you've used Scheme before, you can think of it as "filter" in Scheme.
So what the statement was saying was, a function is defined by its domain=
=20
(where it maps from), codomain (where it maps to), and the set of pairs=20
(a,b) such that f(a) =3D b (how it maps the elements).

-Jelani
---------------------------------------------------------------------------=
-------------
"Everything about a function is captured by three sets: its domain, its=20
codomain, and the set {(a,b)|f(a)=3Db} which is called the graph of f."

This was the most confusing thing in the reading for me because I have=20
never seen a formal definition of functions before and I am somewhat=20
unfamiliar with a lot of the notation. Specifically, what does the bar=20
between the sequence and the statement mean? How would that set be read=20
aloud?

Cheers,
~Ben

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Ben,<br>
<br>
S =3D {x | P(x) } is the set of all elements x such that P(x) is
true.&nbsp; If you've used Scheme before, you can think of it as
&quot;filter&quot; in Scheme.<br>
So what the statement was saying was, a function is defined by its
domain (where it maps from), codomain (where it maps to), and the set
of pairs (a,b) such that f(a) =3D b (how it maps the elements).<br>
<br>
-Jelani<br>
---------------------------------------------------------------------------=
-------------<br>
&quot;Everything about a function is captured by three sets: its domain, it=
s <br>
codomain, and the set {(a,b)|f(a)=3Db} which is called the graph of f.&quot=
;<br>
<br>
This was the most confusing thing in the reading for me because I have <br>
never seen a formal definition of functions before and I am somewhat <br>
unfamiliar with a lot of the notation. Specifically, what does the bar <br>
between the sequence and the statement mean? How would that set be read <br=
>
aloud?<br>
<br>
Cheers,<br>
~Ben<br>

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Clinton,

If A is equal to B, then A is a subset of B. A "proper subset" though is a=
=20
subset that is not equal to the set itself, so A would not be a proper=20
subset of B. Let me know if there were any other confusing terms or=20
notation.

-Jelani
---------------------------------------------------------------------------=
-------------
Section 3.2, page 9.



The subset notations are confusing. What exactly is the difference between =
.
Are there better examples?



Never mind. I see now that the difference occurs in conditional statements.
Although, if A is equal to B, does A not qualify as a subset of B?=20



Either way, I found this difficult as it took me a few read-throughs and
this email to understand.



----

Clinton C. Blackburn

MIT Class of 2008

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Arup,

In general, it suffices to prove something false by just giving a=20
counter-example. What did you have in mind when you said a more general way=
?=20
For example, even though it is not a validity it can still be true for some=
=20
predicates P. Consider the predicate P(x,y) =3D True.

-Jelani
---------------------------------------------------------------------------=
--------
Section 2.6, page 8:

I would like to have the last (false) assertion explained more=20
fully. While I understand the proof for why it would not be true, I=20
want to know if there is any more general way of understanding it=20
besides the example given, since at first glance it does not appear=20
to be incorrect.

|Arup|

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Arup,<br>
<br>
In general, it suffices to prove something false by just giving a
counter-example.&nbsp; What did you have in mind when you said a more
general way?&nbsp; For example, even though it is not a validity it can
still be true for some predicates P.&nbsp; Consider the predicate
P(x,y) =3D True.<br>
<br>
-Jelani<br>
---------------------------------------------------------------------------=
--------<br>
Section 2.6, page 8:<br>
<br>
I would like to have the last (false) assertion explained more <br>
fully.&nbsp; While I understand the proof for why it would not be true, I <=
br>
want to know if there is any more general way of understanding it <br>
besides the example given, since at first glance it does not appear <br>
to be incorrect.<br>
<br>
|Arup|

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Sameer,

Are you still confused by the definitions of surjective, injective, and=20
bijective? If so, let me know tomorrow
in class and I'll try to better explain them.

-Jelani
---------------------------------------------------------------------------=
--------------
One aspect I would like to have explained in class further is (3.5=20
Functions, page 11) where surjectives, injectives, and bijectives are=20
explained. The terminology here is confusing, and it would be useful to=20
go over the Lemma and definitions once more.

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Sameer,<br>
<br>
Are you still confused by the definitions of surjective, injective, and bij=
ective?&nbsp; If so, let me know tomorrow<br>
in class and I'll try to better explain them.<br>
<br>
-Jelani<br>
---------------------------------------------------------------------------=
--------------<br>
One aspect I would like to have explained in class further is (3.5 <br>
Functions, page 11) where surjectives, injectives, and bijectives are <br>
explained.&nbsp; The terminology here is confusing, and it would be useful =
to <br>
go over the Lemma and definitions once more. <br>

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Scot,

The truth table for implies is basically saying True implies only True, and=
=20
False implies anything. The contrapositive says if A implies B, then not B=
=20
implies not A. Before looking at the truth tables, you can try to reason=20
about it. If A implies B, that means whenever A is true then B must be true=
.=20
So if B isn't true, then A couldn't be true either (because if it were, it=
=20
would imply B were true, which we said it isn't). Think about it for a=20
little, and let me know if you still have questions.

-Jelani
---------------------------------------------------------------------------=
-----
Hello,

In Week 1 readings, on page 15, I found it more difficult to understand=20
the contrapositive. In lecture I thought it made sense, but even some=20
aspects of the 'implies' truth table also seem confusing.

Scot Frank

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Scot,<br>
<br>
The truth table for implies is basically saying True implies only True,
and False implies anything.&nbsp; The contrapositive says if A implies
B, then not B implies not A.&nbsp; Before looking at the truth tables,
you can try to reason about it.&nbsp; If A implies B, that means
whenever A is true then B must be true.&nbsp; So if B isn't true, then
A couldn't be true either (because if it were, it would imply B were
true, which we said it isn't).&nbsp; Think about it for a little, and
let me know if you still have questions.<br>
<br>
-Jelani<br>
---------------------------------------------------------------------------=
-----<br>
Hello,<br>
<br>
In Week 1 readings, on page 15, I found it more difficult to understand <br=
>
the contrapositive. In lecture I thought it made sense, but even some <br>
aspects of the 'implies' truth table also seem confusing.<br>
<br>
Scot Frank

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Natalia,

With long lists of statements, order matters and you should begin reading=
=20
from the left

That is to say:

there exists a, there exists b, there exists c, for all d P(a,b,c,d)

is the same as

there exists a (there exists b (there exists c (for all d P(a,b,c,d))))

In this case parentheses didn't matter. But, parentheses in predicates=20
matter for cases such as the following:

(P ^ (Q v R)) v S

vs.

P ^ (Q v R v S)

The first says that either S is true, or P is true and one of Q and R is=20
true.
The second says that P is true and one of Q,R,S is true.

In particular, S=3DTrue, P=3DQ=3DR=3DFalse makes the first one evaluate to =
true but=20
the second one evaluate to false. For 2.4.1 in the reading, the parentheses=
=20
weren't incorrect, but they didn't add any extra information.

Please let me know if you still have questions.

-Jelani
---------------------------------------------------------------------------=
-------------
The part I had the most trouble with was the notation. It became
especially difficult in parts 2.2 through 2.4 (pp. 6-7). I am not sure
how to interpret long lists of statements, such as in 2.4, and also how
to read the meaning of parentheses when predicates are enclosed within
them (2.4.1).=20

Natalia Chernenko

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Natalia,<br>
<br>
With long lists of statements, order matters and you should begin reading f=
rom the left<br>
<br>
That is to say:<br>
<br>
there exists a, there exists b, there exists c, for all d P(a,b,c,d)<br>
<br>
is the same as<br>
<br>
there exists a (there exists b (there exists c (for all d P(a,b,c,d))))<br>
<br>
In this case parentheses didn't matter.&nbsp; But, parentheses in predicate=
s matter for cases such as the following:<br>
<br>
(P ^ (Q v R)) v S<br>
<br>
vs.<br>
<br>
P ^ (Q v R v S)<br>
<br>
The first says that either S is true, or P is true and one of Q and R is tr=
ue.<br>
The second says that P is true and one of Q,R,S is true.<br>
<br>
In particular, S=3DTrue, P=3DQ=3DR=3DFalse makes the first one evaluate to =
true
but the second one evaluate to false.&nbsp; For 2.4.1 in the reading,
the parentheses weren't incorrect, but they didn't add any extra
information.<br>
<br>
Please let me know if you still have questions.<br>
<br>
-Jelani<br>
---------------------------------------------------------------------------=
-------------<br>
The part I had the most trouble with was the notation. It became<br>
especially difficult in parts 2.2 through 2.4 (pp. 6-7). I am not sure<br>
how to interpret long lists of statements, such as in 2.4, and also how<br>
to read the meaning of parentheses when predicates are enclosed within<br>
them (2.4.1). <br>
<br>
Natalia Chernenko&nbsp; <br>

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Crystal,

The case with 4 strangers and a pair who knows each other is actually=20
covered by our cases.

We picked an x, and Case 2 says that at least 3 people have not met x. If=
=20
there are 4 strangers and a pair who know each other, we will be in Case 2.=
=20
The, we will get into Case 2.2 which says that at least one pair of people=
=20
haven't met each other, and we will conclude that there is a group of at=20
least 3 strangers (which is true, since there are 4).

Please let me know if this made things clearer. If you still have questions=
,=20
feel free to email me or ask me in class or office hours.

-Jelani
---------------------------------------------------------------------------=
-
I was confused by the strangers/clubs proof by case analysis (p.=20
3-4), especially cases 1.2 and 2.2. How does one know there isn't a=20
set of, say, four strangers, and then a pair who knows each other? I=20
mean, I trust that it works, but I got lost in all the wording. I=20
think a visual depiction of the problem would have been effective.=20
(Also, just so you know, there is a small typo on p. 3; it says,=20
"Among... at least 3 have did not met x.")

~Crystal

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Crystal,<br>
<br>
The case with 4 strangers and a pair who knows each other is actually cover=
ed by our cases.<br>
<br>
We picked an x, and Case 2 says that at least 3 people have not met
x.&nbsp; If there are 4 strangers and a pair who know each other, we
will be in Case 2.&nbsp; The, we will get into Case 2.2 which says that
at least one pair of people haven't met each other, and we will
conclude that there is a group of at least 3 strangers (which is true,
since there are 4).<br>
<br>
Please let me know if this made things clearer.&nbsp; If you still have
questions, feel free to email me or ask me in class or office hours.<br>
<br>
-Jelani<br>
---------------------------------------------------------------------------=
-<br>
I was confused by the strangers/clubs proof by case analysis (p. &nbsp;<br>
3-4), especially cases 1.2 and 2.2. How does one know there isn't a &nbsp;<=
br>
set of, say, four strangers, and then a pair who knows each other? I &nbsp;=
<br>
mean, I trust that it works, but I got lost in all the wording. I &nbsp;<br=
>
think a visual depiction of the problem would have been effective. &nbsp;<b=
r>
(Also, just so you know, there is a small typo on p. 3; it says, &nbsp;<br>
&quot;Among... at least 3 have did not met x.&quot;)<br>
<br>
~Crystal

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With set builder notation, we say things like S =3D {a in A | P (a)}. You c=
an=20
read the | as a "such that", so what this is saying is that S consists of=
=20
all elements a in A such that P(a) is true.

Please let me know if you are still confused about the definitions of total=
,=20
surjective, injective, and bijective. If so, I'd be happy to go over them=
=20
with you with examples.

-Jelani

------------------------------------------------------------------------
I found set builder notation (pg 10) and functions (pg 11) most=20
confusing. I would not be able to describe a set using the words=20
total, surjective, injective, or bijective.

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With set builder notation, we say things like S =3D {a in A | P
(a)}.&nbsp; You can read the | as a &quot;such that&quot;, so what this is =
saying
is that S consists of all elements a in A such that P(a) is true.<br>
<br>
Please let me know if you are still confused about the definitions of
total, surjective, injective, and bijective.&nbsp; If so, I'd be happy
to go over them with you with examples.<br>
<br>
-Jelani<br>
<br>
------------------------------------------------------------------------<br=
>
I found set builder notation (pg 10) and functions (pg 11) most <br>
confusing.&nbsp; I would not be able to describe a set using the words <br>
total, surjective, injective, or bijective.

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From: Jelani Nelson <minilek@mit.edu>
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Adriana,

>> I was wondering, is there a way to say "P(n) is true for exactly one n" =
?
Yes. You could say that there exists an n such that P(n), and for all m P(m=
)=20
implies m =3D n.

>> for exactly m n's where m is an integer greater than 1?
This can be done also, and I'll let you think about it as practice. As a=20
hint, consider trying to modify the solution for "P(n) is true for exactly=
=20
one n".

-Jelani

----------------------------------------------------------------------
In the readings for week 2, on page 5:

"Sometimes True:
There exists an n such that P(n) is true.
P(n) is true for some n.
P(n) is true for at least one n."

I was wondering, is there a way to say "P(n) is true for exactly one n" ?=
=20
for at
most one n? for exactly m n's where m is an integer greater than 1?

I would like this to be discussed more fully in class.

Adriana Lopez

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Adriana,<br>
<br>
&gt;&gt; I was wondering, is there a way to say &quot;P(n) is true for exac=
tly one n&quot; ?<br>
Yes.&nbsp; You could say that there exists an n such that P(n), and for all=
 m P(m) implies m =3D n.<br>
<br>
&gt;&gt; for exactly m n's where m is an integer greater than 1?<br>
This can be done also, and I'll let you think about it as
practice.&nbsp; As a hint, consider trying to modify the solution for
&quot;P(n) is true for exactly one n&quot;.<br>
<br>
-Jelani<br>
<br>
----------------------------------------------------------------------<br>
In the readings for week 2, on page 5:<br>
<br>
&quot;Sometimes True:<br>
There exists an n such that P(n) is true.<br>
P(n) is true for some n.<br>
P(n) is true for at least one n.&quot;<br>
<br>
I was wondering, is there a way to say &quot;P(n) is true for exactly one n=
&quot; ? for at<br>
most one n?&nbsp; for exactly m n's where m is an integer greater than 1?<b=
r>
<br>
I would like this to be discussed more fully in class.<br>
<br>
Adriana Lopez

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Notationally speaking, computability people have already come up with their=
=20
own style for dealing with exactly this. They say a "language" is just a se=
t=20
of strings over some alphabet. They then say an algorithm A "decides" a=20
language L if A always halts when given an input, and it returns true=20
("accepts" the input) if the input was in L and it rejects otherwise. So=20
using this framework you could ask things like, "does there exist an=20
algorithm that decides the language consisting of all predicates?".

If you're interested in this, you should read "Introduction to the Theory o=
f=20
Computation" by Michael Sipser, or take 6.840, which he teaches.

-Jelani

**
---------------------------------------------------------------------------=
------------
I think Predicate notation (pg. 4) is very cool, because it allows us to=20
write functions f:<anything> -> {T,F}. In particular, it would be cool=20
to think about predicates whose arguments are logical statements. That=20
might provide a good notation for reasoning about theorem-provers and=20
computability.

-Ben

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Notationally speaking, computability people have already come up with
their own style for dealing with exactly this.&nbsp; They say a
&quot;language&quot; is just a set of strings over some alphabet.&nbsp; The=
y then
say an algorithm A &quot;decides&quot; a language L if A always halts when =
given
an input, and it returns true (&quot;accepts&quot; the input) if the input =
was in
L and it rejects otherwise.&nbsp; So using this framework you could ask
things like, &quot;does there exist an algorithm that decides the language
consisting of all predicates?&quot;.<br>
<br>
If you're interested in this, you should read &quot;<font size=3D"-1">Intro=
duction to the </font>Theory of Computation&quot; by Michael Sipser, or tak=
e 6.840, which he teaches.<br>
<br>
-Jelani<br>
<br>
<font size=3D"-1"><b></b></font>-------------------------------------------=
--------------------------------------------<br>
I think Predicate notation (pg. 4) is very cool, because it allows us to <b=
r>
write functions f:&lt;anything&gt; -&gt; {T,F}.&nbsp; In particular, it wou=
ld be cool <br>
to think about predicates whose arguments are logical statements.&nbsp; Tha=
t <br>
might provide a good notation for reasoning about theorem-provers and <br>
computability.<br>
<br>
-Ben

From meyer@imap.theory.csail.mit.edu  Thu Sep 15 15:13:56 2005
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From: Yuhsin Chen <yuhsin@MIT.EDU>
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I just realized that I didn't turn in my reading comment or the online 
tutor problem. I'm very sorry, I was mixed up on the dates. Now that I'm 
off on a bad start, would you suggest that I drop the class and take it 
again at some later date, or should I keep trying?

Yuhsin (Joyce) Chen

The comment I found most interesting in the reading over Sets and 
Functions was in section 2.4, page 6, regarding Order of Quantifiers. Had 
I submitted it in on time, I would've liked to have a chance to go over 
how order influences the logical flow in lecture. (not directly related to 
the reading, I also found prefixing "not" in front of a proposition 
surprising--"not all P are true" is equivalent to "there exists P that is 
false". Perhaps I am just very interested in how many ways a proposition 
can be transformed).





From meyer@imap.theory.csail.mit.edu  Thu Sep 15 15:24:31 2005
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Date: Thu, 15 Sep 2005 15:24:41 -0400
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I won't penalize you for your late email comments.  It's good that you 
asked.

And for goodness sake, I hope you won't consider dropping again in the 
event of another such minor problem! (Do the Math: online tutor + email 
totals 5% of the final grade, of which the email is about half.  There 
are about a dozen required emails, and being a day late would get you 
part credit anyway.  So even if I did penalize you, it would be for an 
imperceptible 0.1% of your grade.)

Anyway, it will be a pleasure to have you continue in the course.  I 
hope you enjoy it.

Regards, A.

Yuhsin Chen wrote:
> I just realized that I didn't turn in my reading comment or the online 
> tutor problem. I'm very sorry, I was mixed up on the dates. Now that I'm 
> off on a bad start, would you suggest that I drop the class and take it 
> again at some later date, or should I keep trying?
> 
> Yuhsin (Joyce) Chen
> 
> The comment I found most interesting in the reading over Sets and 
> Functions was in section 2.4, page 6, regarding Order of Quantifiers. 
> Had I submitted it in on time, I would've liked to have a chance to go 
> over how order influences the logical flow in lecture. (not directly 
> related to the reading, I also found prefixing "not" in front of a 
> proposition surprising--"not all P are true" is equivalent to "there 
> exists P that is false". Perhaps I am just very interested in how many 
> ways a proposition can be transformed).
> 
> 
> 
> 


From meyer@imap.theory.csail.mit.edu  Fri Sep 16 00:16:19 2005
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ZFC was introduced in Week 1 Notes, pp.4--5.  Did you read them?

Regards, A.

Zev Benjamin wrote:
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 > The most difficult section I found in the reading was 3.5 Functions
 > (page 11).  The various terms and their definitions are rather
 > confusing.  Section four mentions ZFC axioms without explaining what the
 > acronym expands to and without much pretext.  It's odd that it jumps
 > into talking about proving mathematics without explaining what it is
 > talking about.
 >
 >
 > Zev
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The most difficult section I found in the reading was 3.5 Functions
(page 11).  The various terms and their definitions are rather
confusing.  Section four mentions ZFC axioms without explaining what the
acronym expands to and without much pretext.  It's odd that it jumps
into talking about proving mathematics without explaining what it is
talking about.


Zev
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From meyer@imap.theory.csail.mit.edu  Fri Sep 16 00:20:43 2005
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did wed lecture and problems help you sort this out?  If not, go to
TA's office hours and ask for more explanation.

regards, A.

Anton Katz wrote:
> Page 6,
> 
> 2.4 = order of Quantifiers.
> 
>  
> 
> Seems pretty clear but had trouble with the last question in the tutor.
> 
>  
> 
> When you write:
> 
> ’¢Ï//x//’¢Ð//y// //Q//(//x//, //y//) ’¢ª ’¢Ð//y//’¢Ï//x// //Q//(//x//, //y//)
> 
>  
> 
> How are the different components connected amongst each other? (and, or’¡Ä)
> 
>  
> 
>  
> 


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Page 6,

2.4 = order of Quantifiers.



Seems pretty clear but had trouble with the last question in the tutor.



When you write:

¢Ïx¢Ðy Q(x, y) ¢ª ¢Ðy¢Ïx Q(x, y)



How are the different components connected amongst each other? (and, or¡Ä)





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Page 6,

2.4 = order of Quantifiers.



Seems pretty clear but had trouble with the last question in the tutor.



When you write:

¢Ïx¢Ðy Q(x, y) ¢ª ¢Ðy¢Ïx Q(x, y)



How are the different components connected amongst each other? (and, or¡Ä)






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<p class=3DMsoNormal><font size=3D2 face=3DArial><span =
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font-family:Arial'>Page 6,<o:p></o:p></span></font></p>

<p class=3DMsoNormal><font size=3D2 face=3DArial><span =
style=3D'font-size:10.0pt;
font-family:Arial'>2.4 =3D order of =
Quantifiers.<o:p></o:p></span></font></p>

<p class=3DMsoNormal><font size=3D2 face=3DArial><span =
style=3D'font-size:10.0pt;
font-family:Arial'><o:p>&nbsp;</o:p></span></font></p>

<p class=3DMsoNormal><font size=3D2 face=3DArial><span =
style=3D'font-size:10.0pt;
font-family:Arial'>Seems pretty clear but had trouble with the last =
question in
the tutor.<o:p></o:p></span></font></p>

<p class=3DMsoNormal><font size=3D2 face=3DArial><span =
style=3D'font-size:10.0pt;
font-family:Arial'><o:p>&nbsp;</o:p></span></font></p>

<p class=3DMsoNormal><font size=3D2 face=3DArial><span =
style=3D'font-size:10.0pt;
font-family:Arial'>When you write:<o:p></o:p></span></font></p>

<p class=3DMsoNormal><font size=3D3 color=3Dblack face=3D"MS =
Gothic"><span
style=3D'font-size:12.0pt;font-family:"MS =
Gothic";color:black'>=1B$B"O=1B(J</span></font><em><i><font
color=3Dblack face=3DArial><span =
style=3D'font-family:Arial;color:black'>x</span></font></i></em><font
color=3Dblack face=3D"MS Gothic"><span style=3D'font-family:"MS =
Gothic";color:black'>=1B$B"P=1B(J</span></font><em><i><font
color=3Dblack face=3DArial><span =
style=3D'font-family:Arial;color:black'>y</span></font></i></em><font
color=3Dblack face=3DArial><span =
style=3D'font-family:Arial;color:black'> <em><i><font
face=3DArial><span =
style=3D'font-family:Arial'>Q</span></font></i></em>(<em><i><font
face=3DArial><span style=3D'font-family:Arial'>x</span></font></i></em>, =
<em><i><font
face=3DArial><span style=3D'font-family:Arial'>y</span></font></i></em>) =
=1B$B"*=1B(J </span></font><font
color=3Dblack face=3D"MS Gothic"><span style=3D'font-family:"MS =
Gothic";color:black'>=1B$B"P=1B(J</span></font><em><i><font
color=3Dblack face=3DArial><span =
style=3D'font-family:Arial;color:black'>y</span></font></i></em><font
color=3Dblack face=3D"MS Gothic"><span style=3D'font-family:"MS =
Gothic";color:black'>=1B$B"O=1B(J</span></font><em><i><font
color=3Dblack face=3DArial><span =
style=3D'font-family:Arial;color:black'>x</span></font></i></em><font
color=3Dblack face=3DArial><span =
style=3D'font-family:Arial;color:black'> <em><i><font
face=3DArial><span =
style=3D'font-family:Arial'>Q</span></font></i></em>(<em><i><font
face=3DArial><span style=3D'font-family:Arial'>x</span></font></i></em>, =
<em><i><font
face=3DArial><span =
style=3D'font-family:Arial'>y</span></font></i></em>)<o:p></o:p></span></=
font></p>

<p class=3DMsoNormal><font size=3D3 color=3Dblack face=3DArial><span =
style=3D'font-size:
12.0pt;font-family:Arial;color:black'><o:p>&nbsp;</o:p></span></font></p>=


<p class=3DMsoNormal><font size=3D3 color=3Dblack face=3DArial><span =
style=3D'font-size:
12.0pt;font-family:Arial;color:black'>How are the different components
connected amongst each other? (and, =
or=1B$B!D=1B(J)<o:p></o:p></span></font></p>

<p class=3DMsoNormal><font size=3D3 color=3Dblack face=3DArial><span =
style=3D'font-size:
12.0pt;font-family:Arial;color:black'><o:p>&nbsp;</o:p></span></font></p>=


<p class=3DMsoNormal><font size=3D2 face=3DArial><span =
style=3D'font-size:10.0pt;
font-family:Arial'><o:p>&nbsp;</o:p></span></font></p>

</div>

</body>

</html>

------=_NextPart_000_0090_01C5B90A.FA2AD610--


From meyer@imap.theory.csail.mit.edu  Fri Sep 16 00:22:23 2005
BCC: 6042-staff@theory.csail.mit.edu
Message-ID: <432A4888.3090706@csail.mit.edu>
Date: Fri, 16 Sep 2005 00:22:32 -0400
From: "Prof. Albert R. Meyer" <meyer@csail.mit.edu>
Reply-To: 6042-meyer <6042-meyer@theory.csail.mit.edu>
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did wed lecture and problems help you sort this out?  If not, go to
TA's office hours and ask for more explanation.

regards, A.

Zachary Adam Ozer wrote:
> My confusion arises from the order of quantifiers section (2.4) of
> week 2 course notes. On page 6, the statement "Swapping quantifiers in
> Goldbach's Conjecture creates a patently false statement." I suppose
> that I don't understand why the statement which follows is indeed
> patently false. Indeed, in English one could say either "I will stand
> up every time I hear the bell" or "Every time I hear a bell I will
> stand up." The statements are equivalent, why not so in math?
> 
> -zozer
> 


From meyer@imap.theory.csail.mit.edu  Wed Sep 14 21:47:33 2005
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My confusion arises from the order of quantifiers section (2.4) of
week 2 course notes. On page 6, the statement "Swapping quantifiers in
Goldbach's Conjecture creates a patently false statement." I suppose
that I don't understand why the statement which follows is indeed
patently false. Indeed, in English one could say either "I will stand
up every time I hear the bell" or "Every time I hear a bell I will
stand up." The statements are equivalent, why not so in math?

-zozer


From meyer@imap.theory.csail.mit.edu  Fri Sep 16 00:26:31 2005
BCC: 6042-staff@theory.csail.mit.edu
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Date: Fri, 16 Sep 2005 00:26:41 -0400
From: "Prof. Albert R. Meyer" <meyer@csail.mit.edu>
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To: Knight W Fu <knightfu@MIT.EDU>
Subject: Re: Required Reading Comment
References: <20050914045543.6yddpubg7w0soo40@webmail.mit.edu>
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the "C" in ZFC stands for Zermelo-Frankel with "C"hoice.  It's not 
really controversial -- virtually all mathematicians accept it an axiom; 
what was a surprise is that Choice does not follow from ZF; it really 
has to be added as an extra axiom.

Regards, A.

Knight W Fu wrote:
> The ZFC Axioms
> For the record, we list the axioms of Zermelo-Frankel Set Theory.
> Essentially all of mathematics can be derived from these axioms together
> with a few logical deduction rules.
> Extensionality. Two sets are equal if they have the same members. In
> formal logical notation, this would be stated as:
> (8z. (z 2 x  ! z 2 y)) ?! x = y.
> Pairing. For any two sets x and y, there is a set, {x, y}, with x and y as
> its only elements.
> Union. The union of a collection, z, of sets is also a set.
> 9u8x. (9y. x 2 y ^ y 2 z)  ! x 2 u.
> Infinity. There is an infinite set; specifically, a nonempty set, x, such
> that for any set y 2 x, the set {y} is also a member of x
> Subset. Given any set, x, and any proposition P(y), there is a set containing
> precisely those elements y 2 x for which P(y) holds.
> Power Set. All the subsets of a set form another set.
> Replacement. The image of a set under a function is a set.
> Foundation. For every non-empty set, x, there is a set y 2 x such that
> x and y are disjoint. (In particular, this axiom prevents a set from
> being a member of itself.)
> Choice. We can choose one element from each set in a collection of
> nonempty sets. More precisely, if f is a function on a set, and
> the result of applying f to any element in the set is always
> a nonempty set, then there is a ?choice? function g such that
> g(y) 2 y for every y in the set.
> We?re not going to be working with the ZFC axioms in this course. We
> just thought you might like to see them.
> 
> - The above passage was quoted from page 5
> 
> I had read a few books that mention the axioms of set theory, and I have
> actually not seen the ZFC Axioms so completely listed. I have studied the
> axioms of choice in a topology class, and I was told that it was very
> controversial in the math world. I never thought that it was one of the ZFC
> axioms.


From meyer@imap.theory.csail.mit.edu  Wed Sep 14 21:47:32 2005
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X-Keywords: NonJunk NotJunk                                                                                            


The ZFC Axioms
For the record, we list the axioms of Zermelo-Frankel Set Theory.
Essentially all of mathematics can be derived from these axioms together
with a few logical deduction rules.
Extensionality. Two sets are equal if they have the same members. In
formal logical notation, this would be stated as:
(8z. (z 2 x  ! z 2 y)) ?! x = y.
Pairing. For any two sets x and y, there is a set, {x, y}, with x and y as
its only elements.
Union. The union of a collection, z, of sets is also a set.
9u8x. (9y. x 2 y ^ y 2 z)  ! x 2 u.
Infinity. There is an infinite set; specifically, a nonempty set, x, such
that for any set y 2 x, the set {y} is also a member of x
Subset. Given any set, x, and any proposition P(y), there is a set containing
precisely those elements y 2 x for which P(y) holds.
Power Set. All the subsets of a set form another set.
Replacement. The image of a set under a function is a set.
Foundation. For every non-empty set, x, there is a set y 2 x such that
x and y are disjoint. (In particular, this axiom prevents a set from
being a member of itself.)
Choice. We can choose one element from each set in a collection of
nonempty sets. More precisely, if f is a function on a set, and
the result of applying f to any element in the set is always
a nonempty set, then there is a ?choice? function g such that
g(y) 2 y for every y in the set.
We?re not going to be working with the ZFC axioms in this course. We
just thought you might like to see them.

- The above passage was quoted from page 5

I had read a few books that mention the axioms of set theory, and I have
actually not seen the ZFC Axioms so completely listed. I have studied the
axioms of choice in a topology class, and I was told that it was very
controversial in the math world. I never thought that it was one of the ZFC
axioms.

From meyer@imap.theory.csail.mit.edu  Fri Sep 16 00:38:35 2005
BCC: 6042-staff@theory.csail.mit.edu
Message-ID: <432A4C53.7060001@csail.mit.edu>
Date: Fri, 16 Sep 2005 00:38:43 -0400
From: "Prof. Albert R. Meyer" <meyer@csail.mit.edu>
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To: Irene Zhang <iyzhang@MIT.EDU>
Subject: Re: question about pset
References: <E1EFxgj-0000JR-7c@icampustutor.csail.mit.edu> <432A47E1.5050909@mit.edu>
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the domain of f is A, and the codomain of f is the powerset of A.  So 
what we know is that for each x in A, the value f(x) is a subset of A. 
(Technically, f(x) also might be undefined for certain x, since it's 
possible that f is not total.  But it's ok to assume that f is total in 
this problem if that makes things clearer.)

regards, A.

Irene Zhang wrote:
> In problem 4, could you explain the {x \in A | x \notin f(x)}? Would the 
> f(x) be the range of the function? or the codomain?
> 
> Thanks,
> Irene


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X-Keywords: NotJunk                                                                                            

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Ah.  I didn't see the lecture notes links on the calendar because I
followed the week two lecture notes from the tutor and was confused when
the week 1 tutor problem set linked to the week 2 lecture notes.  Now
that I found them, I'll review them.  Thanks!


Zev

Prof. Albert R. Meyer wrote:
> ZFC was introduced in Week 1 Notes, pp.4--5.  Did you read them?
> 
> Regards, A.
> 
> Zev Benjamin wrote:
> The most difficult section I found in the reading was 3.5 Functions
> (page 11).  The various terms and their definitions are rather
> confusing.  Section four mentions ZFC axioms without explaining what the
> acronym expands to and without much pretext.  It's odd that it jumps
> into talking about proving mathematics without explaining what it is
> talking about.
> 
> 
> Zev
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From meyer@imap.theory.csail.mit.edu  Fri Sep 16 01:30:48 2005
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Absolutely. I now understand why the statements are not equivalent.
Thanks again for your help.

-zozer

On 9/16/05, Prof. Albert R. Meyer <meyer@csail.mit.edu> wrote:
> did wed lecture and problems help you sort this out?  If not, go to
> TA's office hours and ask for more explanation.
> 
> regards, A.
> 
> Zachary Adam Ozer wrote:
> > My confusion arises from the order of quantifiers section (2.4) of
> > week 2 course notes. On page 6, the statement "Swapping quantifiers in
> > Goldbach's Conjecture creates a patently false statement." I suppose
> > that I don't understand why the statement which follows is indeed
> > patently false. Indeed, in English one could say either "I will stand
> > up every time I hear the bell" or "Every time I hear a bell I will
> > stand up." The statements are equivalent, why not so in math?
> >
> > -zozer
> >
>

From meyer@imap.theory.csail.mit.edu  Fri Sep 16 12:04:51 2005
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The kind of email reply I hope for.
regards, A.

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Date: Fri, 16 Sep 2005 01:30:42 -0400
From: Zachary Adam Ozer <zozer@mit.edu>
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Absolutely. I now understand why the statements are not equivalent.
Thanks again for your help.

-zozer

On 9/16/05, Prof. Albert R. Meyer <meyer@csail.mit.edu> wrote:
> did wed lecture and problems help you sort this out?  If not, go to
> TA's office hours and ask for more explanation.
> 
> regards, A.
> 
> Zachary Adam Ozer wrote:
> > My confusion arises from the order of quantifiers section (2.4) of
> > week 2 course notes. On page 6, the statement "Swapping quantifiers in
> > Goldbach's Conjecture creates a patently false statement." I suppose
> > that I don't understand why the statement which follows is indeed
> > patently false. Indeed, in English one could say either "I will stand
> > up every time I hear the bell" or "Every time I hear a bell I will
> > stand up." The statements are equivalent, why not so in math?
> >
> > -zozer
> >
>

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